Genetics: From Genes to Genomes, 5th edition
Genetics: From Genes to Genomes, 5th edition
5th Edition
ISBN: 9780073525310
Author: Leland H. Hartwell, Michael L. Goldberg, Janice A. Fischer, Leroy Hood, Charles F. Aquadro
Publisher: McGraw-Hill Education
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Chapter 20, Problem 6P

A dominant mutation in Drosophila called Delta causes changes in wing morphology in Delta / + heterozygotes. Homozygosity for this mutation (Delta / Delta) is lethal. In a population of 150 flies, it was determined that 60 had normal wings and 90 had abnormal wings.

a. What are the allele frequencies in this population?
b. Using the allele frequencies calculated in part (a), how many total zygotes must be produced by this population in order for you to count 160 viable adults in the next generation?
c. Given that there is random mating, no migration, and no mutation, and ignoring the effects of genetic drift, what are the expected numbers of the different genotypes in the next generation if 160 viable offspring of the population in part (a) are counted?
d. Is this next generation at Hardy-Weinberg equilibrium? Why or why not?
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UARDIAN SIGNA Life Sciences/ Baseline Test Grade 10 ry must be written in point form. pot in full sentences using NO MORE than 70 words sentences from 1 to 7. only ONE point per sentence. words as far as possible. number of words you have used in brackets at the end GDE/2024 QUESTION 3 The table below shows the results of an investigation in which the effect of temperature and light on the yield of tomatoes in two greenhouses on a farm was investigated. TEMPERATURE (°C) AVERAGE YIELD OF TOMATOES PER 3.1 PLANT (kg) LOW LIGHT LEVELS HIGH LIGHT LEVELS 5 0,5 0,5 10 1,5 2,5 15 3,0 5,0 20 3,6 8,5 25 3,5 7,8 30 2,5 6,2 State TWO steps the investigator may have taken into consideration during the planning stage of the investigation. (2) 3.2 Identify the: a) Independent variables (2) b) Dependent variable (1) 3.3 Plot a line graph showing the results of the average yield of the tomatoes from 5°C to 30°C for low light levels. (6) 3.4 State ONE way in which the scientists could have improved the…
Explain why you chose this mutation. Begin by transcribing and translating BOTH the normal and abnormal DNA sequences. The genetic code below is for your reference. SECOND BASE OF CODON כ FIRST BASE OF CODON O THIRD BASE OF CODON SCAGUCAGUGAGUCAG UUU UUC UCU UAU UGU Phenylalanine (F) Tyrosine (Y) Cysteine (C) UCC UAC UGC Serine (S) UUA UUG Leucine (L) UCA UCG_ UAA UGA Stop codon -Stop codon UAG UGG -Tryptophan (W) CUU CUC CCU CAU CGU Histidine (H) CCC CAC CGC -Leucine (L) Proline (P) CUA CCA CAA CUG CCG CAG-Glutamine (Q) -Arginine (R) CGA CGG AUU ACU AAU AGU AUC Isoleucine (1) Asparagine (N) ACC AAC Threonine (T) AUA ACA AAA Methionine (M) Lysine (K) AUG ACG Start codon AAG AGC-Serine (S) -Arginine (R) AGA AGG GUU GCU GAU GUC GUA GUG GCC Valine (V) -Alanine (A) GCA GCG GAC GAA GAG Aspartic acid (D) GGU Glutamic acid (E) GGC GGA GGG Glycine (G) In order to provide a complete answer to the question stated above, fill in the mRNA bases and amino acid sequences by using the Genetic Code…
identify the indicated cell in white arrow

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Genetics: From Genes to Genomes, 5th edition

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