(a)
Interpretation:
The reason for –NHCOR group of amide being activating group is to be explained.
Concept introduction:
An activating group is the group, which activates the benzene ring toward electrophilic
(b)
Interpretation:
It is to be explained why the –NHCOR group of an amide is an activating group, but it is not as strongly activating as
Concept introduction:
An activating group is the group, which activates the benzene ring toward electrophilic
aromatic substitution. In general, ortho/para directors increase the rate of electrophilic aromatic substitution and are called activating groups. A substituent attached to a phenyl ring by an atom possessing a lone pair of electrons tends to be an ortho/para director. Activating groups stabilize the arenium ion intermediate by participation of lone pair on the atom of substituent in resonance.

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Chapter 23 Solutions
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
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- For a CARS experiment on a Raman band 918 cm-1, if omega1= 1280 nm, calculate the omega2 in wavelength (nm) and the CARS output in wavelength (nm).arrow_forwardI need help with the following questionarrow_forwardFor CARS, which statement is not true regarding its advantages? a) Contrast signal based on vibrational characteristics, no need for fluorescent tagging. b) Stronger signals than spontaneous Raman. c) Suffers from fluorescence interference, because CARS signal is at high frequency. d) Faster, more efficient imaging for real-time analysis. e) Higher resolution than spontaneous Raman microscopy.arrow_forward
- Draw the major product of the Claisen condensation reaction between two molecules of this ester. Ignore inorganic byproducts. Incorrect, 5 attempts remaining 1. NaOCH3/CH3OH 2. Acidic workup Select to Draw O Incorrect, 5 attempts remaining The total number of carbons in the parent chain is incorrect. Review the reaction conditions including starting materials and/or intermediate structures and recount the number of carbon atoms in the parent chain of your structure. OKarrow_forwardUsing a cell of known pathlength b = 1.25115 x 10-3 cm, a water absorption spectrum was measured. The band at 1645 cm-1, assigned to the O-H bending, showed an absorbance, A, of 1.40. a) Assuming that water density is 1.00 g/mL, calculate the water molar concentration c (hint: M= mole/L) b) Calculate the molar absorptivity, a, of the 1645 cm-1 band c) The transmitted light, I, can be written as I= Ioexp(-xb), where x is the absorption coefficient (sometimes designated as alpha), Io is the input light, and b is the cell pathlength. Prove that x= (ln10)*x*c d) Calculate x for the 1645 cm-1 bandarrow_forwardConvert 1.38 eV into wavelength (nm) and wavenumber (cm-1) (c = 2.998 x 108 m/s; h = 6.626 x 10-34 J*s).arrow_forward
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