Chemistry: An Atoms-Focused Approach (Second Edition)
2nd Edition
ISBN: 9780393614053
Author: Thomas R. Gilbert, Rein V. Kirss, Stacey Lowery Bretz, Natalie Foster
Publisher: W. W. Norton & Company
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Question
Chapter 2, Problem 2.94QA
Interpretation Introduction
To Find:
The dimensions of the cube based on the densities and mass.
Expert Solution & Answer
Answer to Problem 2.94QA
Solution:
The Aluminum cube will be smaller.
Dimension of the aluminum cube =
Dimension of strontium cube =
Explanation of Solution
Formula and concept:
If we take one mole of any element, we can get its mass from its molar mass. Relation between mass and density gives the volume of the solid. From the volume of the solid, we can create a cube accordingly.
A mole is the SI unit of amount chemical substance. When writing units, it is written as “mol”.
Given information:
Density of aluminum =
Density of strontium =
Quantity of each solid taken =
Atomic mass of Strontium =
Calculation:
For Aluminum
We will calculate the mass of aluminum from the 1 mol element by using atomic weight of Al.
Now we will volume of cube of Al from the
To calculate the edge length of unit cell, we will use volume of cube.
The edge length of aluminum cube is
For Strontium
We will calculate the mass of strontium from the 1 mol element by using atomic weight of Sr.
Now we will volume of cube of Sr from the
To calculate the edge length of unit cell, we will use volume of cube.
The edge length of strontium cube is
So, from the above calculation, we can see that the cube of aluminum shall be smaller.
Conclusion:
The dimensions of cube are calculated from the mass of the cube and density.
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Chapter 2 Solutions
Chemistry: An Atoms-Focused Approach (Second Edition)
Ch. 2 - Prob. 2.1VPCh. 2 - Prob. 2.2VPCh. 2 - Prob. 2.3VPCh. 2 - Prob. 2.4VPCh. 2 - Prob. 2.5VPCh. 2 - Prob. 2.6VPCh. 2 - Prob. 2.7VPCh. 2 - Prob. 2.8VPCh. 2 - Prob. 2.9VPCh. 2 - Prob. 2.10VP
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