
(a)
The rate at which air conditioner removes energy from the laboratory.
(a)

Answer to Problem 70AP
The rate at which air conditioner removes energy from the laboratory is
Explanation of Solution
An air conditioner removes energy from the cold reservoir to heat reservoir. Ideal air conditioner is the one which work in Carnot cycle.
Write the expression for the coefficient of performance of ideal air conditioner.
Here,
Write the expression for the coefficient of performance of practical air refrigerator.
Here,
Write the expression to convert temperature in degree Celsius into Kelvin scale.
Here,
The coefficient of performance of the given air conditioner is
Write the relation between
Conclusion:
The temperature of laboratory is
Substitute
Substitute
Substitute
Substitute
Divide numerator and denominator of right hand side of equation (II) by
It is given that air conditioner emits energy to the outside at the rate of
Substitute
Rearrange above equation to get
Therefore, the rate at which air conditioner removes energy from the laboratory is
(b)
The power required for the input work.
(b)

Answer to Problem 70AP
The power required for the input work is
Explanation of Solution
Write the expression for the work done.
Here,
Divide both sides of the equation by
Conclusion:
Substitute
Therefore, the power required for the input work is
(c)
The change in entropy of the universe produced by the air conditioner in
(c)

Answer to Problem 70AP
The change in entropy of the universe produced by the air conditioner in
Explanation of Solution
The entropy of the working substance does not change, since air conditioner operates in a cycle.
Write the expression for the increase in entropy of the hot reservoir.
Here,
Write the expression for the decrease in entropy of the cold reservoir.
Here,
Write the expression for the change in entropy produced by the air conditioner in
Here,
Use equation (VII) and (VIII) in equation (IX) to get
Divide and multiply
Conclusion:
Substitute
Therefore, the change in entropy of the universe produced by the air conditioner in
(d)
The fractional change in the COP of the air conditioner.
(d)

Answer to Problem 70AP
The fractional change of the COP of the air conditioner is to drop by
Explanation of Solution
It is given that outside temperature is raised to
Use equation (I) to get ideal coefficient of performance and equation (IV) to get actual coefficient of performance.
Use equation (III) to convert temperature in degree Celsius into Kelvin scale.
Write the expression for the fraction al change.
Conclusion:
Substitute
Substitute
Substitute
Initial coefficient of performance of the air conditioner was
Use equation (XII) to calculate fractional change.
Thus, final COP is
Therefore, fractional change is to drop by
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Chapter 22 Solutions
Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
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