Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Textbook Question
Chapter 23, Problem 34RQ
How many form tools are being utilized in the process shown in Figure 23.14 to machine the part?
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In a production turning operation, the workpart is 60 mm in diameter and 500 mm
long. A feed of 0.75 mm/rev is used in the operation. If cutting speed-9 m/s, the tool
must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used
to produce 50 pieces between tool changes. Determine the Taylor tool life equation for
this job. (use the equations given below for solution)
L
Tm- 1,= Nf
N
AD, vT" = C
%3|
AD,L
Tm
fv
A job has to be machined in shaping and the process parameters are given below:
Length of the job=120 mm
Speed of the motor=640 rpm
Cutting speed=248 m/min
Tool allowance before cutting =31.5 mm
Tool allowance after cutting=10 mm
Determine the cutting to return stroke ratio for the above operation and draw the arrangement of machining with tool head and allowances.
In a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed=9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution)
Chapter 23 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 23 - How is the tool-work relationship in turning...Ch. 23 - What different kinds of surfaces can be produced...Ch. 23 - How does form turning differ from ordinary...Ch. 23 - What is the basic difference between facing and a...Ch. 23 - Which operations shown in Figure 23.3 do not form...Ch. 23 - Why is it difficult to make heavy cuts if a form...Ch. 23 - Show how equation 23.6 is an approximate equation.Ch. 23 - Why is the spindle of the lathe hollow?Ch. 23 - What function does a lathe carriage have?Ch. 23 - Why is feed specified for a boring operation...
Ch. 23 - Why are depths of cut in boring usually smaller...Ch. 23 - How can work be held and supported in a lathe?Ch. 23 - How is a workpiece that is mounted between centers...Ch. 23 - What will happen to the workpiece when turned, if...Ch. 23 - Why is it not advisable to hold hot-rolled steel...Ch. 23 - How does a steady rest differ from a follow rest?Ch. 23 - What are the advantages and disadvantages of a...Ch. 23 - Why should the distance the cutting tool overhangs...Ch. 23 - Prob. 19RQCh. 23 - How can a tapered part be turned on a lathe?Ch. 23 - Why might it be desirable to use a heavy depth of...Ch. 23 - If the rpm for a facing cut (assuming given work...Ch. 23 - Why is it usually necessary to take relatively...Ch. 23 - How does the corner radius of the tool influence...Ch. 23 - What effect does a BUE have on the diameter of the...Ch. 23 - How does the multiple-spindle screw machine differ...Ch. 23 - Why does boring ensure concentricity between the...Ch. 23 - Why are vertical spindle machines better suited...Ch. 23 - Prob. 29RQCh. 23 - Prob. 30RQCh. 23 - In which figures in this chapter is a dead center...Ch. 23 - Prob. 32RQCh. 23 - In which figures in this chapter showing setups do...Ch. 23 - How many form tools are being utilized in the...Ch. 23 - Prob. 35RQCh. 23 - Select the speed, feed, and depth of cut for...Ch. 23 - Calculate the rpm NS to run the spindle on a lathe...Ch. 23 - The lathe in problem 2 has rpm settings of 20, 30,...Ch. 23 - Calculate the cutting time if the length of cut is...Ch. 23 - Calculate the metal removal rate for machining at...Ch. 23 - Determine the speed, feed, and depth of cut when...Ch. 23 - At a speed of 90 fpm, feed of 0.030 ipr, and depth...Ch. 23 - Calculate the cutting time for a 4-in. length of...Ch. 23 - For a boring operation at V=90,fr=0.030, and...Ch. 23 - A cutting speed of 100 sfpm has been selected for...Ch. 23 - The following data apply for machining a part on a...Ch. 23 - A finish cut for a length of 10 in. on a diameter...Ch. 23 - A workpiece 10 in. in diameter is to be faced down...Ch. 23 - A hole 89 mm in diameter is to be drilled and...
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- 8 A job has to be machined in shaping and the process parameters are given below: a. Length of the job=120 mm b. Speed of the motor=640 rpm c. Cutting speed=264 m/min d. Tool allowance before cutting =30 mm e. Tool allowance after cutting=15mm Determine the cutting to return stroke ratio for the above operation and draw the arrangement of machining with tool head and allowances.arrow_forwardWhat is the working principle of shaper machine?arrow_forward12. A 600 mm × 30 mm flat surface of a plate is to be finish machined on a shaper. The plate has been fixed with the 600 mm side along the tool travel direction. If the tool over-travel at each end of the plate is 20 mm, average cutting speed is 8 m/min, feed rate is 0.3 mm/stroke and the ratio of return time to cutting time of the tool is 1:2, the time required for machining will be (a) 8 minutes (b) 12 minutes (c) 16 minutes (d) 20 minutesarrow_forward
- Question 3. a. A cast iron component for motorcycle is to be turned with machine settings of feed = 0.22 mm/rev, and speed = 100 m/min. The cutting tool is a carbide tip with a nose radius of 1.2 mm and the rai for the material at a cutting speed of 100 m/min is 1.3. Calculate the surface roughness for this cut. [6 marks]arrow_forwardA NC lathe cuts two passes across a cylindrical workpiece under automatic cycle. The operator loads and unloads the machine. The starting diameter of the work is 3.00 in and its length = 10 in. The work cycle consists of the following steps (with element times given in parentheses where applicable): 1 - Operator loads part into machine, starts cycle (1.00 min); 2 - NC lathe positions tool for first pass (0.10 min); 3 - NC lathe turns first pass (time depends on cutting speed); 4 - NC lathe repositions tool for second pass (0.4 min); 5 - NC lathe turns second pass (time depends on cutting speed); and 6 - Operator unloads part and places in tote pan (1.00 min). In addition, the cutting tool must be periodically changed. This tool change time takes 1.00 min. The feed rate = 0.007 in/rev and the depth of cut for each pass = 0.100 in. The cost of the operator and machine = $39/hr and the tool cost = $2.00/cutting edge. The applicable Taylor tool life equation has parameters: n = 0.26 and…arrow_forwardquick and right answer will get an upvote A total of 6000 product must be produced in next 3 days on a CNC machine. The cycle time is40 sec and the setup time for the job is 2 hrs. Calculate the starting number of units if thescrape rate is 5%. Also find the number of machines required to produce this quantity if theplant operate 7 hours a day and 5 days a week.?arrow_forward
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