Chemistry: Atoms First V1
Chemistry: Atoms First V1
1st Edition
ISBN: 9781259383120
Author: Burdge
Publisher: McGraw Hill Custom
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Chapter 2.3, Problem 1PPA

(a)

Interpretation Introduction

Interpretation: The number of Protons, electrons, Neutrons for each atom is identified.

Concept Introduction:

Conversion of atoms to moles: no.of moles  = no.of atomsAvogadro's number.

Mass number: The sum of protons and neutrons gives the value of atomic mass.

A (mass number) = no.of protons (P) + no.of  neutrons (N)

The element symbol : ZAXwhere, A (atomic mass)= no. of protons + no.of neutrons.Z (atomic number) is same as the protons and electrons.

Nuclear stability: The nucleus is composed of protons and neutrons. The strongest nuclear force binds the particles tightly. Though the protons repel each other due to no attraction between similar charges, possess short-range attractions made the attraction possible between proton and proton, proton and neutron, neutron and neutron.

The stability of any element is determined by the difference between coulombic repulsion and the short-range attraction. If repulsion outweighs the attraction, the disintegration of nucleus occurs by producing the daughter nuclides. If the attractive forces prevail, the nucleus is stable.

(b)

Interpretation Introduction

Interpretation: The number of Protons, electrons, Neutrons for each atom is identified.

Concept Introduction:

Conversion of atoms to moles: no.of moles  = no.of atomsAvogadro's number.

Mass number: The sum of protons and neutrons gives the value of atomic mass.

A (mass number) = no.of protons (P) + no.of  neutrons (N)

The element symbol : ZAXwhere, A (atomic mass)= no. of protons + no.of neutrons.Z (atomic number) is same as the protons and electrons.

Nuclear stability: The nucleus is composed of protons and neutrons. The strongest nuclear force binds the particles tightly. Though the protons repel each other due to no attraction between similar charges, possess short-range attractions made the attraction possible between proton and proton, proton and neutron, neutron and neutron.

The stability of any element is determined by the difference between coulombic repulsion and the short-range attraction. If repulsion outweighs the attraction, the disintegration of nucleus occurs by producing the daughter nuclides. If the attractive forces prevail, the nucleus is stable.

(c)

Interpretation Introduction

Interpretation: The number of Protons, electrons, Neutrons for each atom is identified.

Concept Introduction:

Conversion of atoms to moles: no.of moles  = no.of atomsAvogadro's number.

Mass number: The sum of protons and neutrons gives the value of atomic mass.

A (mass number) = no.of protons (P) + no.of  neutrons (N)

The element symbol : ZAXwhere, A (atomic mass)= no. of protons + no.of neutrons.Z (atomic number) is same as the protons and electrons.

Nuclear stability: The nucleus is composed of protons and neutrons. The strongest nuclear force binds the particles tightly. Though the protons repel each other due to no attraction between similar charges, possess short-range attractions made the attraction possible between proton and proton, proton and neutron, neutron and neutron.

The stability of any element is determined by the difference between coulombic repulsion and the short-range attraction. If repulsion outweighs the attraction, the disintegration of nucleus occurs by producing the daughter nuclides. If the attractive forces prevail, the nucleus is stable.

(d)

Interpretation Introduction

Interpretation: The number of Protons, electrons, Neutrons for each atom is identified.

Concept Introduction:

Conversion of atoms to moles: no.of moles  = no.of atomsAvogadro's number.

Mass number: The sum of protons and neutrons gives the value of atomic mass.

A (mass number) = no.of protons (P) + no.of  neutrons (N)

The element symbol : ZAXwhere, A (atomic mass)= no. of protons + no.of neutrons.Z (atomic number) is same as the protons and electrons.

Nuclear stability: The nucleus is composed of protons and neutrons. The strongest nuclear force binds the particles tightly. Though the protons repel each other due to no attraction between similar charges, possess short-range attractions made the attraction possible between proton and proton, proton and neutron, neutron and neutron.

The stability of any element is determined by the difference between coulombic repulsion and the short-range attraction. If repulsion outweighs the attraction, the disintegration of nucleus occurs by producing the daughter nuclides. If the attractive forces prevail, the nucleus is stable.

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Chapter 2 Solutions

Chemistry: Atoms First V1

Ch. 2.5 - The average atomic mass of nitrogen is 14.0067....Ch. 2.5 - Prob. 2PPCCh. 2.5 - Boron has two naturally occurring isotopes, 10B...Ch. 2.5 - The two naturally occurring isotopes of antimony,...Ch. 2.6 - Prob. 2.6.1SRCh. 2.6 - Prob. 2.6.2SRCh. 2.7 - Calcium is the most abundant metal in the human...Ch. 2.7 - Prob. 3PPACh. 2.7 - Calculate (a) the number of atoms in 1.05 106...Ch. 2.7 - Prob. 3PPCCh. 2.7 - Prob. 2.4WECh. 2.7 - Prob. 4PPACh. 2.7 - Prob. 4PPBCh. 2.7 - Prob. 4PPCCh. 2.7 - Prob. 2.5WECh. 2.7 - Prob. 5PPACh. 2.7 - Prob. 5PPBCh. 2.7 - Prob. 5PPCCh. 2.7 - Prob. 2.7.1SRCh. 2.7 - Prob. 2.7.2SRCh. 2.7 - Prob. 2.7.3SRCh. 2.7 - Prob. 2.7.4SRCh. 2 - Define the terms atom and element.Ch. 2 - Use a familiar macroscopic example as an analogy...Ch. 2 - Prob. 2.3QPCh. 2 - Prob. 2.4QPCh. 2 - Prob. 2.5QPCh. 2 - Prob. 2.6QPCh. 2 - Describe the experimental basis for believing that...Ch. 2 - Prob. 2.8QPCh. 2 - Prob. 2.9QPCh. 2 - Prob. 2.10QPCh. 2 - Prob. 2.11QPCh. 2 - Prob. 2.12QPCh. 2 - Prob. 2.13QPCh. 2 - Prob. 2.14QPCh. 2 - Prob. 2.15QPCh. 2 - Prob. 2.16QPCh. 2 - Prob. 2.17QPCh. 2 - Prob. 2.18QPCh. 2 - Prob. 2.19QPCh. 2 - Determine the mass number of (a) a beryllium atom...Ch. 2 - Prob. 2.21QPCh. 2 - The following radioactive isotopes are used in...Ch. 2 - Prob. 2.23QPCh. 2 - Prob. 2.24QPCh. 2 - Prob. 2.25QPCh. 2 - Prob. 2.26QPCh. 2 - Prob. 2.27QPCh. 2 - Prob. 2.28QPCh. 2 - Prob. 2.29QPCh. 2 - Prob. 2.30QPCh. 2 - What is the mass (in amu) of a carbon-12 atom? Why...Ch. 2 - Prob. 2.32QPCh. 2 - What information would you need to calculate the...Ch. 2 - Prob. 2.34QPCh. 2 - Prob. 2.35QPCh. 2 - Prob. 2.36QPCh. 2 - Prob. 2.37QPCh. 2 - The element rubidium has two naturally occurring...Ch. 2 - Prob. 2.39QPCh. 2 - Prob. 2.40QPCh. 2 - Prob. 2.41QPCh. 2 - Give two examples of each of the following: (a)...Ch. 2 - Prob. 2.43QPCh. 2 - Prob. 2.44QPCh. 2 - Describe the changes in properties (from metals to...Ch. 2 - Consult the WebElements Periodic Table of the...Ch. 2 - Group the following elements in pairs that you...Ch. 2 - Prob. 2.48QPCh. 2 - Prob. 2.49QPCh. 2 - Prob. 2.50QPCh. 2 - Prob. 2.51QPCh. 2 - Prob. 2.52QPCh. 2 - Prob. 2.53QPCh. 2 - Prob. 2.54QPCh. 2 - Prob. 2.55QPCh. 2 - Prob. 2.56QPCh. 2 - Prob. 2.57QPCh. 2 - Prob. 2.58QPCh. 2 - Prob. 2.59QPCh. 2 - Prob. 2.60QPCh. 2 - Prob. 2.61QPCh. 2 - Prob. 2.62QPCh. 2 - Prob. 2.63QPCh. 2 - Prob. 2.64QPCh. 2 - The element francium (Fr) was the last element of...Ch. 2 - Prob. 2.66QPCh. 2 - Prob. 2.67QPCh. 2 - Prob. 2.68QPCh. 2 - Prob. 2.69QPCh. 2 - Prob. 2.70QPCh. 2 - Discuss the significance of assigning an atomic...Ch. 2 - Prob. 2.72QPCh. 2 - Prob. 2.73QPCh. 2 - Prob. 2.74QPCh. 2 - Prob. 2.75QPCh. 2 - Prob. 2.76QPCh. 2 - Identify each of the following elements: (a) a...Ch. 2 - Prob. 2.78QPCh. 2 - Prob. 2.79QPCh. 2 - Prob. 2.80QPCh. 2 - Prob. 2.81QPCh. 2 - Prob. 2.82QPCh. 2 - Prob. 2.83QPCh. 2 - Prob. 2.84QP
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