DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Textbook Question
Chapter 23, Problem 5RQ
Which operations shown in Figure 23.3 do not form a chip?
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1.) The rake angle in an orthogonal cutting operation is -5.736°. The chip thickness before the cut is 0.249 mm, and the resulting chip thickness after the cut is 0.762 mm. The chip thickness ratio is _
2.) The rake angle in an orthogonal cutting operation is 17.995°. The chip thickness before the cut is 0.254 mm, and the resulting chip thickness after the cut is 0.595 mm. The shear plane angle is _ degrees.
3.) The rake angle in an orthogonal cutting operation is -2.804°. The chip thickness before the cut is 0.204 mm, and the resulting chip thickness after the cut is 0.556 mm. The shear strain is _.
4.) Microscopic examination of chips obtained from actual machining operations have revealed that they are produced by _.
5.) Low-carbon steel with 300 MPa tensile strength and 220 MPa shear strength is turned at 2.5 m/s cutting speed on a lathe. Feed (cutting width) is 0.20 mm/rev and depth of cut is 3.0 mm. Rake angle is 5°. The resulting chip ratio = 0.45. The cutting force is _ N…
operation, the shear
IS cIose to,
In turning operation, spindle speed is set to provide a cutting speed of 2.2 m/:
The feed and depth of cut are 0.32 mm and 2.1 mm, respectively. The tool
rake angle is 15°. After the cut, the deformed chip thickness is measured to be
0.43 mm. Using the Orthogonal model as an approximation of turning
operation, the shear strain is close to,
In turning operation, spindle speed is set to provide a cutting speed of 2.4 m/
In a turning process using orthogonal tool geometry, a chip length of 100 mm is
obtained for an uncut chip length of 250 mm. The cutting conditions are cutting speed
30 m/min, rake angle = 20°º.
The shear plane angle is degrees (round off to one decimal place).
=
Chapter 23 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 23 - How is the tool-work relationship in turning...Ch. 23 - What different kinds of surfaces can be produced...Ch. 23 - How does form turning differ from ordinary...Ch. 23 - What is the basic difference between facing and a...Ch. 23 - Which operations shown in Figure 23.3 do not form...Ch. 23 - Why is it difficult to make heavy cuts if a form...Ch. 23 - Show how equation 23.6 is an approximate equation.Ch. 23 - Why is the spindle of the lathe hollow?Ch. 23 - What function does a lathe carriage have?Ch. 23 - Why is feed specified for a boring operation...
Ch. 23 - Why are depths of cut in boring usually smaller...Ch. 23 - How can work be held and supported in a lathe?Ch. 23 - How is a workpiece that is mounted between centers...Ch. 23 - What will happen to the workpiece when turned, if...Ch. 23 - Why is it not advisable to hold hot-rolled steel...Ch. 23 - How does a steady rest differ from a follow rest?Ch. 23 - What are the advantages and disadvantages of a...Ch. 23 - Why should the distance the cutting tool overhangs...Ch. 23 - Prob. 19RQCh. 23 - How can a tapered part be turned on a lathe?Ch. 23 - Why might it be desirable to use a heavy depth of...Ch. 23 - If the rpm for a facing cut (assuming given work...Ch. 23 - Why is it usually necessary to take relatively...Ch. 23 - How does the corner radius of the tool influence...Ch. 23 - What effect does a BUE have on the diameter of the...Ch. 23 - How does the multiple-spindle screw machine differ...Ch. 23 - Why does boring ensure concentricity between the...Ch. 23 - Why are vertical spindle machines better suited...Ch. 23 - Prob. 29RQCh. 23 - Prob. 30RQCh. 23 - In which figures in this chapter is a dead center...Ch. 23 - Prob. 32RQCh. 23 - In which figures in this chapter showing setups do...Ch. 23 - How many form tools are being utilized in the...Ch. 23 - Prob. 35RQCh. 23 - Select the speed, feed, and depth of cut for...Ch. 23 - Calculate the rpm NS to run the spindle on a lathe...Ch. 23 - The lathe in problem 2 has rpm settings of 20, 30,...Ch. 23 - Calculate the cutting time if the length of cut is...Ch. 23 - Calculate the metal removal rate for machining at...Ch. 23 - Determine the speed, feed, and depth of cut when...Ch. 23 - At a speed of 90 fpm, feed of 0.030 ipr, and depth...Ch. 23 - Calculate the cutting time for a 4-in. length of...Ch. 23 - For a boring operation at V=90,fr=0.030, and...Ch. 23 - A cutting speed of 100 sfpm has been selected for...Ch. 23 - The following data apply for machining a part on a...Ch. 23 - A finish cut for a length of 10 in. on a diameter...Ch. 23 - A workpiece 10 in. in diameter is to be faced down...Ch. 23 - A hole 89 mm in diameter is to be drilled and...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- What is chip load?arrow_forward1. List the operations and the tools needed to make the following shape.2. Find the speed of rotation (RPM N) of each tool during roughing andfinishing.The material of the piece is Stainless Steel (C45) with CARBIDE TOOL.arrow_forwardQ1:- Put a mark of True or false for below:- (a):- The milling cutting tool has a single cutting edge? (b):- At the break-even point, the total revenue equals the total cost? (c):- The right-hand rule is used to define machine axes? (d):- Design error is a simple mistake? (e):- The quality of products is poor in mass production? (f):- Allowances must be left before turning? (g):- Up-ward milling is better than down-ward milling?arrow_forward
- It is required to cut screw threads of 2 mm pitch on a lathe. The lead screw has a pitch of 6 mm. If the spindle speed is 60 rpm, then the speed of the lead screw will bearrow_forward4. For the drawing below answer the following: A. The name of the device? B. Its function? C. The parts name? D. How does it work? E. What are the operation parameters? Explain with the help of sketches? F. How is the machine speed changed? 3.arrow_forwardPlease solve in 20 minutesarrow_forward
- Problem 2. Turning Consider Step 2 (Turn Shoulder) in machining the flashlight handle (Figure 2). STEP 1: CUT TO LENGTH STEP 2: TURN SHOULDER 0.600 1.0" 3.000 -0.440 Figure 2. Turning step for Problem 2. i) Calculate the (1) cutting time (in s), (2) the material removal rate (in in3 /s or mm3/s) for this cut, assuming you remove all of the material with one pass (i.e., depth of cut d = (1"-0.6")/2 = 0.2"), and (3) the power (hp or W) required for this turning operation: Consider the following scenarios: Feed (f) in/rev Rotational Speed Cutting Time MRR Power (n) in RPM 0.02 1000 ? ? ? 0.025 900 ? ? ? 0.03 800 ? ? ? 1 j) What changes could you make to the process if you needed to decrease the power requirement?arrow_forwardPlease don't provide handwritten solution...arrow_forwardWhat is the cutting speed of turning in the unit of m/min, when main axis spindle speed is 2,409 rpm and external diameter is 86mm ? Answer in 2 decimal points. Calculate the theoretical spindle rotational speed in rpm required to drill a 1 mm hole in copper using high speed steel drill. The recommende cutting speed is as following. The thickness of the copper plate is 24. (Leave the answer in numerical value, no need to key in 'rpm') Typical cutting speeds (m/min) High speed steel Material Tungsten carbide Aluminum 100 500 60 330 Copper Hard brass 45 230 Bronze 35 180 Mild steel 28 250 Cast iron 20 160arrow_forward
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