Which element has more nonmetallic character:Cl or Sb?
Interpretation:
The element which is more non-metallic from Cl and Sb is to be determined.
Concept introduction:
The non-metallic character of a given element can be defined as its tendency to accept electrons during a given chemical reaction.
Answer to Problem 22.1P
Cl will be more non-metallic in nature as compared to Sb.
Explanation of Solution
The non-metallic character of a given element is related to its tendency to accept electrons.
The electron affinity of a given atom can be defined as the amount of energy which is released when an electron is added to an atom in neutral state and is present in its gaseous form.
The electron affinity is said to increase as one moves from left to right across the period due to decrease in the atomic radius while the electron affinity decreases as one moves down the group due to increase in the atomic radius.
Chlorine is present in the 3rd period and 17th group of the periodic table while antimony belongs to the 5th period and the 15th group of the modern periodic table.
Therefore, the electron affinity of chlorine will be more than that of Antimony. Hence, the tendency to accept electrons will be more in case of chlorine than antimony. Thus, chlorine is more non-metallic in nature than antimony.
The electron affinity of a given atom can be defined as the amount of energy which is released when an electron is added to an atom in neutral state and is present in its gaseous form.
Want to see more full solutions like this?
Chapter 22 Solutions
LCPO CHEMISTRY W/MODIFIED MASTERING
- 4. Propose a synthesis of the target molecules from the respective starting materials. a) b) LUCH C Br OHarrow_forwardThe following mechanism for the gas phase reaction of H2 and ICI that is consistent with the observed rate law is: step 1 step 2 slow: H2(g) +ICI(g) → HCl(g) + HI(g) fast: ICI(g) + HI(g) → HCl(g) + |2(g) (1) What is the equation for the overall reaction? Use the smallest integer coefficients possible. If a box is not needed, leave it blank. + → + (2) Which species acts as a catalyst? Enter formula. If none, leave box blank: (3) Which species acts as a reaction intermediate? Enter formula. If none, leave box blank: (4) Complete the rate law for the overall reaction that is consistent with this mechanism. (Use the form k[A][B]"..., where '1' is understood (so don't write it) for m, n etc.) Rate =arrow_forwardPlease correct answer and don't use hand rating and don't use Ai solutionarrow_forward
- 1. For each of the following statements, indicate whether they are true of false. ⚫ the terms primary, secondary and tertiary have different meanings when applied to amines than they do when applied to alcohols. • a tertiary amine is one that is bonded to a tertiary carbon atom (one with three C atoms bonded to it). • simple five-membered heteroaromatic compounds (e.g. pyrrole) are typically more electron rich than benzene. ⚫ simple six-membered heteroaromatic compounds (e.g. pyridine) are typically more electron rich than benzene. • pyrrole is very weakly basic because protonation anywhere on the ring disrupts the aromaticity. • thiophene is more reactive than benzene toward electrophilic aromatic substitution. • pyridine is more reactive than nitrobenzene toward electrophilic aromatic substitution. • the lone pair on the nitrogen atom of pyridine is part of the pi system.arrow_forwardThe following reactions are NOT ordered in the way in which they occur. Reaction 1 PhO-OPh Reaction 2 Ph-O -CH₂ heat 2 *OPh Pho -CH2 Reaction 3 Ph-O ⚫OPh + -CH₂ Reaction 4 Pho Pho + H₂C OPh + CHOPh H₂C -CH₂ Reactions 1 and 3 Reaction 2 O Reaction 3 ○ Reactions 3 and 4 ○ Reactions 1 and 2 Reaction 4 ○ Reaction 1arrow_forwardSelect all possible products from the following reaction: NaOH H₂O a) b) ОН HO O HO HO e) ОН f) O HO g) h) + OHarrow_forward
- 3. Draw diagrams to represent the conjugation in these molecules. Draw two types of diagram: a. Show curly arrows linking at least two different ways of representing the molecule b. Indicate with dotted lines and partial charges (where necessary) the partial double bond (and charge) distribution H₂N* H₂N -NH2arrow_forwardQuestion 2 of 25 point Question Attempt 3 of Ulimited Draw the structure for 3-chloro-4-ethylheptane. Part 2 of 3 Click and drag to start drawing a structure. Draw the structure for 1-chloro-4-ethyl-3-lodooctane. Click and drag to start drawing a structure. X G X B c Part 3 of 30 Draw the structure for (R)-2-chlorobutane. Include the stereochemistry at all stereogenic centers. Check Click and drag to start drawing a structure. G X A 。 MacBook Pro G P Save For Later Submit Assignment Privacyarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- In a silicon and aluminum alloy, with 12.6% silicon, what are the approximate percentages of the phases present in the constituent that is formed at the end of solidification? Temperature (°C) 1500 1000 L B+L 1415- α+L 577' 500 1.65 12.6 99.83 α+B B 0 Al 20 40 60 Weight percent silicon 80 Siarrow_forwardPlease correct answer and don't used hand raitingarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning