(a) Interpretation: On the basis of the relative boiling point of 2 − butanone and methyl acetate, the compound having the greater dipole moment is to be predicted. Concept introduction: The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below. μ = δ d Dipole moment and boiling point are directly proportional to each other.

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Answer 1

Question

Chapter 21, Problem 21.6P

Interpretation Introduction

(a)

Interpretation:

On the basis of the relative boiling point of 2−butanone and methyl acetate, the compound having the greater dipole moment is to be predicted.

Concept introduction:

The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below.

μ=δd

Dipole moment and boiling point are directly proportional to each other.

Interpretation Introduction

(b)

Interpretation:

The reason as to why 2−butanone has greater dipole moment with the help of vector analysis is to be stated.

Concept introduction:

The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below.

μ=δd

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Answer 2

Question

Chapter 21, Problem 21.6P

Interpretation Introduction

(a)

Interpretation:

On the basis of the relative boiling point of 2−butanone and methyl acetate, the compound having the greater dipole moment is to be predicted.

Concept introduction:

The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below.

μ=δd

Dipole moment and boiling point are directly proportional to each other.

Interpretation Introduction

(b)

Interpretation:

The reason as to why 2−butanone has greater dipole moment with the help of vector analysis is to be stated.

Concept introduction:

The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below.

μ=δd

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Answer 3

Question

Chapter 21, Problem 21.6P

Interpretation Introduction

(a)

Interpretation:

On the basis of the relative boiling point of 2−butanone and methyl acetate, the compound having the greater dipole moment is to be predicted.

Concept introduction:

The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below.

μ=δd

Dipole moment and boiling point are directly proportional to each other.

Interpretation Introduction

(b)

Interpretation:

The reason as to why 2−butanone has greater dipole moment with the help of vector analysis is to be stated.

Concept introduction:

The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below.

μ=δd

Expert Solution & Answer

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See solution

Answer 4

Question

Chapter 21, Problem 21.6P

Interpretation Introduction

(a)

Interpretation:

On the basis of the relative boiling point of 2−butanone and methyl acetate, the compound having the greater dipole moment is to be predicted.

Concept introduction:

The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below.

μ=δd

Dipole moment and boiling point are directly proportional to each other.

Interpretation Introduction

(b)

Interpretation:

The reason as to why 2−butanone has greater dipole moment with the help of vector analysis is to be stated.

Concept introduction:

The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below.

μ=δd

Expert Solution & Answer

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Answer 5

Chapter 21, Problem 21.6P

Interpretation Introduction

(a)

Interpretation:

On the basis of the relative boiling point of 2−butanone and methyl acetate, the compound having the greater dipole moment is to be predicted.

Concept introduction:

The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below.

μ=δd

Dipole moment and boiling point are directly proportional to each other.

Interpretation Introduction

(b)

Interpretation:

The reason as to why 2−butanone has greater dipole moment with the help of vector analysis is to be stated.

Concept introduction:

The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below.

μ=δd

Answer 6

Chapter 21, Problem 21.6P

Interpretation Introduction

(a)

Interpretation:

On the basis of the relative boiling point of 2−butanone and methyl acetate, the compound having the greater dipole moment is to be predicted.

Concept introduction:

The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below.

μ=δd

Dipole moment and boiling point are directly proportional to each other.

Answer 7

Chapter 21, Problem 21.6P

Interpretation Introduction

(a)

Interpretation:

On the basis of the relative boiling point of 2−butanone and methyl acetate, the compound having the greater dipole moment is to be predicted.

Concept introduction:

The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below.

μ=δd

Dipole moment and boiling point are directly proportional to each other.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The reason as to why 2−butanone has greater dipole moment with the help of vector analysis is to be stated.

Concept introduction:

The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below.

μ=δd

Answer 9

Interpretation Introduction

(b)

Interpretation:

The reason as to why 2−butanone has greater dipole moment with the help of vector analysis is to be stated.

Concept introduction:

The dipole moment is used to measure the polarity of the bond in the molecule. It is defined as the product of the separation of charges and its magnitude. It is represented as shown below.

μ=δd

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 21 - Prob. 21.1P Ch. 21 - Prob. 21.2P Ch. 21 - Prob. 21.3P Ch. 21 - Prob. 21.4P Ch. 21 - Prob. 21.5P Ch. 21 - Prob. 21.6P Ch. 21 - Prob. 21.7P Ch. 21 - Prob. 21.8P Ch. 21 - Prob. 21.9P Ch. 21 - Prob. 21.10P

Solution Summary: The author analyzes the dipole moment and boiling point of 2-butanone and methyl acetate.

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Chapter 21 Solutions