(a) Interpretation: The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is to be arranged. Concept introduction: Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Question

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Answer 1

Question

Chapter 23, Problem 23.7P

Interpretation Introduction

(a)

Interpretation:

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Explanation of Solution

It is known that the order of basicity of amines in aqueous solution is $NH3<3° amine<1° amine<2° amine$ . The dipropylamine amine is secondary amine. Therefore, it is most basic. The propylamine is primary amine. Therefore, it is second most basic. Ammonia is least basic. Therefore, the increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Conclusion

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Interpretation Introduction

(b)

Interpretation:

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Explanation of Solution

It is known that the order of basicity of amines in aqueous solution solution is $NH3<3° amine<1° amine<2° amine$ . The sec-butylamine is secondary amine. Therefore, it is most basic. The $methyl-3-aminopropanoate$ is primary amine. Therefore, it is second most basic. In case of $H3N+CH2CH2NH2$ , the positive charge on nitrogen makes it least basic. The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Conclusion

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Interpretation Introduction

(c)

Interpretation:

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Explanation of Solution

The structure of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate is shown below.

ORGANIC CHEM +SG +SAPLING >IP<, Chapter 23, Problem 23.7P , additional homework tip 1

Figure 1

Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

The basicity of aniline substituted compound depends on the group that is attached to benzene ring. If the group attached to benzene ring is electron withdrawing group, it will decrease the basicity of the compound. If the group attached to benzene ring is electron donating group, it will increase the basicity of the compound.

There is no group attached in case of aniline. Therefore, it is most basic. In case of methyl m-aminobenzoate and methyl p-aminobenzoate, the $CH3OCO−$ group is attached to benzene ring which is an electron withdrawing group. Therefore, this group decreases the electron density on nitrogen atom by $−I$ effect. This result the decreases in basicity. The effect is more at para position. Therefore, methyl p-aminobenzoate is less basic than methyl m-aminobenzoate. The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Conclusion

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Interpretation Introduction

(d)

Interpretation:

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Explanation of Solution

The structure of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline is shown below.

ORGANIC CHEM +SG +SAPLING >IP<, Chapter 23, Problem 23.7P , additional homework tip 2

Figure 2

Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

In case of aniline, the lone pair present at nitrogen atom is resonate with the benzene ring. Therefore, the electron density on nitrogen is decreased. Therefore, it is least basic.

In case of cyclohexylamine, there is no resonance. The cyclohexyl group is an electron donating group which increases the electron density on nitrogen atom. Therefore, the basicity of cyclohexylamine increased.

In case of benzylamine there is also no resonance because $sp3$ hybrid carbon is present in between the $NH2$ group and benzene ring. The phenyl group is an electron withdrawing group which decreases the electron density on nitrogen atom. Therefore, the basicity of benzylamine is less than cyclohexylamine.

In case of p-nitrobenzylamine there is also no resonance because $sp3$ hybrid carbon is present in between the $NH2$ group and benzene ring. The phenyl group is an electron withdrawing group which decreases the electron density on nitrogen atom. Due to presence of nitro group at para position the basicity of p-nitrobenzylamine is less than the benzylamine. Therefore, the increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Conclusion

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

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Answer 2

Question

Chapter 23, Problem 23.7P

Interpretation Introduction

(a)

Interpretation:

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Explanation of Solution

It is known that the order of basicity of amines in aqueous solution is $NH3<3° amine<1° amine<2° amine$ . The dipropylamine amine is secondary amine. Therefore, it is most basic. The propylamine is primary amine. Therefore, it is second most basic. Ammonia is least basic. Therefore, the increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Conclusion

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Interpretation Introduction

(b)

Interpretation:

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Explanation of Solution

It is known that the order of basicity of amines in aqueous solution solution is $NH3<3° amine<1° amine<2° amine$ . The sec-butylamine is secondary amine. Therefore, it is most basic. The $methyl-3-aminopropanoate$ is primary amine. Therefore, it is second most basic. In case of $H3N+CH2CH2NH2$ , the positive charge on nitrogen makes it least basic. The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Conclusion

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Interpretation Introduction

(c)

Interpretation:

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Explanation of Solution

The structure of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate is shown below.

ORGANIC CHEM +SG +SAPLING >IP<, Chapter 23, Problem 23.7P , additional homework tip 1

Figure 1

Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

The basicity of aniline substituted compound depends on the group that is attached to benzene ring. If the group attached to benzene ring is electron withdrawing group, it will decrease the basicity of the compound. If the group attached to benzene ring is electron donating group, it will increase the basicity of the compound.

There is no group attached in case of aniline. Therefore, it is most basic. In case of methyl m-aminobenzoate and methyl p-aminobenzoate, the $CH3OCO−$ group is attached to benzene ring which is an electron withdrawing group. Therefore, this group decreases the electron density on nitrogen atom by $−I$ effect. This result the decreases in basicity. The effect is more at para position. Therefore, methyl p-aminobenzoate is less basic than methyl m-aminobenzoate. The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Conclusion

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Interpretation Introduction

(d)

Interpretation:

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Explanation of Solution

The structure of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline is shown below.

ORGANIC CHEM +SG +SAPLING >IP<, Chapter 23, Problem 23.7P , additional homework tip 2

Figure 2

Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

In case of aniline, the lone pair present at nitrogen atom is resonate with the benzene ring. Therefore, the electron density on nitrogen is decreased. Therefore, it is least basic.

In case of cyclohexylamine, there is no resonance. The cyclohexyl group is an electron donating group which increases the electron density on nitrogen atom. Therefore, the basicity of cyclohexylamine increased.

In case of benzylamine there is also no resonance because $sp3$ hybrid carbon is present in between the $NH2$ group and benzene ring. The phenyl group is an electron withdrawing group which decreases the electron density on nitrogen atom. Therefore, the basicity of benzylamine is less than cyclohexylamine.

In case of p-nitrobenzylamine there is also no resonance because $sp3$ hybrid carbon is present in between the $NH2$ group and benzene ring. The phenyl group is an electron withdrawing group which decreases the electron density on nitrogen atom. Due to presence of nitro group at para position the basicity of p-nitrobenzylamine is less than the benzylamine. Therefore, the increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Conclusion

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

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Answer 3

Question

Chapter 23, Problem 23.7P

Interpretation Introduction

(a)

Interpretation:

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Explanation of Solution

It is known that the order of basicity of amines in aqueous solution is $NH3<3° amine<1° amine<2° amine$ . The dipropylamine amine is secondary amine. Therefore, it is most basic. The propylamine is primary amine. Therefore, it is second most basic. Ammonia is least basic. Therefore, the increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Conclusion

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Interpretation Introduction

(b)

Interpretation:

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Explanation of Solution

It is known that the order of basicity of amines in aqueous solution solution is $NH3<3° amine<1° amine<2° amine$ . The sec-butylamine is secondary amine. Therefore, it is most basic. The $methyl-3-aminopropanoate$ is primary amine. Therefore, it is second most basic. In case of $H3N+CH2CH2NH2$ , the positive charge on nitrogen makes it least basic. The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Conclusion

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Interpretation Introduction

(c)

Interpretation:

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Explanation of Solution

The structure of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate is shown below.

ORGANIC CHEM +SG +SAPLING >IP<, Chapter 23, Problem 23.7P , additional homework tip 1

Figure 1

Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

The basicity of aniline substituted compound depends on the group that is attached to benzene ring. If the group attached to benzene ring is electron withdrawing group, it will decrease the basicity of the compound. If the group attached to benzene ring is electron donating group, it will increase the basicity of the compound.

There is no group attached in case of aniline. Therefore, it is most basic. In case of methyl m-aminobenzoate and methyl p-aminobenzoate, the $CH3OCO−$ group is attached to benzene ring which is an electron withdrawing group. Therefore, this group decreases the electron density on nitrogen atom by $−I$ effect. This result the decreases in basicity. The effect is more at para position. Therefore, methyl p-aminobenzoate is less basic than methyl m-aminobenzoate. The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Conclusion

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Interpretation Introduction

(d)

Interpretation:

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Explanation of Solution

The structure of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline is shown below.

ORGANIC CHEM +SG +SAPLING >IP<, Chapter 23, Problem 23.7P , additional homework tip 2

Figure 2

Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

In case of aniline, the lone pair present at nitrogen atom is resonate with the benzene ring. Therefore, the electron density on nitrogen is decreased. Therefore, it is least basic.

In case of cyclohexylamine, there is no resonance. The cyclohexyl group is an electron donating group which increases the electron density on nitrogen atom. Therefore, the basicity of cyclohexylamine increased.

In case of benzylamine there is also no resonance because $sp3$ hybrid carbon is present in between the $NH2$ group and benzene ring. The phenyl group is an electron withdrawing group which decreases the electron density on nitrogen atom. Therefore, the basicity of benzylamine is less than cyclohexylamine.

In case of p-nitrobenzylamine there is also no resonance because $sp3$ hybrid carbon is present in between the $NH2$ group and benzene ring. The phenyl group is an electron withdrawing group which decreases the electron density on nitrogen atom. Due to presence of nitro group at para position the basicity of p-nitrobenzylamine is less than the benzylamine. Therefore, the increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Conclusion

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

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Answer 4

Question

Chapter 23, Problem 23.7P

Interpretation Introduction

(a)

Interpretation:

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Explanation of Solution

It is known that the order of basicity of amines in aqueous solution is $NH3<3° amine<1° amine<2° amine$ . The dipropylamine amine is secondary amine. Therefore, it is most basic. The propylamine is primary amine. Therefore, it is second most basic. Ammonia is least basic. Therefore, the increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Conclusion

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Interpretation Introduction

(b)

Interpretation:

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Explanation of Solution

It is known that the order of basicity of amines in aqueous solution solution is $NH3<3° amine<1° amine<2° amine$ . The sec-butylamine is secondary amine. Therefore, it is most basic. The $methyl-3-aminopropanoate$ is primary amine. Therefore, it is second most basic. In case of $H3N+CH2CH2NH2$ , the positive charge on nitrogen makes it least basic. The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Conclusion

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Interpretation Introduction

(c)

Interpretation:

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Explanation of Solution

The structure of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate is shown below.

ORGANIC CHEM +SG +SAPLING >IP<, Chapter 23, Problem 23.7P , additional homework tip 1

Figure 1

Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

The basicity of aniline substituted compound depends on the group that is attached to benzene ring. If the group attached to benzene ring is electron withdrawing group, it will decrease the basicity of the compound. If the group attached to benzene ring is electron donating group, it will increase the basicity of the compound.

There is no group attached in case of aniline. Therefore, it is most basic. In case of methyl m-aminobenzoate and methyl p-aminobenzoate, the $CH3OCO−$ group is attached to benzene ring which is an electron withdrawing group. Therefore, this group decreases the electron density on nitrogen atom by $−I$ effect. This result the decreases in basicity. The effect is more at para position. Therefore, methyl p-aminobenzoate is less basic than methyl m-aminobenzoate. The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Conclusion

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Interpretation Introduction

(d)

Interpretation:

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Explanation of Solution

The structure of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline is shown below.

ORGANIC CHEM +SG +SAPLING >IP<, Chapter 23, Problem 23.7P , additional homework tip 2

Figure 2

Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

In case of aniline, the lone pair present at nitrogen atom is resonate with the benzene ring. Therefore, the electron density on nitrogen is decreased. Therefore, it is least basic.

In case of cyclohexylamine, there is no resonance. The cyclohexyl group is an electron donating group which increases the electron density on nitrogen atom. Therefore, the basicity of cyclohexylamine increased.

In case of benzylamine there is also no resonance because $sp3$ hybrid carbon is present in between the $NH2$ group and benzene ring. The phenyl group is an electron withdrawing group which decreases the electron density on nitrogen atom. Therefore, the basicity of benzylamine is less than cyclohexylamine.

In case of p-nitrobenzylamine there is also no resonance because $sp3$ hybrid carbon is present in between the $NH2$ group and benzene ring. The phenyl group is an electron withdrawing group which decreases the electron density on nitrogen atom. Due to presence of nitro group at para position the basicity of p-nitrobenzylamine is less than the benzylamine. Therefore, the increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Conclusion

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

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Answer 5

Chapter 23, Problem 23.7P

Interpretation Introduction

(a)

Interpretation:

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Explanation of Solution

It is known that the order of basicity of amines in aqueous solution is $NH3<3° amine<1° amine<2° amine$ . The dipropylamine amine is secondary amine. Therefore, it is most basic. The propylamine is primary amine. Therefore, it is second most basic. Ammonia is least basic. Therefore, the increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Conclusion

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Interpretation Introduction

(b)

Interpretation:

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Explanation of Solution

It is known that the order of basicity of amines in aqueous solution solution is $NH3<3° amine<1° amine<2° amine$ . The sec-butylamine is secondary amine. Therefore, it is most basic. The $methyl-3-aminopropanoate$ is primary amine. Therefore, it is second most basic. In case of $H3N+CH2CH2NH2$ , the positive charge on nitrogen makes it least basic. The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Conclusion

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Interpretation Introduction

(c)

Interpretation:

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Explanation of Solution

The structure of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate is shown below.

ORGANIC CHEM +SG +SAPLING >IP<, Chapter 23, Problem 23.7P , additional homework tip 1

Figure 1

Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

The basicity of aniline substituted compound depends on the group that is attached to benzene ring. If the group attached to benzene ring is electron withdrawing group, it will decrease the basicity of the compound. If the group attached to benzene ring is electron donating group, it will increase the basicity of the compound.

There is no group attached in case of aniline. Therefore, it is most basic. In case of methyl m-aminobenzoate and methyl p-aminobenzoate, the $CH3OCO−$ group is attached to benzene ring which is an electron withdrawing group. Therefore, this group decreases the electron density on nitrogen atom by $−I$ effect. This result the decreases in basicity. The effect is more at para position. Therefore, methyl p-aminobenzoate is less basic than methyl m-aminobenzoate. The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Conclusion

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Interpretation Introduction

(d)

Interpretation:

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Explanation of Solution

The structure of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline is shown below.

ORGANIC CHEM +SG +SAPLING >IP<, Chapter 23, Problem 23.7P , additional homework tip 2

Figure 2

Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

In case of aniline, the lone pair present at nitrogen atom is resonate with the benzene ring. Therefore, the electron density on nitrogen is decreased. Therefore, it is least basic.

In case of cyclohexylamine, there is no resonance. The cyclohexyl group is an electron donating group which increases the electron density on nitrogen atom. Therefore, the basicity of cyclohexylamine increased.

In case of benzylamine there is also no resonance because $sp3$ hybrid carbon is present in between the $NH2$ group and benzene ring. The phenyl group is an electron withdrawing group which decreases the electron density on nitrogen atom. Therefore, the basicity of benzylamine is less than cyclohexylamine.

In case of p-nitrobenzylamine there is also no resonance because $sp3$ hybrid carbon is present in between the $NH2$ group and benzene ring. The phenyl group is an electron withdrawing group which decreases the electron density on nitrogen atom. Due to presence of nitro group at para position the basicity of p-nitrobenzylamine is less than the benzylamine. Therefore, the increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Conclusion

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Answer 6

Chapter 23, Problem 23.7P

Interpretation Introduction

(a)

Interpretation:

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Explanation of Solution

It is known that the order of basicity of amines in aqueous solution is $NH3<3° amine<1° amine<2° amine$ . The dipropylamine amine is secondary amine. Therefore, it is most basic. The propylamine is primary amine. Therefore, it is second most basic. Ammonia is least basic. Therefore, the increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Conclusion

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Answer 7

Chapter 23, Problem 23.7P

Interpretation Introduction

(a)

Interpretation:

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Answer 8

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

It is known that the order of basicity of amines in aqueous solution is $NH3<3° amine<1° amine<2° amine$ . The dipropylamine amine is secondary amine. Therefore, it is most basic. The propylamine is primary amine. Therefore, it is second most basic. Ammonia is least basic. Therefore, the increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Answer 13

Conclusion

The increasing order of basicity of propylamine, ammonia, and dipropylamine in aqueous solution is shown below.

$Ammonia<propylamine<dipropylamine$

Answer 14

Interpretation Introduction

(b)

Interpretation:

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Explanation of Solution

It is known that the order of basicity of amines in aqueous solution solution is $NH3<3° amine<1° amine<2° amine$ . The sec-butylamine is secondary amine. Therefore, it is most basic. The $methyl-3-aminopropanoate$ is primary amine. Therefore, it is second most basic. In case of $H3N+CH2CH2NH2$ , the positive charge on nitrogen makes it least basic. The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Conclusion

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Answer 15

Interpretation Introduction

(b)

Interpretation:

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Answer 16

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Explanation of Solution

It is known that the order of basicity of amines in aqueous solution solution is $NH3<3° amine<1° amine<2° amine$ . The sec-butylamine is secondary amine. Therefore, it is most basic. The $methyl-3-aminopropanoate$ is primary amine. Therefore, it is second most basic. In case of $H3N+CH2CH2NH2$ , the positive charge on nitrogen makes it least basic. The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Answer 21

Conclusion

The increasing order of basicity of $methyl-3-aminopropanoate$ , sec-butylamine, and $H3N+CH2CH2NH2$ in aqueous solution is shown below.

$H3N+CH2CH2NH2<methyl-3-aminopropanoate<sec-butylamine$

Answer 22

Interpretation Introduction

(c)

Interpretation:

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Explanation of Solution

The structure of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate is shown below.

ORGANIC CHEM +SG +SAPLING >IP<, Chapter 23, Problem 23.7P , additional homework tip 1

Figure 1

Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

The basicity of aniline substituted compound depends on the group that is attached to benzene ring. If the group attached to benzene ring is electron withdrawing group, it will decrease the basicity of the compound. If the group attached to benzene ring is electron donating group, it will increase the basicity of the compound.

There is no group attached in case of aniline. Therefore, it is most basic. In case of methyl m-aminobenzoate and methyl p-aminobenzoate, the $CH3OCO−$ group is attached to benzene ring which is an electron withdrawing group. Therefore, this group decreases the electron density on nitrogen atom by $−I$ effect. This result the decreases in basicity. The effect is more at para position. Therefore, methyl p-aminobenzoate is less basic than methyl m-aminobenzoate. The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Conclusion

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Answer 23

Interpretation Introduction

(c)

Interpretation:

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Answer 24

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Explanation of Solution

The structure of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate is shown below.

ORGANIC CHEM +SG +SAPLING >IP<, Chapter 23, Problem 23.7P , additional homework tip 1

Figure 1

Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

The basicity of aniline substituted compound depends on the group that is attached to benzene ring. If the group attached to benzene ring is electron withdrawing group, it will decrease the basicity of the compound. If the group attached to benzene ring is electron donating group, it will increase the basicity of the compound.

There is no group attached in case of aniline. Therefore, it is most basic. In case of methyl m-aminobenzoate and methyl p-aminobenzoate, the $CH3OCO−$ group is attached to benzene ring which is an electron withdrawing group. Therefore, this group decreases the electron density on nitrogen atom by $−I$ effect. This result the decreases in basicity. The effect is more at para position. Therefore, methyl p-aminobenzoate is less basic than methyl m-aminobenzoate. The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Answer 29

Conclusion

The increasing order of basicity of aniline, methyl m-aminobenzoate, and methyl p-aminobenzoate in aqueous solution is shown below.

$Methyl p-aminobenzoate<methyl m-aminobenzoate<aniline$

Answer 30

Interpretation Introduction

(d)

Interpretation:

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Explanation of Solution

The structure of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline is shown below.

ORGANIC CHEM +SG +SAPLING >IP<, Chapter 23, Problem 23.7P , additional homework tip 2

Figure 2

Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

In case of aniline, the lone pair present at nitrogen atom is resonate with the benzene ring. Therefore, the electron density on nitrogen is decreased. Therefore, it is least basic.

In case of cyclohexylamine, there is no resonance. The cyclohexyl group is an electron donating group which increases the electron density on nitrogen atom. Therefore, the basicity of cyclohexylamine increased.

In case of benzylamine there is also no resonance because $sp3$ hybrid carbon is present in between the $NH2$ group and benzene ring. The phenyl group is an electron withdrawing group which decreases the electron density on nitrogen atom. Therefore, the basicity of benzylamine is less than cyclohexylamine.

In case of p-nitrobenzylamine there is also no resonance because $sp3$ hybrid carbon is present in between the $NH2$ group and benzene ring. The phenyl group is an electron withdrawing group which decreases the electron density on nitrogen atom. Due to presence of nitro group at para position the basicity of p-nitrobenzylamine is less than the benzylamine. Therefore, the increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Conclusion

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Answer 31

Interpretation Introduction

(d)

Interpretation:

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is to be arranged.

Concept introduction:

Amines are the organic compounds that are formed by replacement of hydrogen from ammonia. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

Answer 32

Expert Solution

Answer to Problem 23.7P

The increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.

$Aniline<p-nitrobenzylamine<benzylamine<cyclohexylamine$

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Explanation of Solution

The structure of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline is shown below.

ORGANIC CHEM +SG +SAPLING >IP<, Chapter 23, Problem 23.7P , additional homework tip 2

Figure 2

Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.

In case of aniline, the lone pair present at nitrogen atom is resonate with the benzene ring. Therefore, the electron density on nitrogen is decreased. Therefore, it is least basic.

In case of cyclohexylamine, there is no resonance. The cyclohexyl group is an electron donating group which increases the electron density on nitrogen atom. Therefore, the basicity of cyclohexylamine increased.

In case of benzylamine there is also no resonance because $sp3$ hybrid carbon is present in between the $NH2$ group and benzene ring. The phenyl group is an electron withdrawing group which decreases the electron density on nitrogen atom. Therefore, the basicity of benzylamine is less than cyclohexylamine.

In case of p-nitrobenzylamine there is also no resonance because $sp3$ hybrid carbon is present in between the $NH2$ group and benzene ring. The phenyl group is an electron withdrawing group which decreases the electron density on nitrogen atom. Due to presence of nitro group at para position the basicity of p-nitrobenzylamine is less than the benzylamine. Therefore, the increasing order of basicity of benzylamine, p-nitrobenzylamine, cyclohexylamine, aniline in aqueous solution is shown below.