(a) Interpretation: The carbonyl compound in given pair that exhibits the higher percentage of the enol tautomer is to be identified. Concept introduction: Tautomers are isomers which differ only in the position of the hydrogen and electrons of the electronegative atom, generally oxygen. There is no change in the carbon skeleton of the compound. This phenomenon which involves simple proton transfer in an intramolecular fashion is known as tautomerism. The very common example of tautomerism is Keto-enol tautomerism. It can be acid or base catalysed. The very common example of tautomerism is Keto-enol tautomerism. It can be acid or base catalyzed. Formation of predominant product is determined by several factors.

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LTS Solid: AT=Te-Ti Trial 1 Trial 2 Trial 3 Average ΔΗ Mass water, g 24.096 23.976 23.975 Moles of solid, mol 0.01763 001767 0101781 Temp. change, °C 2.9°C 11700 2.0°C Heat of reaction, J -292.37J -170.473 -193.26J AH, kJ/mole 16.58K 9.647 kJ 10.85 kr 16.58K59.64701 KJ mol 12.35k Minimum AS, J/mol K 41.582 mol-k Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn & Show your calculations for: AH in J and then in kJ/mole for Trial 1: qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J qsin = qrxn = 292.35 292.37J AH in J = 292.375 0.2923kJ 0.01763m01 =1.65×107 AH in kJ/mol = = 16.58K 0.01763mol mol qrx Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con Kelvin.) AS=AHIT (1.65×10(9.64×103) + (1.0 Jimai

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Chapter 23, Problem 23.33P

Interpretation Introduction

(a)

Interpretation: The carbonyl compound in given pair that exhibits the higher percentage of the enol tautomer is to be identified.

Concept introduction: Tautomers are isomers which differ only in the position of the hydrogen and electrons of the electronegative atom, generally oxygen. There is no change in the carbon skeleton of the compound. This phenomenon which involves simple proton transfer in an intramolecular fashion is known as tautomerism.

The very common example of tautomerism is Keto-enol tautomerism. It can be acid or base catalysed.

The very common example of tautomerism is Keto-enol tautomerism. It can be acid or base catalyzed. Formation of predominant product is determined by several factors.

Interpretation Introduction

(b)

Interpretation: The carbonyl compound in given pair that exhibits the higher percentage of the enol tautomer is to be identified.

Concept introduction: Tautomers are isomers which differ only in the position of the protons and electrons of the compound. There is no change in the carbon skeleton of the compound. This phenomenon which involves simple proton transfer in an intramolecular fashion is known as tautomerism.The very common example of tautomerism is Keto-enol tautomerism. It can be acid or base catalyzed. Formation of predominant product is determined by several factors.

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LTS Solid: AT=Te-Ti Trial 1 Trial 2 Trial 3 Average ΔΗ Mass water, g 24.096 23.976 23.975 Moles of solid, mol 0.01763 001767 0101781 Temp. change, °C 2.9°C 11700 2.0°C Heat of reaction, J -292.37J -170.473 -193.26J AH, kJ/mole 16.58K 9.647 kJ 10.85 kr 16.58K59.64701 KJ mol 12.35k Minimum AS, J/mol K 41.582 mol-k Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn & Show your calculations for: AH in J and then in kJ/mole for Trial 1: qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J qsin = qrxn = 292.35 292.37J AH in J = 292.375 0.2923kJ 0.01763m01 =1.65×107 AH in kJ/mol = = 16.58K 0.01763mol mol qrx Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con Kelvin.) AS=AHIT (1.65×10(9.64×103) + (1.0 Jimai

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