Chapter 22, Problem 94A

To determine

Energy transformed by resistor.

Answer to Problem 94A

  $E=2.16\times {10}^4\text{J}$

Explanation of Solution

Given:

Resistance of resistor, $R=50\Omega$

Current, $I=3\text{A}$

Time, $t=5\text{min}=300\text{s}$

Formula Used:

The energy power relation is,

  $E=Pt$

Where, $E$ is energy, $P$ is electric power and $t$ is time

And the power of resistor is given as,

  $P=I^{2}R$

Where, P is power, $R$ is resistance of resistor and $I$ is current through resistor.

Calculation:

From the above relations, the energy transformed is

  $Q=E=Pt=I^{2}Rt$

So, on substituting the values

  $\begin{array}{c}E={1.2}^2\times 50\times 300\\ =2.16\times {10}^4\text{J}\end{array}$

Conclusion:

Therefore, the energy transformed by resistor is $E=2.16\times {10}^4\text{J}$