(a) Interpretation: The product obtained on Hofmann rearrangement reaction of 2 − methylpropanamide in ethanol is to be stated. Concept introduction: Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ . The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

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Answer 1

Question

Chapter 23, Problem 23.40P

Interpretation Introduction

(a)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in ethanol is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ. The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Interpretation Introduction

(b)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in aqueous NaOH is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ.

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Transmitance 3. Which one of the following compounds corresponds to this IR spectrum? Point out the absorption band(s) that helped you decide. OH H3C OH H₂C CH3 H3C CH3 H3C INFRARED SPECTRUM 0.8- 0.6 0.4- 0.2 3000 2000 1000 Wavenumber (cm-1) 4. Consider this compound: H3C On the structure above, label the different types of H's as A, B, C, etc. In table form, list the labeled signals, and for each one state the number of hydrogens, their shifts, and the splitting you would observe for these hydrogens in the ¹H NMR spectrum. Label # of hydrogens splitting Shift (2)

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Answer 2

Question

Chapter 23, Problem 23.40P

Interpretation Introduction

(a)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in ethanol is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ. The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Interpretation Introduction

(b)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in aqueous NaOH is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ.

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Answer 3

Question

Chapter 23, Problem 23.40P

Interpretation Introduction

(a)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in ethanol is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ. The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Interpretation Introduction

(b)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in aqueous NaOH is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ.

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Answer 4

Question

Chapter 23, Problem 23.40P

Interpretation Introduction

(a)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in ethanol is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ. The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Interpretation Introduction

(b)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in aqueous NaOH is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ.

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Answer 5

Chapter 23, Problem 23.40P

Interpretation Introduction

(a)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in ethanol is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ. The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Interpretation Introduction

(b)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in aqueous NaOH is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ.

Answer 6

Chapter 23, Problem 23.40P

Interpretation Introduction

(a)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in ethanol is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ. The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Answer 7

Chapter 23, Problem 23.40P

Interpretation Introduction

(a)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in ethanol is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ. The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in aqueous NaOH is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in aqueous NaOH is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 23 - Prob. 23.1P Ch. 23 - Prob. 23.2P Ch. 23 - Prob. 23.3P Ch. 23 - Prob. 23.4P Ch. 23 - Prob. 23.5P Ch. 23 - Prob. 23.6P Ch. 23 - Prob. 23.7P Ch. 23 - Prob. 23.8P Ch. 23 - Prob. 23.9P Ch. 23 - Prob. 23.10P

Solution Summary: The author explains the product obtained on Hofmann rearrangement reaction of 2-methylpropanamide in ethanol.

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Chapter 23 Solutions