
Concept explainers
To explain: the reason why the resistance is equal to the voltage divided by current.

Explanation of Solution
Introduction:
The resistance offered by an electrical component is the ability to oppose the flow of electrons through the components. Higher the resistance of electrical components, slower is the number of electrons to flow through the component and lesser would be the current flow.
The amount of current flowing in the circuit not only depends on the type of materials it also depends on the applied voltage. The current flowing through the electrical component is directly proportional to the potential difference.
The parameter that remains constant is the resistance of the electrical component and the constant for the dependency of current and voltage is the resistance.
The current through the resistance is directly proportional to the applied potential difference. That is,
Upon removing the proportionality and applying a constant, then the equation becomes the relation between current, voltage, and resistance. That is,
Here,
Rearrange the expression (2) for the resistance,
The above equation of resistance depends on the applied potential difference and current through the electrical component.
The unit of resistance is expressed in
Chapter 22 Solutions
Glencoe Physics: Principles and Problems, Student Edition
Additional Science Textbook Solutions
Human Physiology: An Integrated Approach (8th Edition)
Genetic Analysis: An Integrated Approach (3rd Edition)
Cosmic Perspective Fundamentals
College Physics: A Strategic Approach (3rd Edition)
Campbell Biology (11th Edition)
Introductory Chemistry (6th Edition)
- A particle with a charge of − 5.20 nC is moving in a uniform magnetic field of (B→=−( 1.22 T )k^. The magnetic force on the particle is measured to be(F→=−( 3.50×10−7 N )i^+( 7.60×10−7 N )j^. Calculate the scalar product v→F→. Work the problem out symbolically first, then plug in numbers after you've simplified the symbolic expression.arrow_forwardNeed help wity equilibrium qestionarrow_forwardneed answer asap please thanks youarrow_forward
- A man slides two boxes up a slope. The two boxes A and B have a mass of 75 kg and 50 kg, respectively. (a) Draw the free body diagram (FBD) of the two crates. (b) Determine the tension in the cable that the man must exert to cause imminent movement from rest of the two boxes. Static friction coefficient USA = 0.25 HSB = 0.35 Kinetic friction coefficient HkA = 0.20 HkB = 0.25 M₁ = 75 kg MB = 50 kg P 35° Figure 3 B 200arrow_forwardA golf ball is struck with a velocity of 20 m/s at point A as shown below (Figure 4). (a) Determine the distance "d" and the time of flight from A to B; (b) Determine the magnitude and the direction of the speed at which the ball strikes the ground at B. 10° V₁ = 20m/s 35º Figure 4 d Barrow_forwardThe rectangular loop of wire shown in the figure (Figure 1) has a mass of 0.18 g per centimeter of length and is pivoted about side ab on a frictionless axis. The current in the wire is 8.5 A in the direction shown. Find the magnitude of the magnetic field parallel to the y-axis that will cause the loop to swing up until its plane makes an angle of 30.0 ∘ with the yz-plane. Find the direction of the magnetic field parallel to the y-axis that will cause the loop to swing up until its plane makes an angle of 30.0 ∘ with the yz-plane.arrow_forward
- A particle with a charge of − 5.20 nC is moving in a uniform magnetic field of (B→=−( 1.22 T )k^. The magnetic force on the particle is measured to be (F→=−( 3.50×10−7 N )i^+( 7.60×10−7 N )j^. Calculate the y and z component of the velocity of the particle.arrow_forwardneed answer asap please thank youarrow_forward3. a. Determine the potential difference between points A and B. b. Why does point A have a higher potential energy? Q = +1.0 C 3.2 cm 4.8 cm Aarrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON





