INTRO TO GEN ANALYSIS W/ACHIEVE ACCESS
12th Edition
ISBN: 9781319423865
Author: Griffiths
Publisher: MAC HIGHER
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Chapter 2, Problem 56.12P
Summary Introduction
To determine: The difference in the pedigree of Person J’s and Person M’s families.
Introduction: The pedigree of each family is different, as it depends on the alleles that are carried by each generation of a family. The occurrence of a particular disorder in certain generations depends on the inheritance pattern of the family.
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Kate and her husband are both heterozygous for galactosemia gene. If Kate and her husband have four children, how many of their children are likely to have galactosemia?
Martin and Sue are contemplating having children, but Martin’s brother has an autosomal recessive disease and Sue’s great-grandmother also had the same disease. Sue has a sister who has three normal, healthy children. What is the probability that Martin and Sue’s first child will have the autosomal recessive disease? HINT draws out pedigree charts and punnett squares for Martin and Sue.
The second pedigree involves albinism, an autosomal recessive trait. A couple has a son with normal pigmentation, a daughter with normal pigmentation, and an albino son. Another couple has three children, a son with normal pigmentation and two daughters with normal pigmentation. The daughter from the first couple marries the man from the second couple and they have three children together: an albino son, an albino daughter, and a daughter with normal pigmentation.Draw the pedigree on the next page
Chapter 2 Solutions
INTRO TO GEN ANALYSIS W/ACHIEVE ACCESS
Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10P
Ch. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - Prob. 56.1PCh. 2 - Prob. 56.2PCh. 2 - Prob. 56.3PCh. 2 - Prob. 56.4PCh. 2 - Prob. 56.5PCh. 2 - Prob. 56.6PCh. 2 - Prob. 56.7PCh. 2 - Prob. 56.8PCh. 2 - Prob. 56.9PCh. 2 - Prob. 56.10PCh. 2 - Prob. 56.11PCh. 2 - Prob. 56.12PCh. 2 - Prob. 56.13PCh. 2 - Prob. 56.14PCh. 2 - Prob. 56.15PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 71PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79PCh. 2 - Prob. 80PCh. 2 - Prob. 81PCh. 2 - Prob. 82PCh. 2 - Prob. 83PCh. 2 - Prob. 84PCh. 2 - Prob. 85PCh. 2 - Prob. 86PCh. 2 - Prob. 87PCh. 2 - Prob. 88PCh. 2 - Prob. 89PCh. 2 - Prob. 90PCh. 2 - Prob. 91PCh. 2 - Prob. 1GSCh. 2 - Prob. 2GSCh. 2 - Prob. 3GS
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- Does the phenotype indicated by the red circles and squares in this pedigree show an inheritance pattern that is autosomal dominant, autosomal recessive, or X-linked?arrow_forwardSalim and Sara are contemplating having children, but Salim’s brother has galactosemia and Sara’s great-grandmother also had galactosemia. Sara has a sister who has three children, none of whom is affected. What is the probability that Salim and Sara’s first child will have galactosemia? Explain your calculations.arrow_forwardCystic fibrosis is an autosomal recessive disorder that runs in Ann's family. Consider the figure of a pedigree of the known occurrences of cystic fibrosis in her family. Ann Filled (red) circles represent affected females. Filled (red) squares represent affected males. Unfilled (tan) circles, such as Ann's circle, represent symptomless females. Unfilled (tan) squares represent symptomless males.arrow_forward
- Bob and Joan know from a blood test that they are each heterozygous (carriers) for the autosomal recessive gene that causes sickle cell disease. If their first three children are healthy, what is the probability that their fourth child will have the disease?arrow_forwardA man and a woman have two children. One of the two children is a boy with sickle-cell disease. The other child is a girl without sickle-cell disease. Neither of the parents are affected. How would this family be represented in a pedigree? Multiple Choice A. Father = half shaded square, Mother = half shaded circle, Son = fully shaded square, Daughter = circle with a question mark B. Father = square with no shading, Mother = half shaded circle, Son = fully shaded square, Daugther = circle with a question mark C. Father = half shaded square, Mother = half shaded circle, Son = fully shaded square, Daughter = half shaded circle D. Father = square with no shading, Mother = half shaded circle, Son = half shaded square, Daughter = circle with no shadingarrow_forwardAnn's family has a history of cystic fibrosis, a recessive genetic disease. In the pedigree, family members who are afflicted with the disease are shown in red. Members who are unafflicted may or may not be carriers. Which of the given family members can be identified definitively as unafflicted carriers of cystic fibrosis?arrow_forward
- Muffy, a color blind female with blood type A (heterozygous to type O) is married to Biff, who is also color blind and is homozygous for type B blood. Muffy has been having an affair with their gardener, Raoul, who is heterozygous for type B blood and has normal vision. Recall that color blindness is a sex linked recessive condition. Please help Biff's attorney determine the father of each of the children for the divorce proceedings. Show ALL work using punnett squares. a) female, type A blood, normal vision b) male, type O blood, color blind c) female, type AB blood, color blindarrow_forwardHemophilia is caused by an X-linked recessive mutation in humans. If a man whose paternal uncle (father's brother) was a hemophiliac marries a woman whose brother is also a hemophiliac, what is the probability that their first child will have hemophilia? (Assume that no other cases of hemophilia exist in the pedigree.) 1/3 0 1/8 0 1/4 1/2arrow_forwardIs this pedigree dominant or recessive. Which best defines this pedigree Autosomal or sex-linked?arrow_forward
- Kelly and Sam are both unaffected carriers for two autosomal recessive disorders, PKU (chromosome 12) and cystic fibrosis (chromosome 7). They are expecting a daughter. What is the probability that she will be unaffected by PKU, but effected by cystic fibrosis? O 1/16 O 3/16 O 1/2 О 3/4 O 9/16arrow_forwardThe three genes X, Y, and Z are linked on an autosomal chromosome in humans (X to Y is 15 cM, and Y to Z is 18 cM). If an individual that is heterozygous at all three loci (XYZ/xyz) has children with an individual that is homozygous recessive at all three loci (xyz/xyz), what is the probability that they will have a child that is phenotypically identical to either parent (X-Y-Z- or xxyyzz)? Assume there is no genetic interference to double crossover events at this site.arrow_forwardIn a cross between an individual with Huntington disease and an unaffected individual, what are the chances their progeny will have the disease, considering that it is a dominant trait?arrow_forward
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