Chemical Principles
Chemical Principles
8th Edition
ISBN: 9781305581982
Author: Steven S. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
Question
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Chapter 20, Problem 5E

(a)

Interpretation Introduction

Interpretation:

The balanced equation for process which involves the electron capture in decay of Chromium -51 needs to be determined.

Concept Introduction:

Electron capture is a process where nucleus captures electrons from surrounding cloud of electrons. By this process, the protons get converted to neutron and energy is emitted as gamma rays. Thereby the atomic number of the nucleus gets reduced by 1 unit keeping the mass number the same.

(b)

Interpretation Introduction

Interpretation:

The balanced equation for process which involves the emission of β particle in decay of Iodine-131 and used to treat hyperactive thyroid glands needs to be determined.

Concept Introduction:

Beta decay is the process where the nucleus changes neutron to proton and in which mass number remains the same while the atomic number decreases by 1 unit.

(c)

Interpretation Introduction

Interpretation:

The balanced equation for process which involves the emission of β particle during the decay of Phosphorus-32 that accumulates in the liver needs to be determined.

Concept Introduction:

Beta decay brings about changes of neutron to proton wherein the mass number remains unchanged while the atomic number decreases by 1 unit.

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From the following potentials, calculate the activity of Cl- in saturated KCl. E0 (calomel electrode)= 0.268 V E (calomel electrode, saturated KCl)= 0.241 V
Calculate the voltage of each of the following cells. a) Fe(s)/Fe2+ (1.55 x 10-2 M)//Cu2+ (6.55 x 10-3 M)/Cu(s) b) Pt, H2 (0.255 bar)/HCl (4.55 x 10-4 M), AgCl (sat'd)/Ag Fe2+ +2e- = Fe   E0= -0.44 V Cu2+ + 2e- = Cu  E0= 0.337 V Ag+ + e- = Ag   E0= 0.799 V AgCl(s) + e- = Ag(s) + Cl-  E0= 0.222 V 2H+ + 2e- = H2   E0= 0.000 V
A solution contains 0.097 M Ce3+, 1.55x10-3 M Ce4+, 1.55x10-3 M Mn2+, 0.097 M MnO4-, and 1.00 M HClO4 (F= 9.649 x 104 C/mol). a) Write a balanced net reaction that can occur between species in this solution. b) Calculate deltaG0 and K for the reaction. c) Calculate E and deltaG for the conditions given. Ce4+ + e- = Ce3+  E0= 1.70 V MnO4- + 8H+ + 5e- = Mn2+ + 4H2O   E0= 1.507 V

Chapter 20 Solutions

Chemical Principles

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