Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card
Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card
9th Edition
ISBN: 9781305701021
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 22.SE, Problem 53AP
Interpretation Introduction

Interpretation:

Whether the product obtained by the bromination of optically active (R)-2-phenylpropanoic acid under Hell-Volhard-Zelinski conditions is optically active or racemic is to be explained.

Concept introduction:

Hell-Volhard-Zelinski reaction takes place through the formation of an acid bromide enol intermediate. If the chiral carbon of the optically active carboxylic acid is involved in the enol formation chirality will be lost during enolization, as the double bonds are planar. Bromination of this enol can take place from either face of the enol double bond leading to the formation of a racemic mixture. If the chiral carbon does not take part in enol formation, then the resulting product will be optically active.

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Consider this step in a radical reaction: Br N O hv What type of step is this? Check all that apply. Draw the products of the step on the right-hand side of the drawing area below. If more than one set of products is possible, draw any set. Also, draw the mechanism arrows on the left-hand side of the drawing area to show how this happens. O primary Otermination O initialization O electrophilic O none of the above × ☑
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Chapter 22 Solutions

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card

Ch. 22.7 - Draw a resonance structure of the acetonitrile...Ch. 22.7 - Why do you suppose ketone halogenations in acidic...Ch. 22.7 - Prob. 13PCh. 22.7 - Prob. 14PCh. 22.7 - Prob. 15PCh. 22.7 - Prob. 16PCh. 22.SE - Prob. 17VCCh. 22.SE - Prob. 18VCCh. 22.SE - Prob. 19VCCh. 22.SE - Prob. 20MPCh. 22.SE - Predict the product(s) and provide the mechanism...Ch. 22.SE - Predict the product(s) and provide the mechanism...Ch. 22.SE - Prob. 23MPCh. 22.SE - In the Hell–Volhard–Zelinskii reaction, only a...Ch. 22.SE - Prob. 25MPCh. 22.SE - Nonconjugated , -unsaturated ketones, such as...Ch. 22.SE - Prob. 27MPCh. 22.SE - Using curved arrows, propose a mechanism for the...Ch. 22.SE - Prob. 29MPCh. 22.SE - One of the later steps in glucose biosynthesis is...Ch. 22.SE - The Favorskii reaction involves treatment of an...Ch. 22.SE - Treatment of a cyclic ketone with diazomethane is...Ch. 22.SE - Prob. 33MPCh. 22.SE - Amino acids can be prepared by reaction of alkyl...Ch. 22.SE - Amino acids can also be prepared by a two-step...Ch. 22.SE - Heating carvone with aqueous sulfuric acid...Ch. 22.SE - Identify all the acidic hydrogens (pKa 25) in the...Ch. 22.SE - Rank the following compounds in order of...Ch. 22.SE - Prob. 39APCh. 22.SE - Base treatment of the following , -unsaturated...Ch. 22.SE - Prob. 41APCh. 22.SE - Prob. 42APCh. 22.SE - Prob. 43APCh. 22.SE - Which, if any, of the following compounds can be...Ch. 22.SE - Prob. 45APCh. 22.SE - Prob. 46APCh. 22.SE - Prob. 47APCh. 22.SE - How might you convert geraniol into either ethyl...Ch. 22.SE - Prob. 49APCh. 22.SE - One way to determine the number of acidic...Ch. 22.SE - Prob. 51APCh. 22.SE - Prob. 52APCh. 22.SE - Prob. 53APCh. 22.SE - Prob. 54APCh. 22.SE - Prob. 55APCh. 22.SE - Prob. 56APCh. 22.SE - All attempts to isolate primary and secondary...Ch. 22.SE - How would you synthesize the following compounds...Ch. 22.SE - Prob. 59APCh. 22.SE - Prob. 60APCh. 22.SE - Prob. 61APCh. 22.SE - Prob. 62APCh. 22.SE - As far back as the 16th century, South American...Ch. 22.SE - The key step in a reported laboratory synthesis of...Ch. 22.SE - Prob. 65AP
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