Chemistry & Chemical Reactivity, Hybrid Edition (with OWLv2 24-Months Printed Access Card)
Chemistry & Chemical Reactivity, Hybrid Edition (with OWLv2 24-Months Printed Access Card)
9th Edition
ISBN: 9781285462530
Author: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher: Cengage Learning
Question
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Chapter 21, Problem 15PS

(a)

Interpretation Introduction

Interpretation: The balanced chemical equation should be written for the reaction of hydrogen gas with oxygen.

Concept introduction: The reaction of elements with hydrogen produces either ionic metal hydrides or molecular compounds.  The reaction of hydrogen with metals produces ionic metal hydrides. The electronegativity of hydrogen is more than metals and hence, metals bear positive charge and hydrogen has a negative charge. Thus, the oxidation number of hydrogen in ionic metal hydrides is 1. The reaction of non-metals with hydrogen produces molecular compounds. In general, non-metals are more electronegative than hydrogen and hence, hydrogen bears positive charge and non-metals are negatively charged in molecular compounds. Thus, the oxidation number of hydrogen in molecular compounds is +1.

The oxidation number of metals in ionic hydrides and non-metals in molecular compounds are according to the group number and valence electron configuration of these elements.

So, hydrogen reacts with both metals and non-metals to produce hydrides of corresponding elements. However, the elements belonging to the noble gas family have very low chemical reactivity and therefore do not combine with hydrogen.

(b)

Interpretation Introduction

Interpretation: The balanced chemical equation should be written for the reaction of hydrogen gas with chlorine.

Concept introduction: The reaction of elements with hydrogen produces either ionic metal hydrides or molecular compounds.  The reaction of hydrogen with metals produces ionic metal hydrides. The electronegativity of hydrogen is more than metals and hence, metals bear positive charge and hydrogen has a negative charge. Thus, the oxidation number of hydrogen in ionic metal hydrides is 1. The reaction of non-metals with hydrogen produces molecular compounds. In general, non-metals are more electronegative than hydrogen and hence, hydrogen bears positive charge and non-metals are negatively charged in molecular compounds. Thus, the oxidation number of hydrogen in molecular compounds is +1.

The oxidation number of metals in ionic hydrides and non-metals in molecular compounds are according to the group number and valence electron configuration of these elements.

So, hydrogen reacts with both metals and non-metals to produce hydrides of corresponding elements. However, the elements belonging to the noble gas family have very low chemical reactivity and therefore do not combine with hydrogen.

(c)

Interpretation Introduction

Interpretation: The balanced chemical equation should be written for the reaction of hydrogen gas with nitrogen.

Concept introduction: The reaction of elements with hydrogen produces either ionic metal hydrides or molecular compounds.  The reaction of hydrogen with metals produces ionic metal hydrides. The electronegativity of hydrogen is more than metals and hence, metals bear positive charge and hydrogen has a negative charge. Thus, the oxidation number of hydrogen in ionic metal hydrides is 1. The reaction of non-metals with hydrogen produces molecular compounds. In general, non-metals are more electronegative than hydrogen and hence, hydrogen bears positive charge and non-metals are negatively charged in molecular compounds. Thus, the oxidation number of hydrogen in molecular compounds is +1.

The oxidation number of metals in ionic hydrides and non-metals in molecular compounds are according to the group number and valence electron configuration of these elements.

So, hydrogen reacts with both metals and non-metals to produce hydrides of corresponding elements. However, the elements belonging to the noble gas family have very low chemical reactivity and therefore do not combine with hydrogen.

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Chapter 21 Solutions

Chemistry & Chemical Reactivity, Hybrid Edition (with OWLv2 24-Months Printed Access Card)

Ch. 21.8 - Prob. 4QCh. 21.8 - Prob. 3RCCh. 21.11 - Prob. 1QCh. 21.11 - Prob. 2QCh. 21 - Give examples of two basic oxides. Write equations...Ch. 21 - Prob. 2PSCh. 21 - Prob. 3PSCh. 21 - Prob. 4PSCh. 21 - Prob. 5PSCh. 21 - Prob. 6PSCh. 21 - For the product of the reaction you selected in...Ch. 21 - For the product of the reaction you selected in...Ch. 21 - Prob. 9PSCh. 21 - Prob. 10PSCh. 21 - Place the following oxides in order of increasing...Ch. 21 - Place the following oxides in order of increasing...Ch. 21 - Prob. 13PSCh. 21 - Prob. 14PSCh. 21 - Prob. 15PSCh. 21 - Prob. 16PSCh. 21 - Prob. 17PSCh. 21 - Prob. 18PSCh. 21 - Prob. 19PSCh. 21 - Prob. 20PSCh. 21 - Prob. 21PSCh. 21 - Write balanced equations for the reaction of...Ch. 21 - Prob. 23PSCh. 21 - (a) Write equations for the half-reactions that...Ch. 21 - When magnesium bums in air, it forms both an oxide...Ch. 21 - Prob. 26PSCh. 21 - Prob. 27PSCh. 21 - Prob. 28PSCh. 21 - Calcium oxide, CaO, is used to remove SO2 from...Ch. 21 - Prob. 30PSCh. 21 - Prob. 31PSCh. 21 - The boron trihalides (except BF3) hydrolyze...Ch. 21 - When boron hydrides burn in air, the reactions are...Ch. 21 - Prob. 34PSCh. 21 - Write balanced equations for the reactions of...Ch. 21 - Prob. 36PSCh. 21 - Prob. 37PSCh. 21 - Alumina, Al2O3, is amphoteric. Among examples of...Ch. 21 - Prob. 39PSCh. 21 - Prob. 40PSCh. 21 - Describe the structure of pyroxenes (see page...Ch. 21 - Describe how ultrapure silicon can be produced...Ch. 21 - Prob. 43PSCh. 21 - Prob. 44PSCh. 21 - Prob. 45PSCh. 21 - Prob. 46PSCh. 21 - Prob. 47PSCh. 21 - The overall reaction involved in the industrial...Ch. 21 - Prob. 49PSCh. 21 - Prob. 50PSCh. 21 - Prob. 51PSCh. 21 - Prob. 52PSCh. 21 - Prob. 53PSCh. 21 - Prob. 54PSCh. 21 - Prob. 55PSCh. 21 - Sulfur forms a range of compounds with fluorine....Ch. 21 - The halogen oxides and oxoanions are good...Ch. 21 - Prob. 58PSCh. 21 - Bromine is obtained from brine wells. The process...Ch. 21 - Prob. 60PSCh. 21 - Prob. 61PSCh. 21 - Halogens combine with one another to produce...Ch. 21 - The standard enthalpy of formation of XeF4 is 218...Ch. 21 - Draw the Lewis electron dot structure for XeO3F2....Ch. 21 - Prob. 65PSCh. 21 - Prob. 66PSCh. 21 - Prob. 67GQCh. 21 - Prob. 68GQCh. 21 - Consider the chemistries of the elements...Ch. 21 - When BCl3 gas is passed through an electric...Ch. 21 - Prob. 71GQCh. 21 - Prob. 72GQCh. 21 - Prob. 73GQCh. 21 - Prob. 74GQCh. 21 - Prob. 75GQCh. 21 - Prob. 76GQCh. 21 - Prob. 77GQCh. 21 - Prob. 78GQCh. 21 - Prob. 79GQCh. 21 - Prob. 80GQCh. 21 - Prob. 81GQCh. 21 - Prob. 83GQCh. 21 - Prob. 84GQCh. 21 - A Boron and hydrogen form an extensive family of...Ch. 21 - In 1774, C. Scheele obtained a gas by reacting...Ch. 21 - What current must be used in a Downs cell...Ch. 21 - The chemistry of gallium: (a) Gallium hydroxide,...Ch. 21 - Prob. 89GQCh. 21 - Prob. 90GQCh. 21 - Prob. 91GQCh. 21 - Prob. 92GQCh. 21 - Prob. 93ILCh. 21 - Prob. 94ILCh. 21 - Prob. 95ILCh. 21 - Prob. 96ILCh. 21 - Prob. 97ILCh. 21 - Prob. 98ILCh. 21 - Prob. 99SCQCh. 21 - Prob. 100SCQCh. 21 - Prob. 101SCQCh. 21 - Prob. 102SCQCh. 21 - Prob. 103SCQCh. 21 - Prob. 104SCQCh. 21 - Prob. 105SCQCh. 21 - Prob. 106SCQCh. 21 - Prob. 107SCQCh. 21 - Prob. 108SCQCh. 21 - Prob. 109SCQCh. 21 - Prob. 110SCQCh. 21 - Comparing the chemistry of carbon and silicon. (a)...Ch. 21 - Prob. 112SCQCh. 21 - Xenon trioxide, XeO3, reacts with aqueous base to...
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