Organic Chemistry
5th Edition
ISBN: 9780078021558
Author: Janice Gorzynski Smith Dr.
Publisher: McGraw-Hill Education
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Chapter 21, Problem 21.73P
Although the carbonyl absorption of cyclic
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Explain why a carbonyl absorption shifts to lower frequency in an α,β-unsaturated carbonyl compound—a compound having a carbonyl group bonded directly to a carbon–carbon double bond. For example, the carbonyl absorption occurs at 1720 cm−1 for cyclohexanone, and at 1685 cm−1 for cyclohex-2-enone.
Although benzene itself absorbs at 128 ppm in its 13C NMR spectrum, the carbons of substituted benzenes absorb either upeld or downeld from this value depending on the substituent. Explain the observed values for the carbon ortho to the given substituent in the monosubstituted benzene derivatives X and Y.
Identify products A and B from the given 1H NMR data.
Treatment of acetone [(CH3)2C=O] with dilute aqueous base forms B. Compound B exhibits four singlets in its 1H NMR spectrum at 1.3 (6 H), 2.2 (3 H), 2.5 (2 H), and 3.8 (1H) ppm. What is the structure of B?
Chapter 21 Solutions
Organic Chemistry
Ch. 21 - Rank the following compounds in order of...Ch. 21 - Prob. 21.2PCh. 21 - Give the IUPAC name for each aldehyde.Ch. 21 - Prob. 21.4PCh. 21 - Give the IUPAC name for each ketone.Ch. 21 - Prob. 21.6PCh. 21 - Prob. 21.7PCh. 21 - The boiling point of is significantly higher than...Ch. 21 - Which carbonyl group in each pair absorbs at a...Ch. 21 - Problem 21.10 Draw the structure of all...
Ch. 21 - Prob. 21.11PCh. 21 - Prob. 21.12PCh. 21 - Prob. 21.13PCh. 21 - Prob. 21.14PCh. 21 - Problem 21.15 Draw the product of each...Ch. 21 - Prob. 21.16PCh. 21 - Problem 21.17 Draw the products of the following...Ch. 21 - Problem 21.18 Outline a synthesis of each Wittig...Ch. 21 - Problem 21.19 Draw the products (including...Ch. 21 - Problem 21.20 What starting materials are needed...Ch. 21 - Prob. 21.21PCh. 21 - Problem 21.22 The product formed when reacts with...Ch. 21 - Prob. 21.23PCh. 21 - Prob. 21.24PCh. 21 - Prob. 21.25PCh. 21 - Prob. 21.26PCh. 21 - Prob. 21.27PCh. 21 - Problem 21.28 Draw a stepwise mechanism for the...Ch. 21 - Problem 21.29 Draw the products of each...Ch. 21 - Problem 21.30 Label each compound as an acetal, a...Ch. 21 - Problem 21.31 Draw a stepwise mechanism for the...Ch. 21 - Problem 21.32 Draw the products of each...Ch. 21 - Problem 21.33 Safrole is a naturally occurring...Ch. 21 - Prob. 21.34PCh. 21 - Problem 21.35 How would you use a protecting group...Ch. 21 - Prob. 21.36PCh. 21 - Problem 21.37 Two naturally occurring compounds...Ch. 21 - Problem 21.38 Draw the products of each...Ch. 21 - Prob. 21.39PCh. 21 - Problem 21.40 (a) Give the IUPAC name for A and B....Ch. 21 - 21.41 Rank the following compounds in order of...Ch. 21 - Prob. 21.42PCh. 21 - 21.43 Give the IUPAC name for each compound.
a....Ch. 21 - 21.44 Give the structure corresponding to each...Ch. 21 - Prob. 21.45PCh. 21 - 21.46 Draw the products of each reaction.
a. e....Ch. 21 - Prob. 21.47PCh. 21 - 21.48 Draw all stereoisomers formed in each...Ch. 21 - Prob. 21.49PCh. 21 - What products are formed when each acetal is...Ch. 21 - Prob. 21.51PCh. 21 - Prob. 21.52PCh. 21 - Which compound forms the higher concentration of...Ch. 21 - Prob. 21.54PCh. 21 - Prob. 21.55PCh. 21 - Prob. 21.56PCh. 21 - Prob. 21.57PCh. 21 - Devise a synthesis of each alkene using a Wittig...Ch. 21 - Devise a synthesis of each compound from...Ch. 21 - Prob. 21.60PCh. 21 - Devise a synthesis of each compound from ethanol...Ch. 21 - Prob. 21.62PCh. 21 - Prob. 21.63PCh. 21 - 21.64 Draw a stepwise mechanism for the following...Ch. 21 - 21.65 Draw a stepwise mechanism f or the following...Ch. 21 - Prob. 21.66PCh. 21 - 21.67 Draw a stepwise mechanism for each...Ch. 21 - 21.68 Draw a stepwise mechanism for the following...Ch. 21 - Prob. 21.69PCh. 21 - Prob. 21.70PCh. 21 - Prob. 21.71PCh. 21 - Prob. 21.72PCh. 21 - 21.73 Although the carbonyl absorption of cyclic...Ch. 21 - 21.74 Use the and data to determine the...Ch. 21 - 21.75 A solution of acetone in ethanol in the...Ch. 21 - Compounds A and B have molecular formula ....Ch. 21 - 21.77 An unknown compound C of molecular formula ...Ch. 21 - 21.78 An unknown compound D exhibits a strong...Ch. 21 - Prob. 21.79PCh. 21 - -D-Glucose, a hemiacetal, can be converted to a...Ch. 21 - 21.81 Draw a stepwise mechanism for the following...Ch. 21 - Prob. 21.82PCh. 21 - 21.83 Draw a stepwise mechanism f or the...Ch. 21 - Prob. 21.84PCh. 21 - Prob. 21.85PCh. 21 - 21.86 Draw stepwise mechanism for the following...
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- Compound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forwardAlthough benzene itself absorbs at 128 ppm in its 13C NMR spectrum, the carbons of substituted benzenes absorb either upfield or downfield from this value depending on the substituent. Explain the observed values for the carbon ortho to the given substituent in the monosubstituted benzene derivatives X and Y.arrow_forwardTreatment of compound E (molecular formula C4H8O2) with excess CH3CH2MgBr yields compound F (molecular formula C6H14O) after protonation with H2O. E shows a strong absorption in its IR spectrum at 1743 cm-1. F shows a strong IR absorption at 3600–3200 cm-1. The 1H NMR spectral data of E and F are given. What are the structures of E and F?Compound E signals at 1.2 (triplet, 3 H), 2.0 (singlet, 3 H), and 4.1 (quartet, 2 H) ppmCompound F signals at 0.9 (triplet, 6 H), 1.1 (singlet, 3 H), 1.5 (quartet, 4 H), and 1.55 (singlet, 1 H) ppmarrow_forward
- When compound A (C5H12O) is treated with HBr, it forms compound B (C5H11Br). The 1H NMR spectrum of compound A has a 1H singlet, a 3H doublet, a 6H doublet, and two 1H multiplets. The 1H NMR spectrum of compound B has a 6H singlet, a 3H triplet, and a 2H quartet. Identify compounds A and B.arrow_forwardIdentify the structures of D and E, isomers of molecular formulaC6H12O2, from their IR and 1H NMR data. Signals at 1.35 and 1.60 ppm inthe 1H NMR spectrum of D and 1.90 ppm in the 1H NMR spectrum of Eare multipletsarrow_forwardExplain Characteristic Spectroscopic Absorptions of Carboxylic Acid Derivatives ?arrow_forward
- An unknown compound has a molecular formula of C4H6O2. Its IR spectrum shows absorptions at 3095, 1762, 1254, and 1118 cm -1. It exhibits the following signals in its 1H NMR spectrum (ppm): 2.12 (singlet,3H), 4.55 (doublets of doublets, 1H), 4.85 (doublet of doublets, 1H), 7.25 (doublets of doublets, 1H); and the following signals in its 13C NMR spectrum (ppm): 20.8, 100.4, 141.2, 168.0. Draw the structure of the unknown compoundarrow_forwardCompounds A and B are isomers having the molecular formula C4H8O3. Identify A and B on the basis of their 1H NMR spectra.Compound A: δ 1.3 (3H, triplet); 3.6 (2H, quartet); 4.1 (2H, singlet); 11.1 (1H, broad singlet)Compound B: δ 2.6 (2H, triplet); 3.4 (3H, singlet); 3.7 (2H triplet); 11.3 (1H, broad singlet)arrow_forwardWhen compound A (C5H12O) is treated with HBr, it forms compound B (C5H11Br). The 1 H NMR spectrum of compound A has a 1H singlet, a 3H doublet, a 6H doublet, and two 1H multiplets. The 1 H NMR spectrum of compound B has a 6H singlet, a 3H triplet, and a 2H quartet. Identify compounds A and B.arrow_forward
- Identify the structure of compound C (molecular formula C11H15NO2), which has an IR absorption at 1699 cm−1 and the 1H NMR spectrum shown below.arrow_forwardAn unknown compound has a molecular formula of C,H,O. Its IR spectrum shows prominent absorptions at 2980, 2960, and 1718 cm . It exhibits the following signals in its H NMR spectrum (ppm): 1.06 (triplet, 3H), 2.12 (singlet, 3H), 2.45 (quartet, 2H); and the following signals in its ¹3C NMR spectrum ( ppm): 7.6, 29.5, 36.8, 208.8. Draw the structure of the unknown compound. Click and drag to start drawing a structure. 0 X 0:0arrow_forwardDraw the structure of a compound, C4H8O3 that exhibits IR absorptions at 1710 and 2500-3000 cm-1 and thefollowing 1H NMR signals: 11.1 (1H, singlet), 4.14 (2H, singlet), 3.63 (2H, quartet), 1.26 (3H, triplet) ppm.arrow_forward
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