Chapter 22, Problem 22.59AP

Interpretation Introduction

(a)

Interpretation:

The structure of the carbonyl compound ${\text{C}}_{\text{4}}{\text{H}}_{\text{8}}\text{O}$ that gives a precipitate of iodoform with ${\text{I}}_{\text{2}}$ in base is to be drawn.

Concept introduction:

In organic chemistry, the carbonyl compound is a class of functional group which contains a $\text{C}=\text{O}$ group. They are of two types, aldehyde $-\text{CHO}$ and ketone $\text{RC}=\text{OR}$. They are the oxidized product of alcohol. Iodoform test is used to confirm the presence of the carbonyl group. The compounds which contain methyl ketone ${\text{CH}}_{\text{3}}\text{C}=\text{O}$ or secondary alcohol ${\text{CH}}_{\text{3}}\text{CH}\left(\text{OH}\right)$ group gives positive iodoform test.

Interpretation Introduction

(b)

Interpretation:

The structure of the carbonyl compound ${\text{C}}_{\text{4}}{\text{H}}_{\text{8}}\text{O}$ that does not give a precipitate of iodoform with ${\text{I}}_{\text{2}}$ in base is to be drawn.

Concept introduction:

In organic chemistry, the carbonyl compound is a class of functional group which contains a $\text{C}=\text{O}$ group. They are of two types, aldehyde $-\text{CHO}$ and ketone $\text{RC}=\text{OR}$. They are the oxidized product of alcohol. Iodoform test is used to confirm the presence of the carbonyl group. The compounds which contain methyl ketone ${\text{CH}}_{\text{3}}\text{C}=\text{O}$ or secondary alcohol ${\text{CH}}_{\text{3}}\text{CH}\left(\text{OH}\right)$ group gives positive iodoform test.

Interpretation Introduction

(c)

Interpretation:

The structure of the alcohol compound ${\text{C}}_{\text{4}}{\text{H}}_{\text{8}}\text{O}$ that gives a precipitate of iodoform with ${\text{I}}_{\text{2}}$ in base is to be drawn.

Concept introduction:

In organic chemistry, alcohol is a class of functional group which contains a hydroxyl group. They are represented by a formula $\text{R}-\text{OH}$. They are the reduced product of the carbonyl compound. Iodoform test is used to confirm the presence of the carbonyl group. The compounds which contain methyl ketone ${\text{CH}}_{\text{3}}\text{C}=\text{O}$ or secondary alcohol ${\text{CH}}_{\text{3}}\text{CH}\left(\text{OH}\right)$ group gives positive iodoform test.