As shown in the figure above, a thin plano-convex lens is fabricated from glass with an index of refraction of 1.500. The radius of curvature of the convex surface is 25.0 cm. A real object is placed 20.0 cm in front of the lens which is surrounded by air. Find the position of the image produced, the lateral magnification, and completely describe the image.
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As shown in the figure above, a thin plano-convex lens is fabricated from glass with an index of refraction
of 1.500. The radius of curvature of the convex surface is 25.0 cm. A real object is placed 20.0 cm in front
of the lens which is surrounded by air. Find the position of the image produced, the lateral magnification,
and completely describe the image.
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- = A leaf of length his positioned d below. Leaf d 70.3 cm in front of a converging lens with a focal length of 34.0 cm. An observer views the image of the leaf from a position 1.26 m behind the lens, as shown in the figure 1.26 m (a) What is the magnitude of the lateral magnification (the ratio of image size to the object size) produced by the lens? (b) What angular magnification is achieved by viewing the image of the leaf rather than viewing the leaf directly?A biconcave lens has radii of curvature equal to R₁ = 31.0 cm and R₂ = 43.7 cm. A very distant object on the R₁ side of the lens forms an image. The lens medium has index of refraction 1.53 for violet light and 1.51 for red light. (a) Where is the image formed by violet light? (Enter your answer in cm and indicate the position of the image relative to the lens with the sign of your answer. Give your answer to at least two decimal places.) cm (b) Where is the image formed by red light? (Enter your answer in cm and indicate the position of the image relative to the lens with the sign of your answer. Give your answer to at least two decimal places.) cmTwo lenses are separated by 50 cm. Lens 1 is convex and has a radius of curvature of magnitude 30 cm. Lens 2 is concave and has a radius of curvature of magnitude 40 cm and is located to the right of Lens 1. An object is located 20 cm to left of lens 1. Find the location of the final image of the object. What is the magnification of the final image?
- A 3 cm tall object is placed 16 cm from a converging lens with a focal length of 12 cm. A diverging lens with a focal length of 10 cm is placed 36 cm behind the converging lens. Both lenses have the same principal axis. Draw the ray diagram to graphically find the final image. Need only handwritten solution only (not typed one).A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal length 7.80 cm. A diverging lens of focal length –16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position 7.5 cm in front of the second lens v 0.5466 height Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm Is the image inverted or upright? upright O inverted Is the image real or virtual? real virtualThe distance between the eyepiece and the objective lens in a certain compound microscope is 10.4 cm. The focal length of the objective is 0.430 cm, and that of the eyepiece is 1.40 cm. Find the overall magnification of the microscope. (The near point of the eye is 25 cm. Assume that the object is placed at the focal point of the objective lens, and one places the eyepiece at the near point of the eye.)
- The lens-maker’s equation for a lens with index n1 immersed in a medium with index n2 takes the form A thin diverging glass (index = 1.50) lens with R1 = −3.00 m and R2 = −6.00 m is surrounded by air. An arrow is placed 10.0 m to the left of the lens. (a) Determine the position of the image. Repeat part (a) with the arrow and lens immersed in (b) water (index = 1.33) (c) a medium with an index of refraction of 2.00. (d) How can a lens that is diverging in air be changed into a converging lens?A thin lens is comprised of two spherical surfaces with radii of curvatures of 32.4 cm for the front side and -26.9 cm for the back side. The material of which the lens is compose has an index of refraction of 1.49. What is the magnification of the image formed by an object placed 43.7cm from the lens?A man standing 1.54 m in front of a shaving mirror produces an inverted image 18.6 cm in front of it. How close to the mirror should he stand if he wants to form an upright image of his chin that is twice the chin's actual size? cm A contact lens is made of plastic with an index of refraction of 1.40. The lens has an outer radius of curvature of +1.92 cm and an inner radius of curvature of +2.47 cm. What is the focal length of the lens? cm