It is to be written that the appropriate sequence of equations for each of the given transformation. Concept introduction: The alcohols on reaction with thionyl chloride give alkyl chloride. The nitriles can be prepared by the reaction of alkyl halide with potassium cyanide or sodium cyanide. The cyanide (nitrile) can be reduced to a primary amine by the action of lithium aluminum hydride ( LiAlH 4 ) followed by water. The secondary alcohol on oxidation with strong oxidizing agent chromic acid forms ketone . The cyanohydrin can be prepared by the addition of hydrogen cyanide to carbonyl carbon of aldehyde or ketone. The dehydration of alcohol is the loss of H 2 O molecule to form a corresponding alkene . The H and OH eliminates from the adjacent carbons. The primary amine on reaction with alkyl halide gives secondary amine. The alkyl bromide can be prepared by the reaction of alcohol with phosphorus tribromide ( PBr 3 ) . The aqueous ammonia on reaction with epoxide acts as a nucleophile and attacks at ?? The acetal carbon is the carbon bonded to two alkoxy groups. The primary alcohol on oxidation with pyridinium dichromate ( PDC ) or pyridinium chlorochromate ( PCC ) in dichloromethane gives aldehyde. The cyclic acetal can be hydrolyzed in an acidic condition to form a ketone or aldehyde and corresponding vicinal diol. The reaction of the secondary amine with an aldehyde or ketone followed by dehydration forms an enamine. The enamines on catalytic hydrogenation forms tertiary amine.

Question

Want to see the full answer?

Answer 1

Question

Chapter 22, Problem 42P

Interpretation Introduction

Interpretation:

It is to be written that the appropriate sequence of equations for each of the given transformation.

Concept introduction:

The alcohols on reaction with thionyl chloride give alkyl chloride.

The nitriles can be prepared by the reaction of alkyl halide with potassium cyanide or sodium cyanide.

The cyanide (nitrile) can be reduced to a primary amine by the action of lithium aluminum hydride (LiAlH4) followed by water.

The secondary alcohol on oxidation with strong oxidizing agent chromic acid forms ketone.

The cyanohydrin can be prepared by the addition of hydrogen cyanide to carbonyl carbon of aldehyde or ketone.

The dehydration of alcohol is the loss of H2O molecule to form a corresponding alkene. The H and OH eliminates from the adjacent carbons.

The primary amine on reaction with alkyl halide gives secondary amine.

The alkyl bromide can be prepared by the reaction of alcohol with phosphorus tribromide (PBr3).

The aqueous ammonia on reaction with epoxide acts as a nucleophile and attacks at ??

The acetal carbon is the carbon bonded to two alkoxy groups.

The primary alcohol on oxidation with pyridinium dichromate (PDC) or pyridinium chlorochromate (PCC) in dichloromethane gives aldehyde.

The cyclic acetal can be hydrolyzed in an acidic condition to form a ketone or aldehyde and corresponding vicinal diol.

The reaction of the secondary amine with an aldehyde or ketone followed by dehydration forms an enamine.

The enamines on catalytic hydrogenation forms tertiary amine.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Can the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left? ? starting material target If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area. Be sure you follow the standard ALEKS rules for submitting syntheses. + More... Note for advanced students: you may assume that you are using a large excess of benzene as your starting material. C :0 T Add/Remove step G

The following equations represent the formation of compound MX. What is the AH for the electron affinity of X (g)? X₂ (g) → 2X (g) M (s) → M (g) M (g) M (g) + e- AH = 60 kJ/mol AH = 22 kJ/mol X (g) + e-X (g) M* (g) +X (g) → MX (s) AH = 118 kJ/mol AH = ? AH = -190 kJ/mol AH = -100 kJ/mol a) -80 kJ b) -30 kJ c) -20 kJ d) 20 kJ e) 156 kJ

A covalent bond is the result of the a) b) c) d) e) overlap of two half-filled s orbitals overlap of a half-filled s orbital and a half-filled p orbital overlap of two half-filled p orbitals along their axes parallel overlap of two half-filled parallel p orbitals all of the above