Microbiology: An Introduction
12th Edition
ISBN: 9780321929150
Author: Gerard J. Tortora, Berdell R. Funke, Christine L. Case
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Textbook Question
Chapter 20, Problem 3A
Some bacteria become resistant to tetracycline because they don’t make porins. Why can a porin-deficient mutant be detected by its inability to grow on a medium containing a single carbon source such as succinic acid?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
In the experiment by Bernard Davis, bacterial F+cells and F- cells were growing while separated by a filter. Filter pores allowed the passage of the liquid medium but not the bacteria cells. As a result:
1) prototype colonies grew well on minimal medium
2) F+ cells were converted to F- cells despite the physical separation
3)F- cells were converted F+ cells despite the physical separation
4)F+ cells were not converted to F- cells because of the physical separation
5) F- cells were not converted to F+ cells because of the physical separation
6)there was no growth of prototypes on minimal medium
Type S Streptococcus pneumoniae bacterium is lethal and will kill its host. If heat inactivated the S strain dies and becomes nonlethal. Type R Streptococcus pneumoniae is a nonvirulent strain of bacteria. What would occur if one were to inject both the R strain and heat-killed S strains into a host organism such as the mouse?
The R strain would be transformed into the virulent S strain and kill the host.
Neither the S nor the R strain would change.
The R strain would be transformed into the virulent S strain and not affect the host.
The S strain would be transformed into the nonvirulent R strain and not affect the host
The S strain would be transformed into the nonvirulent R strain and kill the host.
You have several different media onto which you inoculated eight strains of yeast (A-H). The media
include a rich medium, an unsupplemented minimal medium, and minimal media each supplemented
with one vitamin. Of the yeast strains, one is a prototroph and seven are auxotrophs for a vitamin.
After overnight incubation, the following results were observed (tan patches represent growth):
D
plate 1
(A) B
DE F
GH
plate 5
plate 4
plate 6
Which plate contains an unsupplemented minimal medium? [Select]
Which plate contains a rich medium? [Select]
plate 2
Which strain is a prototroph? [Select]
Strain E is an auxotroph for niacin. Which plate reveals this specific auxotrophy?
[ Select]
plate 3
plate 7
One strain is an auxotroph for both choline and pantothenic acid. Which one is this most likely to
be? [Select]
Chapter 20 Solutions
Microbiology: An Introduction
Ch. 20 - DRAW IT Show where the following antibiotics work:...Ch. 20 - List and explain five criteria used to identify an...Ch. 20 - What similar problems are encountered with...Ch. 20 - Define drug resistance. How is it produced? What...Ch. 20 - List the advantages of using two chemotherapeutic...Ch. 20 - Why does a cell die from the following...Ch. 20 - How does each of the following inhibit...Ch. 20 - The OH is missing from carbon 39 in ddI. How does...Ch. 20 - Compare the method of action of the following...Ch. 20 - NAME IT This microorganism is not susceptible to...
Ch. 20 - Which of the following pairs is mismatched? a....Ch. 20 - Prob. 2MCQCh. 20 - Prob. 3MCQCh. 20 - An antimicrobial agent should meet all of the...Ch. 20 - The most selective antimicrobial activity would be...Ch. 20 - Prob. 6MCQCh. 20 - Which of the following will not affect eukaryotic...Ch. 20 - Cell membrane damage causes death because a. the...Ch. 20 - A drug that intercalates into DNA has the...Ch. 20 - Chloramphenicol binds to the 50S portion of a...Ch. 20 - Prob. 1ACh. 20 - Why is idoxuridine effective if host cells also...Ch. 20 - Some bacteria become resistant to tetracycline...Ch. 20 - The following data were obtained from a...Ch. 20 - Prob. 5ACh. 20 - The following results were obtained from a broth...Ch. 20 - Vancomycin-resistant Enterococcus faecalis was...Ch. 20 - Prob. 2CAECh. 20 - Prob. 3CAE
Additional Science Textbook Solutions
Find more solutions based on key concepts
Sea turtles have disappeared from many regions, and one way of trying to save them is to reintroduce them to ar...
MARINE BIOLOGY
2. Why is it that the range of resting blood pressures of humans is best represented by a bell-shaped curve co...
Human Biology: Concepts and Current Issues (8th Edition)
Why is it unlikely that two neighboring water molecules would be arranged like this?
Campbell Biology (10th Edition)
A student moving out of a dormitory crouches in correct fashion to lift a heavy box of books. What prime movers...
HUMAN ANATOMY
Why is it unlikely that two neighboring water molecules would be arranged like this?
Campbell Biology (11th Edition)
What are the cervical and lumbar enlargements?
Principles of Anatomy and Physiology
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- You have isolated a strain of E.coli that is resistant to penicillin,streptomycin,chloramphenicol and tetracycline. You also observe that when you mix this strain with a strain that is sensitive to all four antibiotics, the new strain becomes resistant to streptomycin,penicillin and chloramphenicol but not tetracycline. Explain how this is so?arrow_forwardWhat would happen to a bacteria that lost a plasmid for antibiotic resistance? Would it still be able to grow in normal growth conditions? Explain.arrow_forwardYou take 10 ml of a stock solution, which is at a concentration of 1000 phage/ml, and dilute it to a total of 100 ml. From the resulting solution you take 5 ml and dilute it to 25 ml, and from the latter you take 5 ml and make a total of 20 ml. a) It will be possible to know how many bacteriophage particles there will be in 1 ml of the last solution b) What is the dilution factor in each step, in the same order in which the dilutions are made? c) What is the total serial dilution factor?arrow_forward
- Bacillus thuringiensis makes toxins that kill insects. These toxins must be applied several times during the growth season to prevent insect damage. As an alternative to repeated applications, one strategy is to apply bacteria directly to leaves.However,B. thuringiensis does not survive very long in thefield. Other bacteria, such as Pseudomonas syringae, do survive.Propose a way to alter P. syringae so it could be used as an insecticide.Discuss advantages and disadvantages of this approach compared with the repeated applications of the toxins from B. thuringiensis.arrow_forwardWhen present on the leaves of plants, the bacterium Pseudomonas syringae can promote frost damage to plants. Mutant strains, lacking the “ice” gene, have been applied to plants to try and protect the plants from wild-type P. syringae-induced frost. Assume that I am telling the truth that wild-type P. syringae nucleates ice formation at -2 °C, and provide an explanation as to why application of this altered (mutant) bacterium to plants might be a beneficial agricultural strategy in areas where morning lows occasionally dip down to 28-30 °F.arrow_forwardThe wild type bacterium is lac+ amps, leu+, ade+ Mutant I is: lac+ amp r, leu-, ade+ Mutant 2 is: lac+, amp s, leu+, ade- Mutant 3 is: lac-, amp r. leu-, ade- The circles below represent six different types of growth medium for these cells. The text below each circle indicates the composition of the medium in that plate. Please divide each plate into quadrants, one for the wild type and one each for the three mutants. Then, draw in the appearance of the plates after we place cells of these genotypes on them and allow growth to occur (if it can). rich, glucose rich, lactose OO minimal, leucine, adenine minimal, glucose, adenine rich, lactose, amp O minimal. glucose, leucinearrow_forward
- A phenylgalactoside-type compound, which yields galactose when enzymatically cleaved, was added as the sole carbon source to petri dishes containing E. coli culture medium. E. coli can utilize galactose for growth. Each of the following bacterial strains was plated on this medium and scored for growth after 1-2 days. Growth Genotype lacz+ lacI+ lacz+ lacIs lacz+ lacl- + oc lacZ+ lacI+ + a) What do you conclude about this compound with respect to its ability to be cleaved by ß- galactosidase? Why? b) What do you conclude about this compound with respect to its ability to inactivate the Lac repressor? Why? Tarrow_forwardIn your laboratory, you have an F− strain of E. coli that is resistantto streptomycin and is unable to metabolize lactose, but it can metabolizeglucose. Therefore, this strain can grow on a medium thatcontains glucose and streptomycin, but it cannot grow on a mediumcontaining lactose. A researcher has sent you two E. colistrains in two separate tubes. One strain, let’s call it strain A, hasan F′ factor (an F prime factor) that carries the genes that are requiredfor lactose metabolism. On its chromosome, it also has thegenes that are required for glucose metabolism. However, it is sensitiveto streptomycin. This strain can grow on a medium containinglactose or glucose, but it cannot grow if streptomycin is addedto the medium. The second strain, let’s call it strain B, is an F−strain. On its chromosome, it has the genes that are required forlactose and glucose metabolism. Strain B is also sensitive to streptomycin.Unfortunately, when strains A and B were sent to you, thelabels had fallen…arrow_forwardResults from a Kirby Bauer antibiotic assay on a Gram-negative bacterial culture are described as follows: A) the bacterium is resistant to penicillin, an antibiotic that targets synthesis of the peptidoglycan cell wall and B) the bacterium is resistant to tetracycline, an antibiotic that targets the small subunit of the ribosome, inhibiting protein synthesis. Which of the results represents intrinsic resistant and which represents acquired resistants?arrow_forward
- A Hfr bacterium mates with an F- plasmid containing bacterium. What will be the type of bacteria after conjugation is complete?arrow_forwardWhy is it important to use a hyperthermophilic DNA polymerase in PCR? a) Because only hyperthermophiles have DNA polymerases. b) Because hyperthermophilic DNA polymerase is able to resist the saline reaction conditions. c) Because hyperthermophilic DNA polymerase is faster than other polymerases. d) Because hyperthermophilic DNA polymerase is able to resist denaturation at 95℃.arrow_forwardFifteen bacterial colonies growing on a complete medium (that means that they have all of nutrients that they need supplied in the dish, and they don't actually need to synthesize these compounds to survive) are transferred to minimal medium. Twelve of the colonies grow on minimal medium. Three colonies do not grow on minimal medium. But, if these three colonies are put on a plate that has minimal medium supplemented with the amino acid serine (min + Ser), they all What does this suggest about the three bacterial colonies (pick all that apply)? grow. They lack the ability to synthesize their own serine. O They are probably wild-type. They probably have a mutation that causes them to lack a certain protein. They probably have a mutation that causes them to be unable to perform translation. O They probably have a mutation that causes them to be unable to perform transcription. O They are able to synthesize everything that they need to grow except for serine.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Prokaryotic vs. Eukaryotic Cells (Updated); Author: Amoeba Sisters;https://www.youtube.com/watch?v=Pxujitlv8wc;License: Standard youtube license