Chapter 20, Problem 6E

A

Interpretation Introduction

Interpretation : The given equation needs to be completed.

Concept Introduction : The radioactive decay process is the process in which element is decayed by releasing a, ß, and γ rays.

Answer to Problem 6E

Hence the missing particle will be beta particle.

Explanation of Solution

Given information : The given reaction is as follows,

  $Ga\to Ge+?$

Let the missing particle is $X$ , where A represents the atomic mass and Z represents the atomic number. Now the equation looks like this,

  $Ga\to Ge+X$ , now equate the atomic mass and number of the both sides. The following will be the result:-

  $\begin{array}{l}73=73+A\\ 31=32+Z\end{array}$

Hence A=0 and Z= -1. Hence the missing particle will be beta particle and it is represented by $e$ . Now the final equation will be,

  $Ga\to Ge+e$

B

Interpretation Introduction

Interpretation : The given equation needs to be completed.

Concept Introduction : The radioactive decay process is the process in which element is decayed by releasing a, ß, and γ rays.

Answer to Problem 6E

The missing particle will be alpha particle.

Explanation of Solution

Given information : The equation is given,

  $Pt\to Os+?$

Let the missing particle is $X$ , where A represents the atomic mass and Z represents the atomic number. Now the equation looks like this,

  $Pt\to Os+X$ , now equate the atomic mass and number of the both sides. The following will be the result:-

  $\begin{array}{l}192=188+A\\ 78=76+Z\end{array}$

From the above equation, A= 4 and Z=2. Hence the missing particle is alpha particle which is represented by the $He$ . Now the equation will be,

  $Pt\to Os+He$

C

Interpretation Introduction

Interpretation : The given equation needs to be completed.

Concept Introduction : The radioactive decay process is the process in which element is decayed by releasing a, ß, and γ rays.

Answer to Problem 6E

Hence the missing particle is positron.

Explanation of Solution

Given information : The given equation is as follows,

  $Bi\to Pb+?$

Let the missing particle is $X$ , where A represents the atomic mass and Z represents the atomic number. Now the equation looks like this,

  $Bi\to Pb+X$ , now equate the atomic mass and number of the both sides. The following will be the result:-

  $\begin{array}{l}205=205+A\\ 83=82+Z\end{array}$

From the equation, A= 0, and Z= 1, hence this particle will be positron which is represented by the $e$ .

D

Interpretation Introduction

Interpretation : The given equation needs to be completed.

Concept Introduction : The radioactive decay process is the process in which element is decayed by releasing a, ß, and γ rays.

Answer to Problem 6E

Hence the missing particle is beta particle.

Explanation of Solution

Given information : The given equation is given below,

  $Cm+?\to Am$

Let the missing particle is $X$ , where A represents the atomic mass and Z represents the atomic number. Now the equation looks like this,

  $Cm+X\to Am$ , now equate the atomic mass and number of the both sides. The following will be the result:-

  $\begin{array}{l}241+A=241\\ 96+Z=95\end{array}$

From the equation A=0 and Z= -1. Hence the missing particle is beta particle and represented by $e$ . Now the equation become,

  $Cm+e\to Am$

E

Interpretation Introduction

Interpretation : The given equation needs to be completed.

Concept Introduction : The radioactive decay process is the process in which element is decayed by releasing a, ß, and γ rays.

Answer to Problem 6E

Hence the missing particle is beta particle.

Explanation of Solution

Given information : The given equation is given below,

  $Co\to Ni+?$

Let the missing particle is $X$ , where A represents the atomic mass and Z represents the atomic number. Now the equation looks like this,

  $Co\to Ni+X$ , now equate the atomic mass and number of the both sides. The following will be the result:-

  $\begin{array}{l}60=60+A\\ 27=28+Z\end{array}$

From the equation, A= 0 and Z= -1. Hence the missing particle is beta particle and represented by $e$ . Now the equation will be,

  $Co\to Ni+e$

F

Interpretation Introduction

Interpretation : The given equation needs to be completed.

Concept Introduction : The radioactive decay process is the process in which element is decayed by releasing a, ß, and γ rays.

Answer to Problem 6E

Hence the missing particle is beta particle.

Explanation of Solution

Given information : The given equation is given below,

  $Tc+?\to Mo$

Let the missing particle is $X$ , where A represents the atomic mass and Z represents the atomic number. Now the equation looks like this,

  $Tc+X\to Mo$ , now equate the atomic mass and number of the both sides. The following will be the result:-

  $\begin{array}{l}97+A=97\\ 43+Z=42\end{array}$

From the equation, A= 0 and Z= -1. Hence the missing particle is beta particle and represented by $e$ . Now the equation will be,

  $Tc+e\to Mo$

G

Interpretation Introduction

Interpretation : The given equation needs to be completed.

Concept Introduction : The radioactive decay process is the process in which element is decayed by releasing a, ß, and γ rays.

Answer to Problem 6E

Hence the missing particle is beta particle.

Explanation of Solution

Given information : The given equation is given below,

  $Tc\to Ru+?$

Let the missing particle is $X$ , where A represents the atomic mass and Z represents the atomic number. Now the equation looks like this,

  $Tc\to Ru+X$ , now equate the atomic mass and number of the both sides. The following will be the result:-

  $\begin{array}{l}99=99+A\\ 43=44+Z\end{array}$ ,

From the equation, A= 0 and Z= -1. Hence the missing particle is beta particle and represented by $e$ . Now the equation will be,

  $Tc\to Ru+e$

H

Interpretation Introduction

Interpretation : The given equation needs to be completed.

Concept Introduction : The radioactive decay process is the process in which element is decayed by releasing a, ß, and γ rays.

Answer to Problem 6E

Hence the missing particle is alpha particle.

Explanation of Solution

Given information : The given equation is given below,

  $Pu\to U+?$

Let the missing particle is $X$ , where A represents the atomic mass and Z represents the atomic number. Now the equation looks like this,

  $Pu\to U+X$ , now equate the atomic mass and number of the both sides. The following will be the result:-

  $\begin{array}{l}239=235+A\\ 94=92+Z\end{array}$ ,

From the above equation, A= 4 and Z=2. Hence the missing particle is alpha particle which is represented by the $He$ . Now the equation will be:

  $Pu\to U+He$ .