(a) Interpretation: Complete and balance the given chemical reaction . C 3 H 18 ( l ) + O 2 ( g ) → . Concept Introduction: Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond. The reaction in which burning of hydrocarbons takes place in oxygen to release water and carbon dioxide is known combustion reaction of hydrocarbon.

Question

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Answer 1

Question

Definition Definition Molecules that have multiple bonds between their carbon atoms. Alkenes are hydrocarbons with a double bond between two adjacent carbon atoms (R 2 C=CR 2 ), whereas alkynes are hydrocarbons with a triple bond between two adjacent carbon atoms R-C=C-R . These two groups are known as unsaturated hydrocarbons. They have fewer hydrogen atoms when compared with alkanes with same number of carbon atoms. The general molecular formula for an unsaturated hydrocarbon can be represented as C n H 2n +2 .

Chapter 20, Problem 38QAP

Interpretation Introduction

(a)

Interpretation:

Complete and balance the given chemical reaction.

$C3H18(l)+O2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

The reaction in which burning of hydrocarbons takes place in oxygen to release water and carbon dioxide is known combustion reaction of hydrocarbon.

Expert Solution

Answer to Problem 38QAP

$2C3H18(l)+15O2(g)→6CO2(g)+18H2O(l)$ .

Explanation of Solution

The complete reaction is shown below:

$C3H18(l)+O2(g)→CO2(g)+H2O(l)$

Now, balance the above reaction, number of carbon atom is 3 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 18 on reactant side and on product side number of hydrogen atom is 2. Number of oxygen atom is 2 on reactant side and on product side number of oxygen atom is 3.

To balance the reaction, multiply $CO2$ by 16 and $H2O$ by 18 and, $C3H18$ by 2 and $O2$ by 15. Equation becomes:

$2C3H18(l)+15O2(g)→6CO2(g)+18H2O(l)$

Thus, number of carbon atoms, oxygen atoms and hydrogen atoms are equal on both sides of the reaction.

Interpretation Introduction

(b)

Interpretation:

Complete and balance the given chemical reaction.

$CH3Cl(g)+Cl2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

Substitution reactions are those reactions in which or more hydrogen atoms are replaced by other atoms such as halogen.

Expert Solution

Answer to Problem 38QAP

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$ .

Explanation of Solution

The complete reaction is given as:

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$

Above reaction is the second step of successively reaction of methane with chlorine (one hydrogen atom is replaced by chlorine atom). Here, stands for ultraviolet light which is required to break the bond between (Cl₂ ) two chlorine atoms and from two chlorine radicals.

$Cl-Cl→Cl.+Cl.$

Now, balance the above reaction, number of carbon atom is 1 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 3 on reactant side and on product side number of hydrogen atom is 3. Number of chlorine atom is 3 on reactant side and on product side number of chlorine atom is 3.

Thus, reaction is already balanced.

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$

Thus, number of carbon atoms, chlorine atoms and hydrogen atoms are equal on both sides of the reaction.

Interpretation Introduction

(c)

Interpretation:

Complete and balance the given chemical reaction.

$CHCl3(g)+Cl2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

Substitution reactions are those reactions in which or more hydrogen atoms are replaced by other atoms such as halogen.

Expert Solution

Answer to Problem 38QAP

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$ .

Explanation of Solution

The complete reaction is given as:

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$

Above reaction is the last step of successively reaction of methane with chlorine (all the hydrogen atoms are replaced by chlorine atoms). Here, stands for ultraviolet light which is required to break the bond between (Cl₂ ) two chlorine atoms and from two chlorine radicals.

$Cl-Cl→Cl.+Cl.$

Now, balance the above reaction, number of carbon atom is 1 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 1 on reactant side and on product side number of hydrogen atom is 1. Number of chlorine atom is 5 on reactant side and on product side number of chlorine atom is 5.

Thus, reaction is already balanced.

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$

Thus, number of carbon atoms, chlorine atoms and hydrogen atoms are equal on both sides of the reaction.

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Answer 2

Question

Definition Definition Molecules that have multiple bonds between their carbon atoms. Alkenes are hydrocarbons with a double bond between two adjacent carbon atoms (R 2 C=CR 2 ), whereas alkynes are hydrocarbons with a triple bond between two adjacent carbon atoms R-C=C-R . These two groups are known as unsaturated hydrocarbons. They have fewer hydrogen atoms when compared with alkanes with same number of carbon atoms. The general molecular formula for an unsaturated hydrocarbon can be represented as C n H 2n +2 .

Chapter 20, Problem 38QAP

Interpretation Introduction

(a)

Interpretation:

Complete and balance the given chemical reaction.

$C3H18(l)+O2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

The reaction in which burning of hydrocarbons takes place in oxygen to release water and carbon dioxide is known combustion reaction of hydrocarbon.

Expert Solution

Answer to Problem 38QAP

$2C3H18(l)+15O2(g)→6CO2(g)+18H2O(l)$ .

Explanation of Solution

The complete reaction is shown below:

$C3H18(l)+O2(g)→CO2(g)+H2O(l)$

Now, balance the above reaction, number of carbon atom is 3 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 18 on reactant side and on product side number of hydrogen atom is 2. Number of oxygen atom is 2 on reactant side and on product side number of oxygen atom is 3.

To balance the reaction, multiply $CO2$ by 16 and $H2O$ by 18 and, $C3H18$ by 2 and $O2$ by 15. Equation becomes:

$2C3H18(l)+15O2(g)→6CO2(g)+18H2O(l)$

Thus, number of carbon atoms, oxygen atoms and hydrogen atoms are equal on both sides of the reaction.

Interpretation Introduction

(b)

Interpretation:

Complete and balance the given chemical reaction.

$CH3Cl(g)+Cl2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

Substitution reactions are those reactions in which or more hydrogen atoms are replaced by other atoms such as halogen.

Expert Solution

Answer to Problem 38QAP

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$ .

Explanation of Solution

The complete reaction is given as:

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$

Above reaction is the second step of successively reaction of methane with chlorine (one hydrogen atom is replaced by chlorine atom). Here, stands for ultraviolet light which is required to break the bond between (Cl₂ ) two chlorine atoms and from two chlorine radicals.

$Cl-Cl→Cl.+Cl.$

Now, balance the above reaction, number of carbon atom is 1 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 3 on reactant side and on product side number of hydrogen atom is 3. Number of chlorine atom is 3 on reactant side and on product side number of chlorine atom is 3.

Thus, reaction is already balanced.

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$

Thus, number of carbon atoms, chlorine atoms and hydrogen atoms are equal on both sides of the reaction.

Interpretation Introduction

(c)

Interpretation:

Complete and balance the given chemical reaction.

$CHCl3(g)+Cl2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

Substitution reactions are those reactions in which or more hydrogen atoms are replaced by other atoms such as halogen.

Expert Solution

Answer to Problem 38QAP

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$ .

Explanation of Solution

The complete reaction is given as:

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$

Above reaction is the last step of successively reaction of methane with chlorine (all the hydrogen atoms are replaced by chlorine atoms). Here, stands for ultraviolet light which is required to break the bond between (Cl₂ ) two chlorine atoms and from two chlorine radicals.

$Cl-Cl→Cl.+Cl.$

Now, balance the above reaction, number of carbon atom is 1 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 1 on reactant side and on product side number of hydrogen atom is 1. Number of chlorine atom is 5 on reactant side and on product side number of chlorine atom is 5.

Thus, reaction is already balanced.

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$

Thus, number of carbon atoms, chlorine atoms and hydrogen atoms are equal on both sides of the reaction.

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Answer 3

Question

Definition Definition Molecules that have multiple bonds between their carbon atoms. Alkenes are hydrocarbons with a double bond between two adjacent carbon atoms (R 2 C=CR 2 ), whereas alkynes are hydrocarbons with a triple bond between two adjacent carbon atoms R-C=C-R . These two groups are known as unsaturated hydrocarbons. They have fewer hydrogen atoms when compared with alkanes with same number of carbon atoms. The general molecular formula for an unsaturated hydrocarbon can be represented as C n H 2n +2 .

Chapter 20, Problem 38QAP

Interpretation Introduction

(a)

Interpretation:

Complete and balance the given chemical reaction.

$C3H18(l)+O2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

The reaction in which burning of hydrocarbons takes place in oxygen to release water and carbon dioxide is known combustion reaction of hydrocarbon.

Expert Solution

Answer to Problem 38QAP

$2C3H18(l)+15O2(g)→6CO2(g)+18H2O(l)$ .

Explanation of Solution

The complete reaction is shown below:

$C3H18(l)+O2(g)→CO2(g)+H2O(l)$

Now, balance the above reaction, number of carbon atom is 3 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 18 on reactant side and on product side number of hydrogen atom is 2. Number of oxygen atom is 2 on reactant side and on product side number of oxygen atom is 3.

To balance the reaction, multiply $CO2$ by 16 and $H2O$ by 18 and, $C3H18$ by 2 and $O2$ by 15. Equation becomes:

$2C3H18(l)+15O2(g)→6CO2(g)+18H2O(l)$

Thus, number of carbon atoms, oxygen atoms and hydrogen atoms are equal on both sides of the reaction.

Interpretation Introduction

(b)

Interpretation:

Complete and balance the given chemical reaction.

$CH3Cl(g)+Cl2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

Substitution reactions are those reactions in which or more hydrogen atoms are replaced by other atoms such as halogen.

Expert Solution

Answer to Problem 38QAP

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$ .

Explanation of Solution

The complete reaction is given as:

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$

Above reaction is the second step of successively reaction of methane with chlorine (one hydrogen atom is replaced by chlorine atom). Here, stands for ultraviolet light which is required to break the bond between (Cl₂ ) two chlorine atoms and from two chlorine radicals.

$Cl-Cl→Cl.+Cl.$

Now, balance the above reaction, number of carbon atom is 1 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 3 on reactant side and on product side number of hydrogen atom is 3. Number of chlorine atom is 3 on reactant side and on product side number of chlorine atom is 3.

Thus, reaction is already balanced.

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$

Thus, number of carbon atoms, chlorine atoms and hydrogen atoms are equal on both sides of the reaction.

Interpretation Introduction

(c)

Interpretation:

Complete and balance the given chemical reaction.

$CHCl3(g)+Cl2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

Substitution reactions are those reactions in which or more hydrogen atoms are replaced by other atoms such as halogen.

Expert Solution

Answer to Problem 38QAP

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$ .

Explanation of Solution

The complete reaction is given as:

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$

Above reaction is the last step of successively reaction of methane with chlorine (all the hydrogen atoms are replaced by chlorine atoms). Here, stands for ultraviolet light which is required to break the bond between (Cl₂ ) two chlorine atoms and from two chlorine radicals.

$Cl-Cl→Cl.+Cl.$

Now, balance the above reaction, number of carbon atom is 1 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 1 on reactant side and on product side number of hydrogen atom is 1. Number of chlorine atom is 5 on reactant side and on product side number of chlorine atom is 5.

Thus, reaction is already balanced.

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$

Thus, number of carbon atoms, chlorine atoms and hydrogen atoms are equal on both sides of the reaction.

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Answer 4

Question

Definition Definition Molecules that have multiple bonds between their carbon atoms. Alkenes are hydrocarbons with a double bond between two adjacent carbon atoms (R 2 C=CR 2 ), whereas alkynes are hydrocarbons with a triple bond between two adjacent carbon atoms R-C=C-R . These two groups are known as unsaturated hydrocarbons. They have fewer hydrogen atoms when compared with alkanes with same number of carbon atoms. The general molecular formula for an unsaturated hydrocarbon can be represented as C n H 2n +2 .

Chapter 20, Problem 38QAP

Interpretation Introduction

(a)

Interpretation:

Complete and balance the given chemical reaction.

$C3H18(l)+O2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

The reaction in which burning of hydrocarbons takes place in oxygen to release water and carbon dioxide is known combustion reaction of hydrocarbon.

Expert Solution

Answer to Problem 38QAP

$2C3H18(l)+15O2(g)→6CO2(g)+18H2O(l)$ .

Explanation of Solution

The complete reaction is shown below:

$C3H18(l)+O2(g)→CO2(g)+H2O(l)$

Now, balance the above reaction, number of carbon atom is 3 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 18 on reactant side and on product side number of hydrogen atom is 2. Number of oxygen atom is 2 on reactant side and on product side number of oxygen atom is 3.

To balance the reaction, multiply $CO2$ by 16 and $H2O$ by 18 and, $C3H18$ by 2 and $O2$ by 15. Equation becomes:

$2C3H18(l)+15O2(g)→6CO2(g)+18H2O(l)$

Thus, number of carbon atoms, oxygen atoms and hydrogen atoms are equal on both sides of the reaction.

Interpretation Introduction

(b)

Interpretation:

Complete and balance the given chemical reaction.

$CH3Cl(g)+Cl2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

Substitution reactions are those reactions in which or more hydrogen atoms are replaced by other atoms such as halogen.

Expert Solution

Answer to Problem 38QAP

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$ .

Explanation of Solution

The complete reaction is given as:

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$

Above reaction is the second step of successively reaction of methane with chlorine (one hydrogen atom is replaced by chlorine atom). Here, stands for ultraviolet light which is required to break the bond between (Cl₂ ) two chlorine atoms and from two chlorine radicals.

$Cl-Cl→Cl.+Cl.$

Now, balance the above reaction, number of carbon atom is 1 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 3 on reactant side and on product side number of hydrogen atom is 3. Number of chlorine atom is 3 on reactant side and on product side number of chlorine atom is 3.

Thus, reaction is already balanced.

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$

Thus, number of carbon atoms, chlorine atoms and hydrogen atoms are equal on both sides of the reaction.

Interpretation Introduction

(c)

Interpretation:

Complete and balance the given chemical reaction.

$CHCl3(g)+Cl2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

Substitution reactions are those reactions in which or more hydrogen atoms are replaced by other atoms such as halogen.

Expert Solution

Answer to Problem 38QAP

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$ .

Explanation of Solution

The complete reaction is given as:

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$

Above reaction is the last step of successively reaction of methane with chlorine (all the hydrogen atoms are replaced by chlorine atoms). Here, stands for ultraviolet light which is required to break the bond between (Cl₂ ) two chlorine atoms and from two chlorine radicals.

$Cl-Cl→Cl.+Cl.$

Now, balance the above reaction, number of carbon atom is 1 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 1 on reactant side and on product side number of hydrogen atom is 1. Number of chlorine atom is 5 on reactant side and on product side number of chlorine atom is 5.

Thus, reaction is already balanced.

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$

Thus, number of carbon atoms, chlorine atoms and hydrogen atoms are equal on both sides of the reaction.

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Answer 5

Chapter 20, Problem 38QAP

Interpretation Introduction

(a)

Interpretation:

Complete and balance the given chemical reaction.

$C3H18(l)+O2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

The reaction in which burning of hydrocarbons takes place in oxygen to release water and carbon dioxide is known combustion reaction of hydrocarbon.

Expert Solution

Answer to Problem 38QAP

$2C3H18(l)+15O2(g)→6CO2(g)+18H2O(l)$ .

Explanation of Solution

The complete reaction is shown below:

$C3H18(l)+O2(g)→CO2(g)+H2O(l)$

Now, balance the above reaction, number of carbon atom is 3 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 18 on reactant side and on product side number of hydrogen atom is 2. Number of oxygen atom is 2 on reactant side and on product side number of oxygen atom is 3.

To balance the reaction, multiply $CO2$ by 16 and $H2O$ by 18 and, $C3H18$ by 2 and $O2$ by 15. Equation becomes:

$2C3H18(l)+15O2(g)→6CO2(g)+18H2O(l)$

Thus, number of carbon atoms, oxygen atoms and hydrogen atoms are equal on both sides of the reaction.

Interpretation Introduction

(b)

Interpretation:

Complete and balance the given chemical reaction.

$CH3Cl(g)+Cl2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

Substitution reactions are those reactions in which or more hydrogen atoms are replaced by other atoms such as halogen.

Expert Solution

Answer to Problem 38QAP

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$ .

Explanation of Solution

The complete reaction is given as:

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$

Above reaction is the second step of successively reaction of methane with chlorine (one hydrogen atom is replaced by chlorine atom). Here, stands for ultraviolet light which is required to break the bond between (Cl₂ ) two chlorine atoms and from two chlorine radicals.

$Cl-Cl→Cl.+Cl.$

Now, balance the above reaction, number of carbon atom is 1 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 3 on reactant side and on product side number of hydrogen atom is 3. Number of chlorine atom is 3 on reactant side and on product side number of chlorine atom is 3.

Thus, reaction is already balanced.

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$

Thus, number of carbon atoms, chlorine atoms and hydrogen atoms are equal on both sides of the reaction.

Interpretation Introduction

(c)

Interpretation:

Complete and balance the given chemical reaction.

$CHCl3(g)+Cl2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

Substitution reactions are those reactions in which or more hydrogen atoms are replaced by other atoms such as halogen.

Expert Solution

Answer to Problem 38QAP

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$ .

Explanation of Solution

The complete reaction is given as:

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$

Above reaction is the last step of successively reaction of methane with chlorine (all the hydrogen atoms are replaced by chlorine atoms). Here, stands for ultraviolet light which is required to break the bond between (Cl₂ ) two chlorine atoms and from two chlorine radicals.

$Cl-Cl→Cl.+Cl.$

Now, balance the above reaction, number of carbon atom is 1 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 1 on reactant side and on product side number of hydrogen atom is 1. Number of chlorine atom is 5 on reactant side and on product side number of chlorine atom is 5.

Thus, reaction is already balanced.

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$

Thus, number of carbon atoms, chlorine atoms and hydrogen atoms are equal on both sides of the reaction.

Answer 6

Chapter 20, Problem 38QAP

Interpretation Introduction

(a)

Interpretation:

Complete and balance the given chemical reaction.

$C3H18(l)+O2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

The reaction in which burning of hydrocarbons takes place in oxygen to release water and carbon dioxide is known combustion reaction of hydrocarbon.

Expert Solution

Answer to Problem 38QAP

$2C3H18(l)+15O2(g)→6CO2(g)+18H2O(l)$ .

Explanation of Solution

The complete reaction is shown below:

$C3H18(l)+O2(g)→CO2(g)+H2O(l)$

Now, balance the above reaction, number of carbon atom is 3 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 18 on reactant side and on product side number of hydrogen atom is 2. Number of oxygen atom is 2 on reactant side and on product side number of oxygen atom is 3.

To balance the reaction, multiply $CO2$ by 16 and $H2O$ by 18 and, $C3H18$ by 2 and $O2$ by 15. Equation becomes:

$2C3H18(l)+15O2(g)→6CO2(g)+18H2O(l)$

Thus, number of carbon atoms, oxygen atoms and hydrogen atoms are equal on both sides of the reaction.

Answer 7

Chapter 20, Problem 38QAP

Interpretation Introduction

(a)

Interpretation:

Complete and balance the given chemical reaction.

$C3H18(l)+O2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

The reaction in which burning of hydrocarbons takes place in oxygen to release water and carbon dioxide is known combustion reaction of hydrocarbon.

Answer 8

Expert Solution

Answer to Problem 38QAP

$2C3H18(l)+15O2(g)→6CO2(g)+18H2O(l)$ .

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The complete reaction is shown below:

$C3H18(l)+O2(g)→CO2(g)+H2O(l)$

Now, balance the above reaction, number of carbon atom is 3 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 18 on reactant side and on product side number of hydrogen atom is 2. Number of oxygen atom is 2 on reactant side and on product side number of oxygen atom is 3.

To balance the reaction, multiply $CO2$ by 16 and $H2O$ by 18 and, $C3H18$ by 2 and $O2$ by 15. Equation becomes:

$2C3H18(l)+15O2(g)→6CO2(g)+18H2O(l)$

Thus, number of carbon atoms, oxygen atoms and hydrogen atoms are equal on both sides of the reaction.

Answer 13

Interpretation Introduction

(b)

Interpretation:

Complete and balance the given chemical reaction.

$CH3Cl(g)+Cl2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

Substitution reactions are those reactions in which or more hydrogen atoms are replaced by other atoms such as halogen.

Expert Solution

Answer to Problem 38QAP

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$ .

Explanation of Solution

The complete reaction is given as:

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$

Above reaction is the second step of successively reaction of methane with chlorine (one hydrogen atom is replaced by chlorine atom). Here, stands for ultraviolet light which is required to break the bond between (Cl₂ ) two chlorine atoms and from two chlorine radicals.

$Cl-Cl→Cl.+Cl.$

Now, balance the above reaction, number of carbon atom is 1 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 3 on reactant side and on product side number of hydrogen atom is 3. Number of chlorine atom is 3 on reactant side and on product side number of chlorine atom is 3.

Thus, reaction is already balanced.

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$

Thus, number of carbon atoms, chlorine atoms and hydrogen atoms are equal on both sides of the reaction.

Answer 14

Interpretation Introduction

(b)

Interpretation:

Complete and balance the given chemical reaction.

$CH3Cl(g)+Cl2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

Substitution reactions are those reactions in which or more hydrogen atoms are replaced by other atoms such as halogen.

Answer 15

Expert Solution

Answer to Problem 38QAP

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$ .

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

The complete reaction is given as:

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$

Above reaction is the second step of successively reaction of methane with chlorine (one hydrogen atom is replaced by chlorine atom). Here, stands for ultraviolet light which is required to break the bond between (Cl₂ ) two chlorine atoms and from two chlorine radicals.

$Cl-Cl→Cl.+Cl.$

Now, balance the above reaction, number of carbon atom is 1 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 3 on reactant side and on product side number of hydrogen atom is 3. Number of chlorine atom is 3 on reactant side and on product side number of chlorine atom is 3.

Thus, reaction is already balanced.

$CH3Cl(g)+Cl2(g)→hvCH2Cl2(l)+HCl(g)$

Thus, number of carbon atoms, chlorine atoms and hydrogen atoms are equal on both sides of the reaction.

Answer 20

Interpretation Introduction

(c)

Interpretation:

Complete and balance the given chemical reaction.

$CHCl3(g)+Cl2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

Substitution reactions are those reactions in which or more hydrogen atoms are replaced by other atoms such as halogen.

Expert Solution

Answer to Problem 38QAP

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$ .

Explanation of Solution

The complete reaction is given as:

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$

Above reaction is the last step of successively reaction of methane with chlorine (all the hydrogen atoms are replaced by chlorine atoms). Here, stands for ultraviolet light which is required to break the bond between (Cl₂ ) two chlorine atoms and from two chlorine radicals.

$Cl-Cl→Cl.+Cl.$

Now, balance the above reaction, number of carbon atom is 1 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 1 on reactant side and on product side number of hydrogen atom is 1. Number of chlorine atom is 5 on reactant side and on product side number of chlorine atom is 5.

Thus, reaction is already balanced.

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$

Thus, number of carbon atoms, chlorine atoms and hydrogen atoms are equal on both sides of the reaction.

Answer 21

Interpretation Introduction

(c)

Interpretation:

Complete and balance the given chemical reaction.

$CHCl3(g)+Cl2(g)→$ .

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

Substitution reactions are those reactions in which or more hydrogen atoms are replaced by other atoms such as halogen.

Answer 22

Expert Solution

Answer to Problem 38QAP

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$ .

Answer 23

Expert Solution

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

The complete reaction is given as:

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$

Above reaction is the last step of successively reaction of methane with chlorine (all the hydrogen atoms are replaced by chlorine atoms). Here, stands for ultraviolet light which is required to break the bond between (Cl₂ ) two chlorine atoms and from two chlorine radicals.

$Cl-Cl→Cl.+Cl.$

Now, balance the above reaction, number of carbon atom is 1 on reactant side and on product side number of carbon atom is 1. Similarly, number of hydrogen atom is 1 on reactant side and on product side number of hydrogen atom is 1. Number of chlorine atom is 5 on reactant side and on product side number of chlorine atom is 5.

Thus, reaction is already balanced.

$CHCl3(g)+Cl2(g)→hvCCl4(l)+HCl(g)$