(a) Interpretation: The reason of more electronegative nature of oxygen than sulfur should be explained. Concept introduction: The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons. The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Answer 1

Question

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Answer 2

Question

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Answer 3

Question

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Answer 4

Question

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Answer 5

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 6

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 7

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 22 - Which element has more nonmetallic character:Cl or...Ch. 22 - Prob. 22.2A Ch. 22 - Prob. 22.3P Ch. 22 - Prob. 22.4A Ch. 22 - Prob. 22.5P Ch. 22 - Look at the location of elements A, B, C, and Din...Ch. 22 - What are the formula and charge of the silicate...Ch. 22 - Suggest a plausible structure for the silicate...Ch. 22 - Prob. 22.9P Ch. 22 - Write balanced net ionic equations for the...

Solution Summary: The author explains that the group 6A is a combination of non-metal, metalloid and metals.

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Chapter 22 Solutions