Domestic dogs evolved from ancestral grey wolves. Wolves have coats of short, straight hair and lack “fur-nishings,” a growth pattern marked by eyebrows and a mustache found in some domestic dogs. In domestic dogs, coat variation is controlled by allelic variation in three genes. Recessive mutant alleles in the FGF5 gene result in long hair, while dogs carrying the dominant ancestral allele have short hair. Likewise, recessive mutant alleles in the KRT71 gene result in curly hair, whereas dogs with an ancestral dominant allele have straight hair. Dominant mutant alleles in the RSPO2 gene cause the presence of furnishings, while dogs homozygous for the ancestral recessive allele have no furnishings.
A pure-breeding curly-and long-haired poodle with furnishings was crossed to a pure-breeding short-and straight-haired border collie lacking furnishings.
a. What are the genotypes and
b. If dogs of the
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Genetic Analysis: An Integrated Approach (3rd Edition)
- Spoink is a Pokemon character with a spring tail. It must bounce continuously or it will die. Imagine that the spring in the tail is controlled by a single gene with two alleles T and t. Individuals with the genotype TT have very stiff tails that take a lot of energy to bounce, Tt have just the right amount of spring, and those with tt tails have very floppy tails that deform after long periods of bouncing, making it very difficult to continue bouncing. The genotype frequency in this population is: TT=25% Tt=70% tt=5% Part A: The frequency of the t allele in the population is ___%. The expected frequency of the Tt genotype in the population is ___%. Part B: Is the population of Spoink in Hardy-Weinberg Equilibrium? A. Yes B. No Rationale? Part C: What type of selection, if at all, might be operating on Spoink tails springy-ness? A. Stabilizing Selection B. Balancing Selection C. Directional Selection D. Disruptive Selection E. No selection is occurring; population is in…arrow_forwardSuppose a geneticist is using a three-point test cross to map three linked rabbit morphology and behavioral mutations called si, sf, and H. The gene si is associated with the silky fur phenotype, and sf is associated with the short-footed phenotype. Both si and sf are recessive mutations with respect to wild type. H is a dominant mutation that confers the hyper phenotype. The geneticist first crosses true-breeding hyper rabbits to true-breeding silky fur, short-footed rabbits. Next, the geneticist backcrosses the F₁ progeny to the silky fur, short-footed parents, and obtains the results reported in the table. Phenotype hyper silky fur, short-footed short-footed silky fur, hyper silky fur short-footed, hyper silky fur, short-footed, hyper wild type Place the genes in the correct order in the chromosome. LLIIN HEL H Number 815 807 175 169 4 5 27 29 Answer Bank si sfarrow_forwardChoose one plsarrow_forward
- Choose one plsarrow_forwardIn mice, gene A is epistatic to gene B. Dominant allele "A" allows for pigment to be transported to the fur; recessive allele "a" prevents the transport of pigment to the fur, resulting in an albino mouse. Dominant allele "B" gives agouti fur color; recessive allele "b" gives black fur color. What phenotype would you expect from a mouse with "aaBb" genotype? * A.black and white fur B.albino fur C. agouti fur D. black furarrow_forward"In cattle, the allele that causes horns to grow is recessive. Another recessive allele causes the cows to grow abnormally large and muscular. These muscular cows are often called Belgian blue cows. If a cow that is heterozygous for both the horn and Belgian blue trait genes passes on the allele for growing horns to an offspring, what are the odds that the parent cow also passes on the allele for becoming very muscular to that offspring?" I know the answer is 50% but how do I get to this answer?arrow_forward
- In Minx cats, the alleles TT yield a cat with a normal tail, the heterozygous alleles Tt yield a cat with a short tail or no tail at all, and the recessive alleles tt are lethal to the embryo. Using Punnett squares, determine the genotypes and phenotypes of all offspring from parent Minx cats that both have short-tails.arrow_forwardHairlessness in dogs is inherent in a single dominant allele. Inheriting two dominant alleles is lethal for an embryo. Penelope, a hairless dog mates with Arnold, a hairless dog. The probability that Penelope has hairless puppies isarrow_forwardWith explanationarrow_forward
- Based on the information shown in the chart above, what is the most likely inheritance pattern for the 'forked bristles' trait? why?arrow_forwardOn the basis of these results, is the burnsi phenotype most likely inherited as a dominant trait or as a recessive trait?arrow_forwardThe bison herd on Konza Prairie has begun to show a genetic defect. Some of the males have a condition known as "rabbit hock" in which the knee of the back leg is malformed slightly. This condition is controlled by a sex-linked gene and it is recessive. Now, suppose that the herd bull (the dominant one which does most of the breeding) who is normal (XN) mates with a cow that is a carrier for rabbit hock. What are his chances of producing a normal son (bull)? If he mates with this cow every year, what percentage of their daughters will have normal knees? What percentage of their daughters will be carriers of rabbit hock?arrow_forward
- Human Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage Learning