Chapter 22.1, Problem 15PP

To determine

Voltage of the source.

Answer to Problem 15PP

  $V=121.6\text{V}$

Explanation of Solution

Given:

Operating resistance of motor, $R=32\Omega$

Current through motor, $I=3.8\text{A}$

Formula Used:

Ohm’s law is given as,

  $V=IR$

Where, $V$ is applied voltage, $I$ is current and $R$ is resistance.

Calculation:

On substituting the values in above relation,

  $\begin{array}{c}V=3.8\times 32\\ V=121.6\text{V}\end{array}$

Conclusion:

Therefore, the voltage of the source is $V=121.6\text{V}$ .