Chapter 2, Problem 2.57QP

Interpretation Introduction

Interpretation:

It should be determined that how many grams of platinum (Pt) are there in 26.4 moles of Pt.

Concept introduction:

• A mole is $\text{6}\text{.022 }\times {10}^{23}$ of anything.
• $\text{6}\text{.022 }\times {10}^{23}$ Is known as Avogadro number.
• Molar mass of an element is the mass in gram of one mole of the element. Unit of molar mass is expressed in grams per mole g/mol.
• $\text{Number}\text{}\text{}\text{}\text{of}\text{}\text{mole}\text{=}\frac{\text{Given}\text{}\text{mass}}{\text{Molar}\text{mass}}$