(a) Interpretation: The reason of more electronegative nature of oxygen than sulfur should be explained. Concept introduction: The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons. The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Answer 1

Question

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Consider the reaction: 2 A (aq) ⇌ B(aq) Given the following KC values and starting with the initial concentration of A = 4.00 M, complete ICE diagram(s)and find the equilibrium concentrations for A and B.A) KC = 4.00B) KC = 200C) KC = 8.00 x10-3

5) Consider the reaction: Cl2 (g) + F2 (g) ⟷ 2 ClF (g) KP=? The partial pressure of 203 kPa for Cl2 and a partial pressure of 405 kPa for F2. Upon reaching equilibrium, thepartial pressure of ClF is 180 kPa. Calculate the equilibrium concentrations and then find the value for KP.

Don't used hand raiting and don't used Ai solution

Answer 2

Question

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Answer 3

Question

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Answer 4

Question

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Answer 5

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 6

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 7

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 22 - Which element has more nonmetallic character:Cl or...Ch. 22 - Prob. 22.2A Ch. 22 - Prob. 22.3P Ch. 22 - Prob. 22.4A Ch. 22 - Prob. 22.5P Ch. 22 - Look at the location of elements A, B, C, and Din...Ch. 22 - What are the formula and charge of the silicate...Ch. 22 - Suggest a plausible structure for the silicate...Ch. 22 - Prob. 22.9P Ch. 22 - Write balanced net ionic equations for the...

Solution Summary: The author explains that the group 6A is a combination of non-metal, metalloid and metals.

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Chapter 22 Solutions