The genotypes of the family members. Introduction: The dominant characters in the genotypes are represented by “PP”. Recessive characters are represented by letter “pp”. However, the heterozygous characters are represented by the “Pp”. The outsiders are also considered healthy and dominant and unknown genotypes are represented by P.

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Answer 1

Question

Chapter 2, Problem 67P

a.

Summary Introduction

To list: The genotypes of the family members.

Introduction: The dominant characters in the genotypes are represented by “PP”. Recessive characters are represented by letter “pp”. However, the heterozygous characters are represented by the “Pp”. The outsiders are also considered healthy and dominant and unknown genotypes are represented by P.

b.

Summary Introduction

To determine: The probability of the first child to have the PKU, when person A and B marry.

Introduction: Phenylketonuria is an autosomal recessive condition which is caused due to alteration of metabolic amino acid. The metabolism of the phenylketonuria becomes reduced which creates mental disorders, intellectual disabilities, and lighting the skin.

c.

Summary Introduction

To determine: The probability of the second child to be unaffected when first child is diseased.

Introduction: Generally, a child to be diseased requires both the parents to be factor causing the disease. It is not necessary that parents will exhibit the signs, but without showing signs, parents can transmit the disease to progenies. The parents of the children can either be diseased or carrier.

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Answer 2

Question

Chapter 2, Problem 67P

a.

Summary Introduction

To list: The genotypes of the family members.

Introduction: The dominant characters in the genotypes are represented by “PP”. Recessive characters are represented by letter “pp”. However, the heterozygous characters are represented by the “Pp”. The outsiders are also considered healthy and dominant and unknown genotypes are represented by P.

b.

Summary Introduction

To determine: The probability of the first child to have the PKU, when person A and B marry.

Introduction: Phenylketonuria is an autosomal recessive condition which is caused due to alteration of metabolic amino acid. The metabolism of the phenylketonuria becomes reduced which creates mental disorders, intellectual disabilities, and lighting the skin.

c.

Summary Introduction

To determine: The probability of the second child to be unaffected when first child is diseased.

Introduction: Generally, a child to be diseased requires both the parents to be factor causing the disease. It is not necessary that parents will exhibit the signs, but without showing signs, parents can transmit the disease to progenies. The parents of the children can either be diseased or carrier.

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Answer 3

Question

Chapter 2, Problem 67P

a.

Summary Introduction

To list: The genotypes of the family members.

Introduction: The dominant characters in the genotypes are represented by “PP”. Recessive characters are represented by letter “pp”. However, the heterozygous characters are represented by the “Pp”. The outsiders are also considered healthy and dominant and unknown genotypes are represented by P.

b.

Summary Introduction

To determine: The probability of the first child to have the PKU, when person A and B marry.

Introduction: Phenylketonuria is an autosomal recessive condition which is caused due to alteration of metabolic amino acid. The metabolism of the phenylketonuria becomes reduced which creates mental disorders, intellectual disabilities, and lighting the skin.

c.

Summary Introduction

To determine: The probability of the second child to be unaffected when first child is diseased.

Introduction: Generally, a child to be diseased requires both the parents to be factor causing the disease. It is not necessary that parents will exhibit the signs, but without showing signs, parents can transmit the disease to progenies. The parents of the children can either be diseased or carrier.

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Answer 4

Question

Chapter 2, Problem 67P

a.

Summary Introduction

To list: The genotypes of the family members.

Introduction: The dominant characters in the genotypes are represented by “PP”. Recessive characters are represented by letter “pp”. However, the heterozygous characters are represented by the “Pp”. The outsiders are also considered healthy and dominant and unknown genotypes are represented by P.

b.

Summary Introduction

To determine: The probability of the first child to have the PKU, when person A and B marry.

Introduction: Phenylketonuria is an autosomal recessive condition which is caused due to alteration of metabolic amino acid. The metabolism of the phenylketonuria becomes reduced which creates mental disorders, intellectual disabilities, and lighting the skin.

c.

Summary Introduction

To determine: The probability of the second child to be unaffected when first child is diseased.

Introduction: Generally, a child to be diseased requires both the parents to be factor causing the disease. It is not necessary that parents will exhibit the signs, but without showing signs, parents can transmit the disease to progenies. The parents of the children can either be diseased or carrier.

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Answer 5

Chapter 2, Problem 67P

a.

Summary Introduction

To list: The genotypes of the family members.

Introduction: The dominant characters in the genotypes are represented by “PP”. Recessive characters are represented by letter “pp”. However, the heterozygous characters are represented by the “Pp”. The outsiders are also considered healthy and dominant and unknown genotypes are represented by P.

b.

Summary Introduction

To determine: The probability of the first child to have the PKU, when person A and B marry.

Introduction: Phenylketonuria is an autosomal recessive condition which is caused due to alteration of metabolic amino acid. The metabolism of the phenylketonuria becomes reduced which creates mental disorders, intellectual disabilities, and lighting the skin.

c.

Summary Introduction

To determine: The probability of the second child to be unaffected when first child is diseased.

Introduction: Generally, a child to be diseased requires both the parents to be factor causing the disease. It is not necessary that parents will exhibit the signs, but without showing signs, parents can transmit the disease to progenies. The parents of the children can either be diseased or carrier.

Answer 6

Chapter 2, Problem 67P

a.

Summary Introduction

To list: The genotypes of the family members.

Introduction: The dominant characters in the genotypes are represented by “PP”. Recessive characters are represented by letter “pp”. However, the heterozygous characters are represented by the “Pp”. The outsiders are also considered healthy and dominant and unknown genotypes are represented by P.

Answer 7

Chapter 2, Problem 67P

a.

Summary Introduction

To list: The genotypes of the family members.

Introduction: The dominant characters in the genotypes are represented by “PP”. Recessive characters are represented by letter “pp”. However, the heterozygous characters are represented by the “Pp”. The outsiders are also considered healthy and dominant and unknown genotypes are represented by P.

Answer 8

b.

Summary Introduction

To determine: The probability of the first child to have the PKU, when person A and B marry.

Introduction: Phenylketonuria is an autosomal recessive condition which is caused due to alteration of metabolic amino acid. The metabolism of the phenylketonuria becomes reduced which creates mental disorders, intellectual disabilities, and lighting the skin.

Answer 9

b.

Summary Introduction

To determine: The probability of the first child to have the PKU, when person A and B marry.

Introduction: Phenylketonuria is an autosomal recessive condition which is caused due to alteration of metabolic amino acid. The metabolism of the phenylketonuria becomes reduced which creates mental disorders, intellectual disabilities, and lighting the skin.

Answer 10

c.

Summary Introduction

To determine: The probability of the second child to be unaffected when first child is diseased.

Introduction: Generally, a child to be diseased requires both the parents to be factor causing the disease. It is not necessary that parents will exhibit the signs, but without showing signs, parents can transmit the disease to progenies. The parents of the children can either be diseased or carrier.

Answer 11

c.

Summary Introduction

To determine: The probability of the second child to be unaffected when first child is diseased.

Introduction: Generally, a child to be diseased requires both the parents to be factor causing the disease. It is not necessary that parents will exhibit the signs, but without showing signs, parents can transmit the disease to progenies. The parents of the children can either be diseased or carrier.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 2 - Prob. 1P Ch. 2 - Prob. 2P Ch. 2 - Prob. 3P Ch. 2 - Prob. 4P Ch. 2 - Prob. 5P Ch. 2 - Prob. 6P Ch. 2 - Prob. 7P Ch. 2 - Prob. 8P Ch. 2 - Prob. 9P Ch. 2 - Prob. 10P

Solution Summary: The author explains the genotypes of the family members, including dominant, heterozygous, and unknown.

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