INTRO TO GEN ANALYSIS W/ACHIEVE ACCESS
12th Edition
ISBN: 9781319423865
Author: Griffiths
Publisher: MAC HIGHER
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Chapter 2, Problem 56.6P
Summary Introduction
To determine: The various assumptions that are needed for complete pedigree analysis.
Introduction: Risk analysis of a particular disease for new generations is considered based on alleles that are carried by past generations. The information about the alleles gives complete information for an individual, whether an individual is prone to a particular disease or not.
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Salim and Sara are contemplating having children, but Salim’s brother has galactosemia and Sara’s great-grandmother also had galactosemia. Sara has a sister who has three children, none of whom is affected.
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Chapter 2 Solutions
INTRO TO GEN ANALYSIS W/ACHIEVE ACCESS
Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10P
Ch. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - Prob. 56.1PCh. 2 - Prob. 56.2PCh. 2 - Prob. 56.3PCh. 2 - Prob. 56.4PCh. 2 - Prob. 56.5PCh. 2 - Prob. 56.6PCh. 2 - Prob. 56.7PCh. 2 - Prob. 56.8PCh. 2 - Prob. 56.9PCh. 2 - Prob. 56.10PCh. 2 - Prob. 56.11PCh. 2 - Prob. 56.12PCh. 2 - Prob. 56.13PCh. 2 - Prob. 56.14PCh. 2 - Prob. 56.15PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 71PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79PCh. 2 - Prob. 80PCh. 2 - Prob. 81PCh. 2 - Prob. 82PCh. 2 - Prob. 83PCh. 2 - Prob. 84PCh. 2 - Prob. 85PCh. 2 - Prob. 86PCh. 2 - Prob. 87PCh. 2 - Prob. 88PCh. 2 - Prob. 89PCh. 2 - Prob. 90PCh. 2 - Prob. 91PCh. 2 - Prob. 1GSCh. 2 - Prob. 2GSCh. 2 - Prob. 3GS
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- Bob and Joan know from a blood test that they are each heterozygous (carriers) for the autosomal recessive gene that causes sickle cell disease. If their first three children are healthy, what is the probability that their fourth child will have the disease?arrow_forwardSalim and Sara are contemplating having children, but Salim’s brother has galactosemia and Sara has a sister who has three children, none of whom is affected. Sara dad has no history in his family of any sign of the diease and it is assumed to be homozygous normal. What is the probability that salim and saras first child will have galactosemia?arrow_forwardSalim and Sara are contemplating having children, but Salim’s brother has galactosemia and Sara has a sister who has three children, one of whom is affected. Sara dad has no history in his family of any sign of the diease and it is assumed to be homozygous normal. What is the probability that salim and saras first child will have galactosemia?arrow_forward
- what is the probability that a couple (both heterozygous for the same recessive mutation) will have two children with the disease if the couple plans to have four children in total?arrow_forwardMartin and Sue are contemplating having children, but Martin’s brother has an autosomal recessive disease and Sue’s great-grandmother also had the same disease. Sue has a sister who has three normal, healthy children. What is the probability that Martin and Sue’s first child will have the autosomal recessive disease? HINT draws out pedigree charts and punnett squares for Martin and Sue.arrow_forwardAlong with the trait in the pedigree, individual IV-6 and the woman are also both heterozygous for the autosomal dominant allele causing Huntington's disease. If they have a child, what is the probability that it will be affected by at least one of these traits? Remember to include both the trait in the pedigree and Huntington's disease in your calculations. Enter your answer to two decimal places (e.g., 0.55).arrow_forward
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- A recently married couple are both heterozygous for cystic fibrosis, a recessive genetic disorder. They would like to start a family and would like to have two children. a.) What is the probability that their second pregnancy would result in a child with cystic fibrosis? b.) What is the probability that their second pregnancy would result in a child with cystic fibrosis?arrow_forwardMark has an autosomal recessive condition called sickle cell anemia, a serious blood disorder that is associated with painful complications. His spouse has not experienced symptoms of sickle cell anemia but their first child developed the disease. What conclusions can be drawn about the mother's genotype and the probability of having a second child with the condition? Answer Choices: A: her genotype is heterozygous and there is a 25% percent chance of having another child with the disorder B: her genotype is heterozygous and there is a 50% percent chance of having another child with the disorder C: her genotype is heterozygous and there is a 75% percent chance of having another child with the disorder D: she lacks the allele for sickle cell anemia in that she lacks symptoms of the disease. There is a 0% percent chance of having another child with the disorderMark has an autosomal recessive condition called sickle cell anemia, a serious blood disorder that is associated with…arrow_forwardInigo Montoya is healthy but his mother had the recessive condition, cystic fibrosis, which is autosomal. Buttercup marries Inigo and through genetic testing finds out that she is a carrier of the allele causing cystic fibrosis. What is the probability that their first three children will have cystic fibrosis? Show your calculations.arrow_forward
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