ORGANIC CHEMISTRY 1 TERM ACCESS
ORGANIC CHEMISTRY 1 TERM ACCESS
3rd Edition
ISBN: 9781119661511
Author: Klein
Publisher: WILEY
Question
Book Icon
Chapter 22.6, Problem 14PTS

(a)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  1

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  2

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  3

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

(b)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  4

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  5

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  6

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

(c)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  7

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  8

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  9

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

(d)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  10

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  11

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  12

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

(e)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  13

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  14

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

ORGANIC CHEMISTRY 1 TERM ACCESS, Chapter 22.6, Problem 14PTS , additional homework tip  15

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

Blurred answer
Students have asked these similar questions
Gramicidin A can adopt more than one structure; NMR spectroscopy has revealed an “end-to-end” dimer form, and x-ray crystallography has revealed an “anti-parallel double- helical” form. Briefly outline and describe an experimentalapproach/strategy to investigate WHICH configuration (“end-to-end dimer” vs “anti-paralleldouble helical”) gramicidin adopts in an actual lipid bilayer.
Don't used hand raiting
CHEM2323 Problem 2-24 Tt O e: ל Predict the product(s) of the following acid/base reactions. Draw curved arrows to show the formation and breaking of bonds. If the bonds needed are not drawn out, you should redraw them. + BF3 (a) (b) HI + (c) OH -BF Problem 2-25 Use curved arrows and a proton (H+) to draw the protonated form of the following Lewis bases. Before starting, add all missing lone pairs. (a) (b) :0: (c) N 1 CHEM2323 PS CH02 Name:

Chapter 22 Solutions

ORGANIC CHEMISTRY 1 TERM ACCESS

Ch. 22.4 - Prob. 10CCCh. 22.4 - Prob. 11CCCh. 22.5 - Prob. 2LTSCh. 22.5 - Prob. 12PTSCh. 22.5 - Prob. 13ATSCh. 22.6 - Prob. 3LTSCh. 22.6 - Prob. 14PTSCh. 22.6 - Prob. 15ATSCh. 22.7 - Prob. 4LTSCh. 22.7 - Prob. 16PTSCh. 22.7 - Prob. 17PTSCh. 22.7 - Prob. 18PTSCh. 22.7 - Prob. 19ATSCh. 22.8 - Prob. 20CCCh. 22.8 - Prob. 21CCCh. 22.8 - Prob. 22CCCh. 22.9 - Prob. 5LTSCh. 22.9 - Prob. 23PTSCh. 22.9 - Prob. 24ATSCh. 22.10 - Prob. 25CCCh. 22.11 - Prob. 26CCCh. 22.11 - Prob. 6LTSCh. 22.11 - Prob. 27PTSCh. 22.11 - Prob. 28ATSCh. 22.12 - Prob. 29CCCh. 22.12 - Prob. 30CCCh. 22.13 - Prob. 31CCCh. 22.13 - Prob. 32CCCh. 22 - Prob. 33PPCh. 22 - Prob. 34PPCh. 22 - Prob. 35PPCh. 22 - Prob. 36PPCh. 22 - Prob. 37PPCh. 22 - Prob. 38PPCh. 22 - Prob. 39PPCh. 22 - Prob. 40PPCh. 22 - Prob. 41PPCh. 22 - Prob. 42PPCh. 22 - Prob. 43PPCh. 22 - Prob. 44PPCh. 22 - Prob. 45PPCh. 22 - Prob. 46PPCh. 22 - Prob. 47PPCh. 22 - Prob. 48PPCh. 22 - Prob. 49PPCh. 22 - Prob. 50PPCh. 22 - Prob. 51PPCh. 22 - Prob. 52PPCh. 22 - Prob. 53PPCh. 22 - Prob. 54PPCh. 22 - Prob. 55PPCh. 22 - Prob. 56PPCh. 22 - Prob. 57PPCh. 22 - Prob. 58PPCh. 22 - Prob. 59PPCh. 22 - Prob. 60PPCh. 22 - Prob. 61PPCh. 22 - Prob. 62PPCh. 22 - Prob. 63PPCh. 22 - Prob. 64PPCh. 22 - Prob. 65PPCh. 22 - Prob. 66PPCh. 22 - Prob. 67PPCh. 22 - Prob. 68PPCh. 22 - Prob. 69PPCh. 22 - Prob. 70PPCh. 22 - Prob. 71PPCh. 22 - Prob. 72PPCh. 22 - Prob. 73IPCh. 22 - Prob. 74IPCh. 22 - Prob. 75IPCh. 22 - Prob. 76IPCh. 22 - Prob. 77IPCh. 22 - Prob. 78IPCh. 22 - Prob. 79IPCh. 22 - Prob. 80IPCh. 22 - Prob. 81IPCh. 22 - Prob. 82IPCh. 22 - Prob. 83IPCh. 22 - Prob. 84IPCh. 22 - Prob. 85IPCh. 22 - Prob. 86IPCh. 22 - Prob. 87IPCh. 22 - Prob. 88IPCh. 22 - Prob. 89IPCh. 22 - Prob. 90IPCh. 22 - Prob. 91IPCh. 22 - Prob. 92IPCh. 22 - Prob. 93IPCh. 22 - Prob. 94IPCh. 22 - Prob. 95IPCh. 22 - Prob. 96CPCh. 22 - Prob. 97CPCh. 22 - Prob. 98CPCh. 22 - Prob. 99CP
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY