Study Guide for Campbell Biology
11th Edition
ISBN: 9780134443775
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece, Martha R. Taylor, Michael A. Pollock
Publisher: PEARSON
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Textbook Question
Chapter 23, Problem 11TYK
In a random sample of a population of shorthorn cattle, 73 animals were red (CRCR); 63 were roan, a mixture of red and white (CRCr); and 13 were white (CrCr). Estimate the allele frequencies of CR and Cr, and explain whether or not the population is in Hardy-Weinberg equilibrium.
- a. CR = 0.64, Cr = 0.36; because the population is large and a random sample was chosen, the population is in equilibrium.
- b. CR = 0.7, Cr = 0.3; the genotype ratio is not what would be predicted from these frequencies, and the population is not in equilibrium.
- c. CR = 0.7, Cr = 0.3; the genotype ratio is close to what would be predicted from these frequencies, and the population is in equilibrium.
- d. CR = 1.04, Cr = 0.44; the allele frequencies add up to greater than 1, and the population is not in equilibrium.
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Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem. So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations). If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…
If a population is in Hardy-Weinberg equilibrium for the multiple alleles A+, A and a, whose frequencies are p= 0.60 for A+, q= 0.20 for A, and r = 0.20 for a, what percentage of the population is expected to be heterozygous?
An autosomal locus has alleles A and a.
The allele frequencies in a population at Hardy Weinberg equilibrium are
p = Freq(A) = 0.5
q = Freq(a) = 0.5
What is the frequency of homozygous wild-type (AA) in this population?
Enter a single number between 0 and 1, for example, 0.33
Chapter 23 Solutions
Study Guide for Campbell Biology
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