(a) Interpretation: Each binary hydride should be identified as ionic, covalent or interstitial. Concept introduction: The location of each element in the periodic table determines the formula of the hydride it forms. Alkali metals form ionic hydrides and have the formula AH . Transition elements form interstitial hydrides and have no definite stoichiometric formula, AH x . Covalent hydrides are formed by nonmetals and the formula depends on their group in periodic table.
(a) Interpretation: Each binary hydride should be identified as ionic, covalent or interstitial. Concept introduction: The location of each element in the periodic table determines the formula of the hydride it forms. Alkali metals form ionic hydrides and have the formula AH . Transition elements form interstitial hydrides and have no definite stoichiometric formula, AH x . Covalent hydrides are formed by nonmetals and the formula depends on their group in periodic table.
Solution Summary: The author explains that each binary hydride should be identified as ionic, covalent or interstitial.
Definition Definition Elements containing partially filled d-subshell in their ground state configuration. Elements in the d-block of the periodic table receive the last or valence electron in the d-orbital. The groups from IIIB to VIIIB and IB to IIB comprise the d-block elements.
Chapter 22, Problem 22.21CP
Interpretation Introduction
(a)
Interpretation:
Each binary hydride should be identified as ionic, covalent or interstitial.
Concept introduction:
The location of each element in the periodic table determines the formula of the hydride it forms. Alkali metals form ionic hydrides and have the formula AH. Transition elements form interstitial hydrides and have no definite stoichiometric formula, AHx. Covalent hydrides are formed by nonmetals and the formula depends on their group in periodic table.
Interpretation Introduction
(b)
Interpretation:
The oxidation state of hydrogen and the other element in compounds (1), (2) and (3) should be determined.
Concept introduction:
In ionic hydrides, hydrogen is in oxidation state and in other types of hydride, hydrogen is in +1 oxidation state.
For the titration of a divalent metal ion (M2+) with EDTA, the stoichiometry of the reaction is typically:
1:1 (one mole of EDTA per mole of metal ion)
2:1 (two moles of EDTA per mole of metal ion)
1:2 (one mole of EDTA per two moles of metal ion)
None of the above
Please help me solve this reaction.
Indicate the products obtained by mixing 2,2-dimethylpropanal with acetaldehyde and sodium ethoxide in ethanol.
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