a) Interpretation: Two 1 HNMR spectra belonging to crotonic acid (trans-CH 3 CH=CHCOOH) and methacrylic acid (H 2 C=C (CH 3 ) COOH) are given. Which corresponds to which is to be explained. 1 HNMR: Spectrum (a): 1.91 δ (Rel.area: 3.00), 5.83 δ (Rel.area: 1.00), 7.10 δ (Rel.area: 1.00), 12.21 δ (Rel.area: 1.00). Concept introduction: Crotonic acid (trans-CH 3 CH=CHCOOH) and methacrylic acid (H 2 C=C (CH 3 ) COOH) can be easily distinguished by looking the signal for the methyl protons in these two compounds. To explain: Of the two 1 HNMR spectra given, which belongs to crotonic acid (trans-CH 3 CH=CHCOOH) and methacrylic acid (H 2 C=C (CH 3 ) COOH).

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> You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: 1. ☑ CI 2. H3O+ O Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. Explanation Check ? DO 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility

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Chapter 20.SE, Problem 67AP

Interpretation Introduction

a)

Interpretation:

Two ¹HNMR spectra belonging to crotonic acid (trans-CH₃CH=CHCOOH) and methacrylic acid (H₂C=C (CH₃) COOH) are given. Which corresponds to which is to be explained.

¹HNMR: Spectrum (a): 1.91 δ (Rel.area: 3.00), 5.83 δ (Rel.area: 1.00), 7.10 δ (Rel.area: 1.00), 12.21 δ (Rel.area: 1.00).

Concept introduction:

Crotonic acid (trans-CH₃CH=CHCOOH) and methacrylic acid (H₂C=C (CH₃) COOH) can be easily distinguished by looking the signal for the methyl protons in these two compounds.

To explain:

Of the two ¹HNMR spectra given, which belongs to crotonic acid (trans-CH₃CH=CHCOOH) and methacrylic acid (H₂C=C (CH₃) COOH).

Interpretation Introduction

b)

Interpretation:

Two ¹HNMR spectra belonging to crotonic acid (trans-CH₃CH=CHCOOH) and methacrylic acid (H₂C=C (CH₃) COOH) are given. Which corresponds to which is to be explained.

¹HNMR: Spectrum (b): 1.93 δ (Rel.area: 3.00), 5.66 δ (Rel.area: 1.00), 6.25 δ (Rel.area: 1.00), 12.24 δ (Rel.area: 1.00).

Concept introduction:

Crotonic acid (trans-CH₃CH=CHCOOH) and methacrylic acid (H₂C=C (CH₃) COOH) can be easily distinguished by looking the signal for the methyl protons in these two compounds.

To explain:

Of the two ¹HNMR spectra given, which belongs to crotonic acid (trans-CH₃CH=CHCOOH) and methacrylic acid (H₂C=C (CH₃) COOH).

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> You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: 1. ☑ CI 2. H3O+ O Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. Explanation Check ? DO 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility

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Consider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence point