To write the balanced chemical equation for the formation of N a B r . Concept Introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds. Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability. M → M n + + n e − Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below. X + n e − → X n − The metals of group IA form + 1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is + 1 . Similarly, group IIA elements form + 2 ions by losing two electrons and have an oxidation number of + 2 . The non-metal gains these electrons to form anions with − 1 and − 2 charge. The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side. For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

Question

Want to see the full answer?

Answer 1

Question

Chapter 21.2, Problem 1CYU

(a)

Interpretation Introduction

Interpretation: To write the balanced chemical equation for the formation of NaBr.

Concept Introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(b)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of CaSe should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group 1A form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(c)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of PbO should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group 1A elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(d)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of AlCl3 should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

How many signals do you expect in the H NMR spectrum for this molecule? Br Br Write the answer below. Also, in each of the drawing areas below is a copy of the molecule, with Hs shown. In each copy, one of the H atoms is colored red. Highlight in red all other H atoms that would contribute to the same signal as the H already highlighted red. Note for advanced students: In this question, any multiplet is counted as one signal. Number of signals in the 'H NMR spectrum. For the molecule in the top drawing area, highlight in red any other H atoms that will contribute to the same signal as the H atom already highlighted red. If no other H atoms will contribute, check the box at right. No additional Hs to color in top molecule For the molecule in the bottom drawing area, highlight in red any other H atoms that will contribute to the same signal as the H atom already highlighted red. If no other H atoms will contribute, check the box at right. No additional Hs to color in bottom molecule

In the drawing area below, draw the major products of this organic reaction: 1. NaOH ? 2. CH3Br If there are no major products, because nothing much will happen to the reactant under these reaction conditions, check the box under the drawing area instead. No reaction. Click and drag to start drawing a structure. ☐ : A ค

Predict the major products of the following organic reaction: NC Δ ? Some important Notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to draw bonds carefully to show important geometric relationships between substituents. Note: if your answer contains a complicated ring structure, you must use one of the molecular fragment stamps (available in the menu at right) to enter the ring structure. You can add any substituents using the pencil tool in the usual way. Click and drag to start drawing a structure. Х а

Answer 2

Question

Chapter 21.2, Problem 1CYU

(a)

Interpretation Introduction

Interpretation: To write the balanced chemical equation for the formation of NaBr.

Concept Introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(b)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of CaSe should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group 1A form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(c)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of PbO should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group 1A elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(d)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of AlCl3 should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 21.2, Problem 1CYU

(a)

Interpretation Introduction

Interpretation: To write the balanced chemical equation for the formation of NaBr.

Concept Introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(b)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of CaSe should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group 1A form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(c)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of PbO should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group 1A elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(d)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of AlCl3 should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 21.2, Problem 1CYU

(a)

Interpretation Introduction

Interpretation: To write the balanced chemical equation for the formation of NaBr.

Concept Introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(b)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of CaSe should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group 1A form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(c)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of PbO should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group 1A elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(d)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of AlCl3 should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 21.2, Problem 1CYU

(a)

Interpretation Introduction

Interpretation: To write the balanced chemical equation for the formation of NaBr.

Concept Introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(b)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of CaSe should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group 1A form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(c)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of PbO should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group 1A elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

(d)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of AlCl3 should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

Answer 6

Chapter 21.2, Problem 1CYU

(a)

Interpretation Introduction

Interpretation: To write the balanced chemical equation for the formation of NaBr.

Concept Introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

Answer 7

Chapter 21.2, Problem 1CYU

(a)

Interpretation Introduction

Interpretation: To write the balanced chemical equation for the formation of NaBr.

Concept Introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

Answer 8

(b)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of CaSe should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group 1A form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

Answer 9

(b)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of CaSe should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group 1A form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

Answer 10

(c)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of PbO should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group 1A elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

Answer 11

(c)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of PbO should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group 1A elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

Answer 12

(d)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of AlCl3 should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

Answer 13

(d)

Interpretation Introduction

Interpretation: The balanced chemical equation for the formation of AlCl3 should be written.

Concept introduction: Main group elements are categorised as s-block and p-block elements. The s-block elements includes metals belonging to group 1 and group 2 and elements from group 13 to 18 are referred to as p-block elements. The reaction of themetals of main group elements with the non metals forms ionic compounds.

Ionic compounds are formed by the loss of electrons from the metal which are gained by the non metals. The metal gets positively charge and the non metal attains a negative charge thus forming cations and anions respectively. They do so to attain a noble gas configuration or to attain stability.

M→Mn++ne−

Here, by losing electrons metal M achieve the noble gas configuration. These electrons are gained by the non-metals X as shown below.

X+ne−→Xn−

The metals of group IA form +1 ions because the highest oxidation number is always equal to the group number of that element. Thus, the charge on group IA elements is +1. Similarly, group IIA elements form +2 ions by losing two electrons and have an oxidation number of +2. The non-metal gains these electrons to form anions with −1 and −2 charge.

The stoichometric coefficents are multiplied with the compounds or species in the chemical equation to have equal number of atoms on both side of the equation. The equation is known as a balanced chemical equation if there are equal number of atoms of each element in both the product and reactant side.

For the naming of an ionic compound, the cation is always named first followed by the anion and the anion ends with the “-ide”.

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 17

Ch. 21.2 - Prob. 1CYU Ch. 21.2 - Write the formula for each of the following (a)...Ch. 21.2 - Prob. 3CYU Ch. 21.2 - Prob. 4CYU Ch. 21.4 - Prob. 3RC Ch. 21.5 - Prob. 1Q Ch. 21.5 - Prob. 2Q Ch. 21.8 - Prob. 1Q Ch. 21.8 - Prob. 2Q Ch. 21.8 - Prob. 3Q

Solution Summary: The author explains the balanced chemical equation for the formation of NaBr.

Want to see the full answer?

Chapter 21 Solutions