
Concept explainers
22-5 What are the functions of (a) ovalbumin and (b) myosin?

(a)
Interpretation:
The functions of ovalbumin should be explained.
Concept Introduction:
An organic compound derived from two amino acids is known as dipeptide. The amino acids can be same or different. There are different ways by which amino acids can join to form a protein. The order of amino acid decides the type of protein. The bond between two amino acids to form a dipeptide is a peptide bond.
Answer to Problem 22.5P
Ovalbumin is known to be a storage protein.
Explanation of Solution
Ovalbumin is found in egg white, it makes 55% of the total protein. Its function is not known but it is assumed to be a storage protein.

(b)
Interpretation:
The functions of myosin should be explained.
Concept Introduction:
An organic compound derived from two amino acids is known as dipeptide. The amino acids can be same or different. There are different ways by which amino acids can join to form a protein. The order of amino acid decides the type of protein. The bond between two amino acids to form a dipeptide is a peptide bond.
Answer to Problem 22.5P
Myosin plays an important role in the contraction of muscles and processes involved in movement of one substance to other in eukaryotes.
Explanation of Solution
Myosin is ATP- dependent and plays an important role in the contraction of muscle and mobile processes in the cells of eukaryotes.
They are restricted to muscle cells but important for binding of actin, hydrolysis of ATP and force transduction.
There are myosin isoforms present in all the eukaryotic cells and they have specialized functions depending on the type of muscles they are present in.
Want to see more full solutions like this?
Chapter 22 Solutions
Introduction to General, Organic and Biochemistry
- Which of the following is the most acidic transition metal cation? Group of answer choices Fe3+ Sc3+ Mn4+ Zn2+arrow_forwardBased on the thermodynamics of acetic acid dissociation discussed in Lecture 2-5, what can you conclude about the standard enthalpy change (ΔHo) of acid dissociation for HCl? Group of answer choices You cannot arrive at any of the other three conclusions It is a positive value It is more negative than −0.4 kJ/mol It equals −0.4 kJ/molarrow_forwardPLEASE HELP URGENT!arrow_forward
- Draw the skeletal structure corresponding to the following IUPAC name: 7-isopropyl-3-methyldecanearrow_forwardWhich of the following oxyacids is the weakest? Group of answer choices H2SeO3 Si(OH)4 H2SO4 H3PO4arrow_forwardAdd conditions above and below the arrow that turn the reactant below into the product below in a single transformation. + More... If you need to write reagents above and below the arrow that have complex hydrocarbon groups in them, there is a set of standard abbreviations you can use. More... T H,N NC Datarrow_forward
- Indicate the order of basicity of primary, secondary and tertiary amines.arrow_forward> Classify each of the following molecules as aromatic, antiaromatic, or nonaromatic. Cl Z- N O aromatic O antiaromatic O nonaromatic O aromatic O antiaromatic O nonaromatic O aromatic ○ antiaromatic nonaromaticarrow_forwardPlease help me answer this question. I don't understand how or even if this can happen in a single transformation. Please provide a detailed explanation and a drawing showing how it can happen in a single transformation. Add the necessary reagents and reaction conditions above and below the arrow in this organic reaction. If the products can't be made from the reactant with a single transformation, check the box under the drawing area instead.arrow_forward
- 2) Draw the correct chemical structure (using line-angle drawings / "line structures") from their given IUPAC name: a. (E)-1-chloro-3,4,5-trimethylhex-2-ene b. (Z)-4,5,7-trimethyloct-4-en-2-ol C. (2E,6Z)-4-methylocta-2,6-dienearrow_forwardපිපිම Draw curved arrows to represent the flow of electrons in the reaction on the left Label the reactants on the left as either "Acid" or "Base" (iii) Decide which direction the equilibrium arrows will point in each reaction, based on the given pk, values (a) + H-O H 3-H + (c) H" H + H****H 000 44-00 NH₂ (e) i Дон OH Ө NHarrow_forward3) Label the configuration in each of the following alkenes as E, Z, or N/A (for non-stereogenic centers). 00 E 000 N/A E Br N/A N/A (g) E N/A OH E (b) Oz N/A Br (d) 00 E Z N/A E (f) Oz N/A E (h) Z N/Aarrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningGeneral, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,


