Chapter 22, Problem 65A

(a)

To determine

To calculate: the resistance.

Explanation of Solution

Given:

The range of voltage is 0.00 V − 10.0 V.

Calculation:

Replace $V$ and $I$ with measurements in the table and find the corresponding resistance as shown below:

Voltage, V	Current , I	Resistance, $R=\frac{V}{I}$
2	0.0140	143
4	0.0270	148
6	0.0400	150
8	0.0520	154
10	0.0630	159
-2.0	-0.0140	143
-4.0	-0.0280	143
-6.0	-0.0390	154
-8.0	-0.0510	157
-10.0	-0.0620	161

Conclusion:

Hence, all the values of resistance are evaluated.

(b)

To determine

To draw: the graph between $I$ and $V$.

Explanation of Solution

Given:

The range of voltage is 0.00 V − 10.0 V.

Table found in part (a) is attached below:

Voltage, V	Current , I	Resistance, $R=\frac{V}{I}$
2	0.0140	143
4	0.0270	148
6	0.0400	150
8	0.0520	154
10	0.0630	159
-2.0	-0.0140	143
-4.0	-0.0280	143
-6.0	-0.0390	154
-8.0	-0.0510	157
-10.0	-0.0620	161

Calculation:

Graph between $I$ vs. $V$ is shown below:

  

Conclusion:

Hence, the graph is shown.

(c)

To determine

whether the nichrome wire obey Ohm’s law or not.

Explanation of Solution

Given:

The range of voltage is 0.00 V − 10.0 V.

Table found in part (a) is attached below:

Voltage, V	Current , I	Resistance, $R=\frac{V}{I}$
2	0.0140	143
4	0.0270	148
6	0.0400	150
8	0.0520	154
10	0.0630	159
-2.0	-0.0140	143
-4.0	-0.0280	143
-6.0	-0.0390	154
-8.0	-0.0510	157
-10.0	-0.0620	161

Calculation:

The ohm’s law holds for the device having constant resistance independent of the potential difference.

It is to note that for different voltage the resistance of the nichrome wire is different. This means, that nichrome wire doesn’t obey ohms law.

The resistance is 143 $\Omega$ for the voltage from -2.00 V to -4.00 V.

Conclusion:

Hence, the ohm’s law holds for the voltage range of -2.00 V to -4.00 V.