Chapter 22, Problem 22.14P

Interpretation Introduction

(a)

Interpretation:

The expected product formed when given compound reacts with $\text{B}{\text{r}}_{\text{2}}$ in $\text{NaOH}$ is to be stated.

Concept Introduction:

Halogenation of ketone takes place in both acidic and basic medium. Bromine attacks at the $\alpha$ carbon to replace $\alpha$ hydrogen present in the compound. When the given aldehyde or ketone is acetaldehyde or methyl ketone, then tri-halo carbonyl compound is formed as product.

Interpretation Introduction

(b)

Interpretation:

The expected product formed when given compound reacts with $\text{B}{\text{r}}_{\text{2}}$ in $\text{NaOH}$ is to be stated.

Concept Introduction:

Halogenation of ketone takes place in both acidic and basic medium Bromine attacks at the $\alpha$ carbon to replace $\alpha$ hydrogen present in the compound. In the halogenation reaction of ketone, first keto gets converted into enol. Then, halogen gets added to the enol structure to form intermediate which after elimination of $\text{HX}$ forms haloketone.

Interpretation Introduction

(c)

Interpretation:

The expected product formed when given compound reacts with $\text{B}{\text{r}}_{\text{2}}$ in $\text{NaOH}$ is to be stated.

Concept Introduction:

Some of the alcohols also give haloform reaction as they get oxidized into ketone and then react with halogen in basic medium to form carboxylic acid and haloform. The reaction of alocohol first gets oxidized into ketone then reacts with bromine in $\text{NaOH}$ to form carboxylic acid salt and haloform.