
Concept explainers
(a)
The amount of iron in
(a)

Answer to Problem 16P
Explanation of Solution
Given Info: The cross-sectional area of iron wire is
Amount of iron in one mole is given as,
It is the standard value for iron wire.
Convert the amount of iron into
Thus,
Conclusion:
Therefore,
(b)
The molar density of iron.
(b)

Answer to Problem 16P
The molar density of iron is
Explanation of Solution
Given Info: The cross-sectional area of iron wire is
The formula for the molar density is,
Here,
Substitute
Thus, the molar density of iron is
Conclusion:
Therefore, the molar density of iron is
(c)
The number density of iron atoms.
(c)

Answer to Problem 16P
The number density of iron atoms is
Explanation of Solution
Given Info: The cross-sectional area of iron wire is
The formula for the number density is,
Here,
Substitute
Thus, the number density of iron atoms is
Conclusion:
Therefore, the number density of iron atoms is
(d)
The number density of two
(d)

Answer to Problem 16P
The number density of two conduction iron atoms is
Explanation of Solution
Given Info: The cross-sectional area of iron wire is
The formula for the number density of two conduction atoms is,
Here,
Substitute
Thus, the number density of two conduction iron atoms is
Conclusion:
Therefore, the number density of two conduction iron atoms is
(e)
The drift speed of the conduction electrons.
(e)

Answer to Problem 16P
The drift speed of the conduction electrons is.
Explanation of Solution
Given Info: The cross-sectional area of iron wire is
Formula to calculate the drift speed is,
Substitute
Conclusion:
Therefore, the total drift speed of the conduction electrons is.
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Chapter 21 Solutions
Bundle: Principles of Physics: A Calculus-Based Text, 5th + WebAssign Printed Access Card for Serway/Jewett's Principles of Physics: A Calculus-Based Text, 5th Edition, Multi-Term
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