(a)
Interpretation:
The electron dot structure and the geometrical structure of
Concept introduction:
VSEPR theory stands as Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pairs or lone pairs present in it. According to the VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry. This is because of the repulsion between lone pairs and bond pairs of the central atom of the molecule. The order of repulsion is:
Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
Based on the number of lone pairs and bond pairs, the molecular geometry can be determined with the help of the below table.
| Number of hybridization | Bond pair | Lone pair | Geometry |
| 2 | 2 | 0 | Linear |
| 2 | 1 | 1 | Linear |
| 3 | 3 | 0 | Trigonal planar |
| 3 | 2 | 1 | Bent |
| 4 | 4 | 0 | Tetrahedral |
| 4 | 3 | 1 | Trigonal pyramidal |
| 4 | 2 | 2 | Bent |
| 5 | 5 | 0 | Trigonal bipyramidal |
| 5 | 4 | 1 | See saw |
| 5 | 3 | 2 | T shaped |
| 5 | 2 | 3 | Linear |
| 6 | 6 | 0 | Octahedral |
(b)
Interpretation:
The electron dot structure and the geometrical structure of
Concept introduction:
VSEPR theory stands as Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pairs or lone pairs present in it. According to the VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry. This is because of the repulsion between lone pairs and bond pairs of the central atom of the molecule. The order of repulsion is:
Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
Based on the number of lone pairs and bond pairs, the molecular geometry can be determined with the help of the below table.
| Number of hybridization | Bond pair | Lone pair | Geometry |
| 2 | 2 | 0 | Linear |
| 2 | 1 | 1 | Linear |
| 3 | 3 | 0 | Trigonal planar |
| 3 | 2 | 1 | Bent |
| 4 | 4 | 0 | Tetrahedral |
| 4 | 3 | 1 | Trigonal pyramidal |
| 4 | 2 | 2 | Bent |
| 5 | 5 | 0 | Trigonal bipyramidal |
| 5 | 4 | 1 | See saw |
| 5 | 3 | 2 | T shaped |
| 5 | 2 | 3 | Linear |
| 6 | 6 | 0 | Octahedral |
(c)
Interpretation:
The electron dot structure and the geometrical structure of
Concept introduction:
VSEPR theory stands as Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pairs or lone pairs present in it. According to the VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry. This is because of the repulsion between lone pairs and bond pairs of the central atom of the molecule. The order of repulsion is:
Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
Based on the number of lone pairs and bond pairs, the molecular geometry can be determined with the help of the below table.
| Number of hybridization | Bond pair | Lone pair | Geometry |
| 2 | 2 | 0 | Linear |
| 2 | 1 | 1 | Linear |
| 3 | 3 | 0 | Trigonal planar |
| 3 | 2 | 1 | Bent |
| 4 | 4 | 0 | Tetrahedral |
| 4 | 3 | 1 | Trigonal pyramidal |
| 4 | 2 | 2 | Bent |
| 5 | 5 | 0 | Trigonal bipyramidal |
| 5 | 4 | 1 | See saw |
| 5 | 3 | 2 | T shaped |
| 5 | 2 | 3 | Linear |
| 6 | 6 | 0 | Octahedral |
(d)
Interpretation:
The electron dot structure and the geometrical structure of
Concept introduction:
VSEPR theory stands as Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pairs or lone pairs present in it. According to the VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry. This is because of the repulsion between lone pairs and bond pairs of the central atom of the molecule. The order of repulsion is:
Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
Based on the number of lone pair and bond pair, the molecular geometry can be determined with the help of the below table.
| Number of hybridization | Bond pair | Lone pair | Geometry |
| 2 | 2 | 0 | Linear |
| 2 | 1 | 1 | Linear |
| 3 | 3 | 0 | Trigonal planar |
| 3 | 2 | 1 | Bent |
| 4 | 4 | 0 | Tetrahedral |
| 4 | 3 | 1 | Trigonal pyramidal |
| 4 | 2 | 2 | Bent |
| 5 | 5 | 0 | Trigonal bipyramidal |
| 5 | 4 | 1 | See saw |
| 5 | 3 | 2 | T shaped |
| 5 | 2 | 3 | Linear |
| 6 | 6 | 0 | Octahedral |
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Chapter 22 Solutions
LCPO CHEMISTRY W/MODIFIED MASTERING
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- Use a textbook or other valid source to research the physical and chemical properties of each element listed in Data Table 1 using the following as a guideline: Ductile (able to be deformed without losing toughness) and malleable (able to be hammered or pressed permanently out of shape without breaking or cracking) or not ductile or malleable Good, semi, or poor conductors of electricity and heat High or low melting and boiling points Occur or do not occur uncombined/freely in nature High, intermediate, or low reactivity Loses or gains electrons during reactions or is not reactivearrow_forwardProvide the Physical and Chemical Properties of Elements of the following elements listedarrow_forwardQuestions 4 and 5arrow_forward
- For a titration of 40.00 mL of 0.0500 M oxalic acid H2C2O4 with 0.1000 M KOH, calculate the pH at each of the following volume of KOH used in the titration: 1) before the titration begin;2) 15 mL; 3) 20 mL; 4) 25 mL; 5) 40 mL; 6) 50 mL. Ka1 = 5.90×10^-2, Ka2 = 6.50×10^-5 for oxalic acid.arrow_forwardPredict the major organic product(s), if any, of the following reactions. Assume all reagents are in excess unless otherwise indicated.arrow_forwardPredict the major organic product(s), if any, of the following reactions. Assume all reagents are in excess unless otherwise indicated.arrow_forward
- How many signals would you expect to find in the 1 H NMR spectrum of each given compound? Part 1 of 2 2 Part 2 of 2 HO 5 ☑ Х IIIIII***** §arrow_forwardA carbonyl compound has a molecular ion with a m/z of 86. The mass spectra of this compound also has a base peak with a m/z of 57. Draw the correct structure of this molecule. Drawingarrow_forwardCan you draw this using Lewis dot structures and full structures in the same way they are so that I can better visualize them and then determine resonance?arrow_forward
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