DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Textbook Question
Chapter 23, Problem 28RQ
Why are vertical spindle machines better suited for machining large workpieces than horizontal lathes?
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In the lathe machine, the diameter of workpart 35mm is turned at 100 rpm,
depth of cut 0.125 mm, length of continuous chip for one revolution of
workpart = 60mm, length undeformed chip= 100.53mm, rake angle = 35°,
coefficient of friction= 1.5 and resultant cutting force=215.5 N.
Calculate:
1- Horizontal cutting force of the tool on the workpart and vertical cutting force
required to hold the tool against the work.
2- The forces components applied against the chip by the tool.
3- Velocity of chip relative to the tool and workpart.
4- The percentage of total energy dissipated due to friction along the shear plane,
and the friction at the tool-chip interface.
Consider a profile milling operation, where the
initial (stock) geometry has (X,Y,Z) dimensions of
100 mm x 75 mm x 50 mm. The target part has
dimensions of 95 mm x 70 mm x 50 mm. The
target part is located in the centre of the stock
part, i.e. the stock to be removed from all sides is
equal. The operation has a cutting time of 1
minute. The tool axis is along the Z direction and
the tool diameter is 12 mm having 6 cutting
edges. The takes place at 54m/min
feed rate of 0.2 mm/rev/tooth.
Calculate the axial depth of cut ?
process
at a
please answer with detail explanation.
Chapter 23 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 23 - How is the tool-work relationship in turning...Ch. 23 - What different kinds of surfaces can be produced...Ch. 23 - How does form turning differ from ordinary...Ch. 23 - What is the basic difference between facing and a...Ch. 23 - Which operations shown in Figure 23.3 do not form...Ch. 23 - Why is it difficult to make heavy cuts if a form...Ch. 23 - Show how equation 23.6 is an approximate equation.Ch. 23 - Why is the spindle of the lathe hollow?Ch. 23 - What function does a lathe carriage have?Ch. 23 - Why is feed specified for a boring operation...
Ch. 23 - Why are depths of cut in boring usually smaller...Ch. 23 - How can work be held and supported in a lathe?Ch. 23 - How is a workpiece that is mounted between centers...Ch. 23 - What will happen to the workpiece when turned, if...Ch. 23 - Why is it not advisable to hold hot-rolled steel...Ch. 23 - How does a steady rest differ from a follow rest?Ch. 23 - What are the advantages and disadvantages of a...Ch. 23 - Why should the distance the cutting tool overhangs...Ch. 23 - Prob. 19RQCh. 23 - How can a tapered part be turned on a lathe?Ch. 23 - Why might it be desirable to use a heavy depth of...Ch. 23 - If the rpm for a facing cut (assuming given work...Ch. 23 - Why is it usually necessary to take relatively...Ch. 23 - How does the corner radius of the tool influence...Ch. 23 - What effect does a BUE have on the diameter of the...Ch. 23 - How does the multiple-spindle screw machine differ...Ch. 23 - Why does boring ensure concentricity between the...Ch. 23 - Why are vertical spindle machines better suited...Ch. 23 - Prob. 29RQCh. 23 - Prob. 30RQCh. 23 - In which figures in this chapter is a dead center...Ch. 23 - Prob. 32RQCh. 23 - In which figures in this chapter showing setups do...Ch. 23 - How many form tools are being utilized in the...Ch. 23 - Prob. 35RQCh. 23 - Select the speed, feed, and depth of cut for...Ch. 23 - Calculate the rpm NS to run the spindle on a lathe...Ch. 23 - The lathe in problem 2 has rpm settings of 20, 30,...Ch. 23 - Calculate the cutting time if the length of cut is...Ch. 23 - Calculate the metal removal rate for machining at...Ch. 23 - Determine the speed, feed, and depth of cut when...Ch. 23 - At a speed of 90 fpm, feed of 0.030 ipr, and depth...Ch. 23 - Calculate the cutting time for a 4-in. length of...Ch. 23 - For a boring operation at V=90,fr=0.030, and...Ch. 23 - A cutting speed of 100 sfpm has been selected for...Ch. 23 - The following data apply for machining a part on a...Ch. 23 - A finish cut for a length of 10 in. on a diameter...Ch. 23 - A workpiece 10 in. in diameter is to be faced down...Ch. 23 - A hole 89 mm in diameter is to be drilled and...
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- The end of a large tubular workpart is to be faced on a NC vertical boring mill. The part has an outside diameter of 38.0 in and an inside diameter of 24.0 in. If the facing operation is performed at a rotational speed of 40.0 rev/min, feed of 0.015 in/rev, and depth of cut of 0.180 in, determine (a) the cutting time to complete the facing operation and the cutting speeds and metal removal rates at the beginning and end of the cut.arrow_forwardi need the answer quicklyarrow_forwardIn a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed=9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution)arrow_forward
- Please answer all partsarrow_forwardThe following data is given for slab milling of a 300 mm long 50 mm wide mild steel block: Cutter of diameter= 60 mm; Numbers of teeth =12; Cutter speed = 120 rev/min; Depth of cut = 3.2 mm; Feed is 0.25 mm/tooth.Determine (i) Table feed in mm/min, (ii) MRR (iii) Power (iv) Torque and (v) Total machining time. Assumesuitable approach and over-run and specific energy of mild steel as 5 Ws/mm3.arrow_forwardhand write asap ( i'll give you multiple upvotearrow_forward
- Determine the total machining time for a workpiece 30mm in diameter and the required length is 145 mm. Other data: Material: 38mm dia. X 149 mm Depth of cut (turning): 4mm Depth of cut (facing): 2mm Feed : 0.05 mm/rev : 35 SMPM Cutting speedarrow_forwardIn a turning operation on low carbon steel with hardness = 135 HB, the cutting speed = 180 m/min, feed = 0.35 mm/rev, and depth of cut = 6.5 mm. The original work piece has 26 mm Diameter and 120 mm Length. How much power will the lathe draw in performing this operation if its mechanical efficiency = 90% and operator's efficiency = 82%? The specific energy is 3.8 J/mm³arrow_forwardNonearrow_forward
- Rake angle=20 degree, Depth of cut=6 mm, Feed rate =0.25mm/rev,Cutting speed=0.6 m/s, chip length before cutting=29.4mm, vertical cutting force= 1050 NHorizontal cutting force=630, chip length after cutting=12.9Using Merchant’s analysis calculate(a) direction and magnitude of resultant force(b) friction force and friction angle(c) shear plane anglearrow_forwardFor the operation of straight turning in a lathe machine, the diameter of the workpiece is 80 mm, the length is 0.12 m, the cutting speed is 80 m / min, the feed is 0.5 mm / rev and the depth of cut is 0.002 m . Find the material removing rate and the time of machining.arrow_forwardTurning Operation In a production turning operation, the foreman has decreed that a single pass must be completed on the cylindrical workpiece in 4.8 min. The piece is 400 mm long and 150 mm in diameter. Using a feed = 0.43 mm/rev and a depth of cut = 4.0 mm, what cutting speed must be used to meet this machining time requirement? Hint: Re-arrange the Tm equation to find v in m/min Tm= T.DO.L v.f 1.522arrow_forward
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