Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 2, Problem 42P
In chickens, the presence of feathers on the legs is due to a dominant allele (F), and the absence of leg feath-ers is due to a recessive allele (f). The comb on the top of the head can be either pea-shaped, a
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
In a species of plant, two genes control flower color. The redallele (R) is dominant to the white allele (r); the color-producingallele (C) is dominant to the non-color-producing allele (c). Yoususpect that either an rr homozygote or a cc homozygote willproduce white flowers. In other words, rr is epistatic to C, andcc is epistatic to R. To test your hypothesis, you allowed heterozygousplants (RrCc) to self-fertilize and counted the phenotypesof the offspring. You obtained the following data: 201 plantswith red flowers and 144 with white flowers. Conduct a chisquare test to see if your observed data are consistent with yourhypothesis.
In chickens, comb shape is determined by genes at two loci (R, r and P, p). A walnut comb is produced when at least one dominant gene R is present
at one locus and at least one dominant gene P is present at a second locus (genotype R_ P_). A rose comb is produced when at least one dominant
gene is present at the first locus and two recessive genes are present at the second locus (genotype R_ pp). A pea comb is produced when two
recessive genes are present at the first locus and at least one dominant gene is present at the second (genotype rr P_). If two recessive genes are
present at the first and the second locus (rr pp), a single comb is produced. Give genotypes for comb shape of the parents in the following cross:
Rose crossed with pea produces 20 walnut offspring.
O A. Rr pp x Rr Pp
B. Rr pp x rr PP
C. Rr pp x rr Pp
D. RR pp x rr PP
O E. RR pp x rr Pp
Reset Selection
Mark for Douiouu
In chickens, comb shape is determined by genes at two loci (Gene 1 has alleles R, r and Gene 2 has alleles P, p). A walnut comb is
produced when at least one dominant gene R is present at one locus and at least one dominant gene P is present at a second locus
(genotype R_P). The genotype R_pp gives a rose comb phenotype; rrP_gives a pea comb phenotype; and rrpp gives a single comb
phenotype. Based on this information give specific genotypes for comb shape of the parents in the crosses listed below:
A) Walnut crossed with single produces 1 walnut, 1 rose, 1 pea and 1 single offspring.
B) Rose crossed with pea produces 20 walnut offspring.
C) Pea crossed with single produces 1 single offspring.
Chapter 2 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. 2 -
1. Compare and contrast the following terms:
a....Ch. 2 - For the cross , what is the expected genotype...Ch. 2 - 37. Galactosemia is an autosomal recessive...Ch. 2 - In mice, black coat color is dominant to white...Ch. 2 - Two parents plan to have three children. What is...Ch. 2 - Consider the cross AaBbCCAABbCc. a. How many...Ch. 2 - If a chi-square test produces a chi-square value...Ch. 2 -
8. Determine whether the statements below are...Ch. 2 - In the datura plant, purple flower color is...Ch. 2 - 10. The dorsal pigment pattern of frogs can be...
Ch. 2 - 11. Black skin color is dominant to pink skin...Ch. 2 - A male mouse with brown fur color is mated to two...Ch. 2 - 13. Figure 2.12 shows the results of Mendel’s...Ch. 2 - 14. An experienced goldfish breeder receives two...Ch. 2 -
15. The accompanying pedigree shows the...Ch. 2 -
16. A geneticist crosses a pure-breeding strain...Ch. 2 - Suppose an F1 plant from Problem 16 is crossed to...Ch. 2 - 18. In pea plants, the appearance of flowers along...Ch. 2 - 19. If two six-sided dice are rolled, what is the...Ch. 2 - Experimental Insight 2.1 describes data, collected...Ch. 2 -
21. The accompanying pedigree shows the...Ch. 2 - 22. The seeds in bush bean pods are each the...Ch. 2 - List all the different gametes that are possible...Ch. 2 - Organisms with the genotypes AABbCcDd and AaBbCcDd...Ch. 2 - 25. Blue moon beans produce beans that are either...Ch. 2 - In the fruit fly Drosophila, a rudimentary wing...Ch. 2 - In pea plants, plant height, seed shape, and seed...Ch. 2 - A variety of pea plant called Blue Persian...Ch. 2 - 29. In tomato plants, the production of red fruit...Ch. 2 - A male and a female are each heterozygous for both...Ch. 2 - A woman expressing a dominant phenotype is...Ch. 2 - Two parents who are each known to be carriers of...Ch. 2 - 33. An organism having the genotype AaBbCcDdEe is...Ch. 2 - 34. A man and a woman are each heterozygous...Ch. 2 - For a single dice roll, there is a 16 chance that...Ch. 2 - You have four guinea pigs for a genetic study. One...Ch. 2 - 37. Galactosemia is an autosomal recessive...Ch. 2 - Sweet yellow tomatoes with a pear shape bring a...Ch. 2 - A cross between a spicy variety of Capsicum annum...Ch. 2 - Alkaptonuria is an infrequent autosomal recessive...Ch. 2 - 41. Humans vary in many ways from one another....Ch. 2 - 42. In chickens, the presence of feathers on the...Ch. 2 -
43. A pure-breeding fruit fly with the...Ch. 2 - 44. Situs inversus is a congenital condition in...Ch. 2 - 45. Domestic dogs evolved from ancestral grey...Ch. 2 - Alleles of the IGF-1 gene in dogs, encoding...Ch. 2 - 47. The accompanying pedigree shows a family in...Ch. 2 -
48. A pea plant that has the genotype RrGgwwdd is...Ch. 2 - Go to the OMIM website...Ch. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 -
52. In humans, the ability to bend the thumb...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- In Shorthorn cattle, coat color is controlled by a single gene thatcan exist as a red allele (R) or a white allele (r). The heterozygotes (Rr) have a color called roan that looks less red than theRR homozygotes. However, when examined carefully, the roanphenotype in cattle is actually due to a mixture of completelyred hairs and completely white hairs. Should this be calledincomplete dominance, codominance, or something else?Explain your reasoningarrow_forwardIn peaches fuzzy skin (F) is completely dominant to smooth, nectarine skin (f). The gland at the base of the leaves is controlled by a separate, unlinked locus. The gland in heterozygotes is round, while homozygotes with the Go allele have oval glands, and homozygotes with the the GN allele have no glands. A homozygous fuzzy, no-gland peach variety is bred to a smooth, oval-gland variety. The F1 offspring are interbred to produce the F2 generation. What fraction of the F2 offspring will be smooth with round glands? A) 3/16 B) 7/16 C) 4/16 D) 6/16 E) 9/16 F) 2/16 G) 12/16 H) 1/16arrow_forwardIn a species of plant, two genes control flower color. The red allele(R) is dominant to the white allele (r); the color-producing allele(C) is dominant to the non-color-producing allele (c). You suspectthat either an rr homozygote or a cc homozygote will producewhite flowers. In other words, rr is epistatic to C, and cc is epistatic to R. To test your hypothesis, you allow heterozygous plants(RrCc) to self-fertilize and count the offspring. You obtain the following data: 201 plants with red flowers and 144 with white flowers. Conduct a chi square analysis to see if your observed data areconsistent with your hypothesis.arrow_forward
- In mice, the wild-type coat color, agouti (AA) [left mouse], is dominant to solid-colored, black fur (aa) [middle mouse]. However, a separate gene (C) is necessary for pigment production. A mouse that is homozygous for a recessive c allele at this locus is unable to produce pigment and is albino [right mouse] regardless of the allele present at locus A. Thus, the following genotypes are listed with their associated phenotypes: ~ A/A; C/C or A/A; C/c or A/a; C/C or A/a; C/c ==> "agouti" ~ a/a; C/C or a/a; C/c ==> "black" ~ A/A; c/c or A/a; c/c or a/a; c/c or a/a; c/c ==> "albino" This is an example of recessive epistasis, in which the recessive c allele "stands upon" the possible genotypes for the A gene (A/A, A/a, or a/a). If two agouti mice with the A/a; C/c genotype are mated, what is the expected phenotypic ratio in their offspring? A.9 albino, 4 agouti, 3 black B. 9 agouti, 4 albino, 3 black C.9 black, 4 albino, 3 agouti D.9 agouti, 4 black, 3 albinoarrow_forwardThe production of eye-color pigment in Drosophila requires the dominant allele A. The dominant allele P of asecond independent gene turns the pigment to purple,but its recessive allele leaves it red. A fly producing nopigment has white eyes. Two pure lines were crossedwith the following results:P red-eyed female white-eyed maleF1 purple-eyed femalesred-eyed malesF1 F1purple eyed 38red eyed 38white eyed 28F both males and females: 2Explain this mode of inheritance, and show the genotypesof the parents, the F1, and the F2.arrow_forwardBronze coloured turkey is controlled by a dominant allele, B. Red coloured turkey is homozygous for a recessive allele bb. Dominant gene N produce normal feather and recessive genotype produce ‘hairy’ feather nn. In a cross between homozygous bronzed coloured turkey with ‘hairy’ feather and homozygous red coloured turkey with normal feather. What are the ratios of F2 progeny with Bbnn genotypes? (I want to check if what i'm doing is correct)arrow_forward
- Two hedgehog parents are heterozygous at the spiny locus, each with genotype Ss. This locus affects the length of the individuals’ spines, which ranges from 1 cm in SS homozygotes to 3 cm in ss homozygotes.Inheritance of spine length in this family is entirely due to the spiny locus and it exhibits additivity. Remember that development of spines depends on thousands of genes, but we’re only considering this one gene because it’s the one that varies in a way that affects spine length in this family. a) List all of the phenotypes we could observe among offspring of these Ss heterozygote parents. b) What’s the probability that an offspring of these heterozygous parents is an SS homozygote? c) If the parents have exactly two offspring, what is the probability that the two hedgehog kids have no alleles in common? In other words, what’s the probability that one kid is SS and the other ss?arrow_forwardNormal leg size, characteristic of Kerry-type cattle, is produced by homozygous genotype DD. Short-legged Dexter-type cattle possess the heterozygous genotype Dd. The homozygous genotype dd is lethal producing grossly deformed stillbirths called “bulldog calves”. The presence of horns in cattle is governed by the recessive allele of another gene locus p, the polled condition (absence of horn) being produced by its dominant allele P. In matings between polled Dexter cattle genotype DdPp, a) what expected ratio is expected in the adult progeny? b) what percentage of the progeny will carry the lethal allele? (for your answer use the format ex. a) 1/6 dexter, polled : 3/6 dexter, non polled.....b) 6/7arrow_forwardIn Drosophila fruit flies, the genes for warped wings (dwp), rumpled bristles (rmp), and pallid wings (pld) are linked. A trihybrid female for all three allleles is crossed with homozygous recessive male for all three alleles and the offspring obtained showed the following phenotypes: 3 pld rmp dwp 428 pld rmp + 427 + + dwp 48 + rmp + 47 pld + dwp 23 pld + + 2 + + + 22 + rmp dwp What is the order and map distance between these three alleles?arrow_forward
- In rabbits, white coat color (CW) and black coat color (CB) are codominant, and both of these alleles are dominant over albino (c); heterozygotes (CWCB) are spotted. Consider a cross between a heterozygous black-coated rabbit and a homozygous white-coated rabbit.arrow_forwardThe dominant allele H reduces the number of bodybristles in fruit flies, giving rise to a hairless phenotype. In the homozygous condition, H is lethal. Thedominant allele S has no effect on bristle number except in the presence of H, in which case a single S allele suppresses the hairless phenotype, thus restoringthe bristles. However, S is also lethal in homozygotes.a. What ratio of flies with normal bristles to hairlessindividuals would we find in the live progeny of across between two normal flies both carrying theH allele in the suppressed condition?b. When the hairless progeny of the previous cross arecrossed with one of the parental normal flies frompart (a) (meaning a fly that carries H in the suppressed condition), what phenotypic ratio wouldyou expect to find among their live progeny?arrow_forwardIn a certain plant, the genes for flower color and pollen shape are linked. In fe color, Purple (P) is dominant to red (p), and long pollen (L) is dominant to round (1). A researcher crossed true-breeding purple, long pollen plants with true-breeding red, round pollen plants. The Fl generation was then testcrossed with a double homozygous recessive individual. The resultant offspring were as follows. PpLI 44 ppLI 6 Ppll 8 ppll 42 a. What are the phenotypes of the recombinant-type offspring? b. How far apart are these genes in centiMorgans (cM)? c. What are the genotypes of the parental-type GAMETES?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Human Biology (MindTap Course List)
Biology
ISBN:9781305112100
Author:Cecie Starr, Beverly McMillan
Publisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
How to solve genetics probability problems; Author: Shomu's Biology;https://www.youtube.com/watch?v=R0yjfb1ooUs;License: Standard YouTube License, CC-BY
Beyond Mendelian Genetics: Complex Patterns of Inheritance; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-EmvmBuK-B8;License: Standard YouTube License, CC-BY