The name and structure of the alditol formed by reduction of NaBH 4 D-fructose other than the D-sorbitol should be determined. Concept Introduction: The sodium borohydride is a reducing agent, so it reduces the functional group present in the carbohydrate and itself get oxidized. The reduction of aldehyde results in the formation of alcohol because reduction can also be defined as addition of hydrogen atom thus, -CHO group becomes -CH 2 OH after addition of two hydrogen atoms on carbonyl carbon of the aldehydic group.

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Disaccharides are formed from two monosaccharides that are held glycosidic bond. Glycosidic bonds are found only in carbohydr Work on your own. Look at the molecules labelled A and B. Figure 2 Structural formula for glucose showing how (a) a chain becomes (b) a fg OH-C-H HO H-C-OH H-C-OH OH "CH,OH e diagr nosac es up mbine Identify monosaccharides Activity 1 OH HH ОН ОН H OH O C-C-C-C-C-C-H H-C-C-C н ОН ОН Н H. H H HO. molecule A molecule B Explain why both molecules A and B are carbohydrates. Which molecule is a triose and which is a hexose? Explain yu Write down the chemical formula for each molecule. Explain why both molecules A and B are monosaccharides Disaccharides nk the monosaccharides together. Table 2 on page 47 ch homic

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Chapter 20, Problem 20.36P

Interpretation Introduction

Interpretation:

The name and structure of the alditol formed by reduction of NaBH4 D-fructose other than the D-sorbitol should be determined.

Concept Introduction:

The sodium borohydride is a reducing agent, so it reduces the functional group present in the carbohydrate and itself get oxidized.

The reduction of aldehyde results in the formation of alcohol because reduction can also be defined as addition of hydrogen atom thus, -CHO group becomes -CH₂ OH after addition of two hydrogen atoms on carbonyl carbon of the aldehydic group.

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