Among the given two molecules, the major product that is formed by 1 , 2 -addition of HCl to cyclopentadiene has to be found and explained. Concept Introduction: Addition reaction of dienes: The diene with a four carbon system is 1,3-butadiene . When it is allowed to react with two moles of HBr , it undergoes two type of addition reactions such as 1,2-addition and 1,4-addition as shown here: 1,3-butadiene reacts with H-Br and formed a resonance stabilized carbocation. The addition of a bromine atom to each of the two resonance forms has formed the corresponding product. So, two products are obtained. In one product the bromine atom has been attached to the 2 nd carbon atom indicating that it has been formed from 1,2-addition whereas in the other product, the bromine atom has been attached to the 1 st carbon atom indicating that it has been formed from 1,4-addition.

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> You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: 1. ☑ CI 2. H3O+ O Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. Explanation Check ? DO 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility

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Chapter 20, Problem 20.19P

Interpretation Introduction

Interpretation: Among the given two molecules, the major product that is formed by 1,2-addition of HCl to cyclopentadiene has to be found and explained.

Concept Introduction:

Addition reaction of dienes:

The diene with a four carbon system is 1,3-butadiene. When it is allowed to react with two moles of HBr, it undergoes two type of addition reactions such as 1,2-addition and 1,4-addition as shown here:

1,3-butadiene reacts with H-Br and formed a resonance stabilized carbocation. The addition of a bromine atom to each of the two resonance forms has formed the corresponding product. So, two products are obtained. In one product the bromine atom has been attached to the 2^nd carbon atom indicating that it has been formed from 1,2-addition whereas in the other product, the bromine atom has been attached to the 1^st carbon atom indicating that it has been formed from 1,4-addition.

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> You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: 1. ☑ CI 2. H3O+ O Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. Explanation Check ? DO 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility

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Consider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence point