Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN: 9781305960060
Author: Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher: Cengage Learning
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Chapter 23, Problem 23.19E
Interpretation Introduction
Interpretation:
The way by which the formation of lactate allows glycolysis to continue under anaerobic conditions is to be explained.
Concept introduction:
Lactate is the conjugate base of lactic acid. Lactic acid is the organic acid that is soluble in water. It is produced under the anaerobic condition. The high amount of lactate in blood indicates the lack of oxygen.
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Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following:
(a) match structures of isomers given their mass spectra below (spectra A and spectra B)
(b) Draw the fragments given the following prominent peaks from
each spectrum:
Spectra A m/2 =43 and 1/2-57
spectra B m/2 = 43
(c) why is 1/2=57 peak in spectrum A more intense compared
to the same peak in spectrum B.
Relative abundance
Relative abundance
100
A
50
29
29
0
10
-0
-0
100
B
50
720
30
41
43
57
71
4-0
40
50
60 70
m/z
43
57
8-0
m/z = 86
M
90 100
71
m/z = 86
M
-O
0
10 20 30
40 50
60
70
80
-88
m/z
90
100
Part IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass
spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained.
Draw the structures of these fragments.
For each reaction shown below follow the curved arrows to complete each equationby showing the structure of the products. Identify the acid, the base, the conjugated acid andconjugated base. Consutl the pKa table and choose the direciton theequilibrium goes. However show the curved arrows. Please explain if possible.
Chapter 23 Solutions
Chemistry for Today: General, Organic, and Biochemistry
Ch. 23 - Why is glucose considered the pivotal compound in...Ch. 23 - Prob. 23.2ECh. 23 - Prob. 23.3ECh. 23 - Describe what is meant by the terms blood sugar...Ch. 23 - What range of concentrations for glucose in blood...Ch. 23 - Prob. 23.6ECh. 23 - Prob. 23.7ECh. 23 - Prob. 23.8ECh. 23 - Prob. 23.9ECh. 23 - Prob. 23.10E
Ch. 23 - Prob. 23.11ECh. 23 - Prob. 23.12ECh. 23 - Prob. 23.13ECh. 23 - Prob. 23.14ECh. 23 - Prob. 23.15ECh. 23 - Prob. 23.16ECh. 23 - Prob. 23.17ECh. 23 - Prob. 23.18ECh. 23 - Prob. 23.19ECh. 23 - Prob. 23.20ECh. 23 - Prob. 23.21ECh. 23 - Prob. 23.22ECh. 23 - Prob. 23.23ECh. 23 - Prob. 23.24ECh. 23 - Prob. 23.25ECh. 23 - Prob. 23.26ECh. 23 - Prob. 23.27ECh. 23 - Prob. 23.28ECh. 23 - Prob. 23.29ECh. 23 - Prob. 23.30ECh. 23 - Prob. 23.31ECh. 23 - Prob. 23.32ECh. 23 - Prob. 23.33ECh. 23 - Prob. 23.34ECh. 23 - Prob. 23.35ECh. 23 - Prob. 23.36ECh. 23 - Prob. 23.37ECh. 23 - Prob. 23.38ECh. 23 - Prob. 23.39ECh. 23 - Prob. 23.40ECh. 23 - Prob. 23.41ECh. 23 - Prob. 23.42ECh. 23 - Prob. 23.43ECh. 23 - Prob. 23.44ECh. 23 - Prob. 23.45ECh. 23 - Prob. 23.46ECh. 23 - Prob. 23.47ECh. 23 - Prob. 23.48ECh. 23 - Prob. 23.49ECh. 23 - Prob. 23.50ECh. 23 - Prob. 23.51ECh. 23 - Prob. 23.52ECh. 23 - Prob. 23.53ECh. 23 - Prob. 23.54ECh. 23 - Prob. 23.55ECh. 23 - Prob. 23.56ECh. 23 - Prob. 23.57ECh. 23 - Prob. 23.58ECh. 23 - Prob. 23.59ECh. 23 - Prob. 23.60ECh. 23 - Prob. 23.61ECh. 23 - Prob. 23.62ECh. 23 - Prob. 23.63ECh. 23 - Prob. 23.64ECh. 23 - Prob. 23.65ECh. 23 - Lactate dehydrogenase catalyzes the following...Ch. 23 - Prob. 23.67ECh. 23 - Prob. 23.68ECh. 23 - Prob. 23.69ECh. 23 - Prob. 23.70ECh. 23 - A friend started to make wine by adding yeast to...Ch. 23 - Prob. 23.72ECh. 23 - Explain why monitoring blood lactate levels might...Ch. 23 - Prob. 23.74ECh. 23 - Prob. 23.75ECh. 23 - Prob. 23.76ECh. 23 - Prob. 23.77ECh. 23 - Prob. 23.78ECh. 23 - Prob. 23.79ECh. 23 - Prob. 23.80ECh. 23 - Prob. 23.81ECh. 23 - Prob. 23.82ECh. 23 - Prob. 23.83ECh. 23 - Prob. 23.84ECh. 23 - Prob. 23.85ECh. 23 - Prob. 23.86ECh. 23 - Prob. 23.87ECh. 23 - Prob. 23.88ECh. 23 - Prob. 23.89ECh. 23 - Prob. 23.90E
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