Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Chapter 22, Problem 21RQ
Why does a TiN-coated tool consume less power than an uncoated HSS under exactly the same cutting conditions?
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During orthogonal cutting of mild steel with a 10° rake angle tool, the chip thickness ratio was obtained as 0.4 .Calaculate the shear angle.
In addition to cutting speed, what other cutting variables are included in the expanded version of the Taylor tool life equation?
An orthogonal cutting operation is being carried out under the following conditions:
depth of cut, to = 0.1 mm, rake angle, a = 10°, Cutting force, Fc =1500 N, and Thrust
force, Ft = 800 N. Calculate the shear force.
Chapter 22 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 22 - For metal-cutting tools, what is the most...Ch. 22 - What is hot hardness compared to hardness?Ch. 22 - Prob. 3RQCh. 22 - Why is impact strength an important property in...Ch. 22 - Cemented carbide tools are made by a powder...Ch. 22 - What are the primary considerations in tool...Ch. 22 - What is the general strategy behind coated tools?Ch. 22 - Prob. 8RQCh. 22 - How is a CBN tool manufactured?Ch. 22 - Prob. 10RQ
Ch. 22 - Prob. 11RQCh. 22 - Discuss the constraints in the selection of a...Ch. 22 - What does cemented mean in the manufacture of...Ch. 22 - What advantage do ground carbide inserts have over...Ch. 22 - What is a chip groove?Ch. 22 - What is the DCL?Ch. 22 - Suppose you made four beams out of carbide, HSS,...Ch. 22 - Multiple coats or layers are put on the carbide...Ch. 22 - What tool material would you recommend for...Ch. 22 - What makes the process that makes TiC coatings for...Ch. 22 - Why does a TiN-coated tool consume less power than...Ch. 22 - For what work material are CBN tools more commonly...Ch. 22 - Why is CBN better for machining steel than...Ch. 22 - What is the typical coefficient of variation for...Ch. 22 - What is meant by the statement Tool life is a...Ch. 22 - The typical value of a coefficient of variation in...Ch. 22 - Machinability is defined in many ways. Explain how...Ch. 22 - What are the chief functions of cutting fluids?Ch. 22 - Prob. 29RQCh. 22 - Why is the PVD process used to coat HSS tools?Ch. 22 - Why is there no universal cutting tool material?Ch. 22 - What is an 18-4-1 HSS composed of?Ch. 22 - Over the years, tool materials have been developed...Ch. 22 - Why is the rigidity of the machine tool an...Ch. 22 - Explain how it can be that the tool wears when it...Ch. 22 - What is a honed edge on a cutting tool and why is...Ch. 22 - Suppose you have a turning operation using a tool...Ch. 22 - A 2 in.-diameter bar of steel was turned at 284...Ch. 22 - Prob. 3PCh. 22 - The following data have been obtained for...Ch. 22 - In the insert is set with a 0 side cutting-edge...Ch. 22 - Prob. 6PCh. 22 - Here is a single point tool. Identify angles A...Ch. 22 - Figure 22.B gives data for cutting speed and tool...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- What are the functions of cutting fluid?arrow_forwardChoose TWO (2) types of cutting processes that are suitable for cutting thick materials (>20mm thick plate).arrow_forwardQuestion 3. a. A cast iron component for motorcycle is to be turned with machine settings of feed = 0.22 mm/rev, and speed = 100 m/min. The cutting tool is a carbide tip with a nose radius of 1.2 mm and the rai for the material at a cutting speed of 100 m/min is 1.3. Calculate the surface roughness for this cut. [6 marks]arrow_forward
- 8 - Orthogonal cutting is performed on a metal whose mass specific heat = 1.0 J/g-C, density 2.9 g/cm3, and thermal diffusivity = 0.8 cm2/s. The cutting speed is 4.5 m/s, uncut chip thickness (feed) is 0.25 mm, and width of cut (depth) is 2.2 mm. The cutting force is measured at 1170 N. Using Cook's equation, determine the cutting temperature. a) 417.09 b) O 707.60 C) 528.03 d) O 316.82 Boş bırakarrow_forwardIdentify the forces involved in a cutting operation. which of these forces contributes to the power required?arrow_forwardIn orthogonal turning of low carbon steel pipe with principal cutting edge angle of 90°, the main cutting force is 1000 N and the feed force is 800 N. The shear angle is 25° and orthogonal rake angle is zero Employing Merchant's theory, what is the ratio of friction force to normal force acting on the cutting tool?arrow_forward
- 3) The following data are available from orthogonal cutting experiment, Depth of cut t, = 0.13 mm, width of cut w = 2.5 mm, rake angle a = -5°, cutting speed v = 2 m/s, Chip thickness, t= 0.23 mm, cutting force, F. = 430 N, thrust force, F = 280 N. Determine the following: Shear angle Friction Coefficient u (using F= µ N) Shear Stress t,S Shear strain y on the shear plane. Power required to perform the operation. Gross power required if the efficiency of the machine is 85%. Specific Energy, Utarrow_forwardIn an orthogonal cutting test with a bar of 75 mm diameter is reduced to 73 mm by using a HSS tool with arake angle = 10o, following observations were made: length of the chip, lc = 69.44 mm, cutting ratio r =0.3, the horizontal component of the cutting force, FH = 1450 N, and the vertical component of the cuttingforce, FV = 850 N. The various parameters recorded in this cutting operation are: depth of cut, d = 2 mm;feed rate, f = 0.3 mm/rev, cutting speed, V = 60 m/min. Using Merchant’s theory calculate the following:1) Friction force along rake face2) Normal force acting on rake face3) Shear force along the shear plane4) Normal force acting on shear plane5) The percentage error in shear angle predicted by Merchant’s theory6) Shear velocity7) Chip velocity8) Total work done9) The shear work proportion out of the total work done10) The friction work proportion out of the total work donearrow_forwardNote: Read the question carefully and give me right solutions according to the question. In orthogonal cutting of steel tube of 150 mm diameter and 2 mm thick, the cutting force was 130 kg and feed force was 35 kg for chip thickness of 0.3mm. The orthogonal cut was taken at 60 meter per minute with a feed of 0.14 mm/rev. If the back rack angle of the cutting tool was - 8 o (minus 8 degree), then calculate the shear strain and strain energy per unit volume.arrow_forward
- The outside diameter of a cylinder made of steel is to be turned. The starting diameter is 120 mm and the length is 1400 mm. The feed is 0.3 mm/rev and the depth of cut is 2.5mm. The cut will be made with a cemented carbide cutting tool whose Taylor tool life parameters are: n= 0.33 and C=500. Units for the Taylor equation are min for tool life and m/min for cutting speed. Compute the cutting speed that will allow the tool life to be just equal to the cutting time required to complete this turning operation.arrow_forward2. How does the built-up-edge (BUE) form, and what are the influences of BUE on metal cutting?arrow_forward(11,00 Puanlar) 39 An orthogonal cutting operation is being carried out under the following conditions: t0=0,38 mm, tc=0,65 mm, width of the cut= 2.5 mm, V= 3.5 m/s, rake angle=D 6 , Fc= 515 N, and Ft= 210 N. Calculate the percentage of the total energy that is dissipated in the shear plane. The power input in cutting= F.V Power for shearing=F,V, t I'c tan ø = Iccos a tc 1-re sin a cin -1-arrow_forward
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