When an object is put in front of a thin lens, if the focal length of a lens is known, one can predict where the image will be formed by using the thin lens equation: 1 1+1=1 P 9 f 1 F 1 where p is the object distance, q is the image distance, and fis the focal length. fis positive for a converging lens, and negative for a diverging lens. Refer to the figure below to answer the questions: A positive lens F A negative lens 1. If an object is located very far from a converging lens, i.e. p→ ∞o, where would its image be formed? 9= 2. If an object is located on the first focal point of a converging lens, i.e. p=f, where is its image formed? 9= Is the image on the same side or opposite side of the lens as the object?

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Course #
Section #
Pre-lab The Focal length of a lens
Read the manual 0-3 thoroughly.
When an object is put in front of a thin lens, if the focal length of a lens is known, one can predict where the
image will be formed by using the thin lens equation:
Name
1 1 1
p q f
where p is the object distance, q is the image distance, and fis the focal length. fis positive for a converging
lens, and negative for a diverging lens.
Refer to the figure below to answer the questions:
A positive lens
F
9=
A negative lens
-f
1. If an object is located very far from a converging lens, i.e. poo, where would its image be formed?
9=
2. If an object is located on the first focal point of a converging lens, i.e. p=f, where is its image formed?
9. =
Is the image on the same side or opposite side of the lens as the object?
3. If an object is located on the second focal point of a diverging lens, i.e. p = f, where is its image
formed?
Is the image on the same side or opposite side of the lens as the object?
Transcribed Image Text:Course # Section # Pre-lab The Focal length of a lens Read the manual 0-3 thoroughly. When an object is put in front of a thin lens, if the focal length of a lens is known, one can predict where the image will be formed by using the thin lens equation: Name 1 1 1 p q f where p is the object distance, q is the image distance, and fis the focal length. fis positive for a converging lens, and negative for a diverging lens. Refer to the figure below to answer the questions: A positive lens F 9= A negative lens -f 1. If an object is located very far from a converging lens, i.e. poo, where would its image be formed? 9= 2. If an object is located on the first focal point of a converging lens, i.e. p=f, where is its image formed? 9. = Is the image on the same side or opposite side of the lens as the object? 3. If an object is located on the second focal point of a diverging lens, i.e. p = f, where is its image formed? Is the image on the same side or opposite side of the lens as the object?
Course #
O
4. An object is 30 cm from a thin, positive lens. The focal length of the lens is 10 cm. Where will the
image be formed by this positive lens?
Section #
9 =
p=
Name
30 cm
← →
Is the image real of imaginary?
Mark the position of this image on the figure.
5. There is a negative lens to the right of the positive lens, at a distance of L= 10 cm away. What
is the distance between this negative lens and the image formed by the positive lens?
d =
6. The image formed by the positive lens is the object of the negative lens. Is the image formed by
the positive lens to the right or the left of the negative lens? In this case, is the object distance
positive or negative?
To the negative lens,
7. The focal length of the negative lens is also 10 cm (negative). Calculate where the image will
be formed by the negative lens.
q=
mark the position of this image on the figure. Is the image real or virtual?
For a diverging lens, the focal length is negative by definition. Thus in the thin lens equation, if the
object distance is positive, then the image distance will always be negative. How did we make the
diverging lens to form a real image?
Transcribed Image Text:Course # O 4. An object is 30 cm from a thin, positive lens. The focal length of the lens is 10 cm. Where will the image be formed by this positive lens? Section # 9 = p= Name 30 cm ← → Is the image real of imaginary? Mark the position of this image on the figure. 5. There is a negative lens to the right of the positive lens, at a distance of L= 10 cm away. What is the distance between this negative lens and the image formed by the positive lens? d = 6. The image formed by the positive lens is the object of the negative lens. Is the image formed by the positive lens to the right or the left of the negative lens? In this case, is the object distance positive or negative? To the negative lens, 7. The focal length of the negative lens is also 10 cm (negative). Calculate where the image will be formed by the negative lens. q= mark the position of this image on the figure. Is the image real or virtual? For a diverging lens, the focal length is negative by definition. Thus in the thin lens equation, if the object distance is positive, then the image distance will always be negative. How did we make the diverging lens to form a real image?
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