Interpretation: Whether elements, compounds or mixtures are seen mostly in our surroundings like a kitchen and a park needs to be explained.
Concept Introduction: An element is a substance that cannot be decomposed further into simpler substances by any chemical process. On the other hand, compounds are composed of two or more elements. They can be decomposed into their elemental components. A mixture in solid, liquid, or gaseous form is said to be homogenous if it has the same proportions of components throughout the sample. Thus, in any homogenous mixture, only one phase of matter is observed. In heterogeneous mixtures, the components of the mixture can be easily identified. There is more than one phase and can be seen by the naked eye. It has a non-uniform composition.
Explanation of Solution
In the surrounding, there is the possibility of the presence of all elements, compounds, and mixtures. When we look around, the soil is an example of a mixture as it contains several elements and minerals. Another example of a mixture is air as it contains different gases and water. The swings in the park are made up of iron which is an element. Also, utensils in the kitchen are made up of iron and aluminum which are elements. There is water, salt, and other compounds like baking powder, dishwasher, etc. present in the kitchen; thus, we can see elements, compounds, and mixtures all around us.
Chapter 2 Solutions
EP CHEMISTRY-ETEXT ACCESS
- X Draw the major products of the elimination reaction below. If elimination would not occur at a significant rate, check the box under the drawing area instead. ది www. Cl + OH Elimination will not occur at a significant rate. Click and drag to start drawing a structure.arrow_forwardNonearrow_forward1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forward
- Nonearrow_forwardIV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forwardDo the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forward
- Predict and draw the product of the following organic reaction:arrow_forwardNonearrow_forwardRedraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forward
- K m Choose the best reagents to complete the following reaction. L ZI 0 Problem 4 of 11 A 1. NaOH 2. CH3CH2CH2NH2 1. HCI B OH 2. CH3CH2CH2NH2 DII F1 F2 F3 F4 F5 A F6 C CH3CH2CH2NH2 1. SOCl2 D 2. CH3CH2CH2NH2 1. CH3CH2CH2NH2 E 2. SOCl2 Done PrtScn Home End FA FQ 510 * PgUp M Submit PgDn F11arrow_forwardNonearrow_forwardPlease provide a mechanism of synthesis 1,4-diaminobenzene, start from a benzene ring.arrow_forward
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