Chemistry: An Atoms-Focused Approach (Second Edition)
2nd Edition
ISBN: 9780393614053
Author: Thomas R. Gilbert, Rein V. Kirss, Stacey Lowery Bretz, Natalie Foster
Publisher: W. W. Norton & Company
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Chapter 2, Problem 2.116QA
Interpretation Introduction
To find: Number of significant figures that should be used to express the value for the
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In the normal hydrogen electrode, the current flows through the electrode when the power difference
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In the normal hydrogen electrode, the balance potential difference in the interface is 0 and the current flow across the electrode when the interface potential difference is +5 mV. Explain briefly. Is the overvoltage 5 mV?
In the normal hydrogen electrode, the balance potential difference in the interface is 0 mV, the maximum potential is 5 mV. Explain briefly.
Chapter 2 Solutions
Chemistry: An Atoms-Focused Approach (Second Edition)
Ch. 2 - Prob. 2.1VPCh. 2 - Prob. 2.2VPCh. 2 - Prob. 2.3VPCh. 2 - Prob. 2.4VPCh. 2 - Prob. 2.5VPCh. 2 - Prob. 2.6VPCh. 2 - Prob. 2.7VPCh. 2 - Prob. 2.8VPCh. 2 - Prob. 2.9VPCh. 2 - Prob. 2.10VP
Ch. 2 - Prob. 2.11VPCh. 2 - Prob. 2.12VPCh. 2 - Prob. 2.13QACh. 2 - Prob. 2.14QACh. 2 - Prob. 2.15QACh. 2 - Prob. 2.16QACh. 2 - Prob. 2.17QACh. 2 - Prob. 2.18QACh. 2 - Prob. 2.19QACh. 2 - Prob. 2.20QACh. 2 - Prob. 2.21QACh. 2 - Prob. 2.22QACh. 2 - Prob. 2.23QACh. 2 - Prob. 2.24QACh. 2 - Prob. 2.25QACh. 2 - Prob. 2.26QACh. 2 - Prob. 2.27QACh. 2 - Prob. 2.28QACh. 2 - Prob. 2.29QACh. 2 - Prob. 2.30QACh. 2 - Prob. 2.31QACh. 2 - Prob. 2.32QACh. 2 - Prob. 2.33QACh. 2 - Prob. 2.34QACh. 2 - Prob. 2.35QACh. 2 - Prob. 2.36QACh. 2 - Prob. 2.37QACh. 2 - Prob. 2.38QACh. 2 - Prob. 2.39QACh. 2 - Prob. 2.40QACh. 2 - Prob. 2.41QACh. 2 - Prob. 2.42QACh. 2 - Prob. 2.43QACh. 2 - Prob. 2.44QACh. 2 - Prob. 2.45QACh. 2 - Prob. 2.46QACh. 2 - Prob. 2.47QACh. 2 - Prob. 2.48QACh. 2 - Prob. 2.49QACh. 2 - Prob. 2.50QACh. 2 - Prob. 2.51QACh. 2 - Prob. 2.52QACh. 2 - Prob. 2.53QACh. 2 - Prob. 2.54QACh. 2 - Prob. 2.55QACh. 2 - Prob. 2.56QACh. 2 - Prob. 2.57QACh. 2 - Prob. 2.58QACh. 2 - Prob. 2.59QACh. 2 - Prob. 2.60QACh. 2 - Prob. 2.61QACh. 2 - Prob. 2.62QACh. 2 - Prob. 2.63QACh. 2 - Prob. 2.64QACh. 2 - Prob. 2.65QACh. 2 - Prob. 2.66QACh. 2 - Prob. 2.67QACh. 2 - Prob. 2.68QACh. 2 - Prob. 2.69QACh. 2 - Prob. 2.70QACh. 2 - Prob. 2.71QACh. 2 - Prob. 2.72QACh. 2 - Prob. 2.73QACh. 2 - Prob. 2.74QACh. 2 - Prob. 2.75QACh. 2 - Prob. 2.76QACh. 2 - Prob. 2.77QACh. 2 - Prob. 2.78QACh. 2 - Prob. 2.79QACh. 2 - Prob. 2.80QACh. 2 - Prob. 2.81QACh. 2 - Prob. 2.82QACh. 2 - Prob. 2.83QACh. 2 - Prob. 2.84QACh. 2 - Prob. 2.85QACh. 2 - Prob. 2.86QACh. 2 - Prob. 2.87QACh. 2 - Prob. 2.88QACh. 2 - Prob. 2.89QACh. 2 - Prob. 2.90QACh. 2 - Prob. 2.91QACh. 2 - Prob. 2.92QACh. 2 - Prob. 2.93QACh. 2 - Prob. 2.94QACh. 2 - Prob. 2.95QACh. 2 - Prob. 2.96QACh. 2 - Prob. 2.97QACh. 2 - Prob. 2.98QACh. 2 - Prob. 2.99QACh. 2 - Prob. 2.100QACh. 2 - Prob. 2.101QACh. 2 - Prob. 2.102QACh. 2 - Prob. 2.103QACh. 2 - Prob. 2.104QACh. 2 - Prob. 2.105QACh. 2 - Prob. 2.106QACh. 2 - Prob. 2.107QACh. 2 - Prob. 2.108QACh. 2 - Prob. 2.109QACh. 2 - Prob. 2.110QACh. 2 - Prob. 2.111QACh. 2 - Prob. 2.112QACh. 2 - Prob. 2.113QACh. 2 - Prob. 2.114QACh. 2 - Prob. 2.115QACh. 2 - Prob. 2.116QA
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- utron eutro cle TH tro (Na (b) Atoms are said to be electrically neutral. Explain. (c) Distinguish between the following: (i) Atomic number and mass number. (ii) Mass number and relative atomic mass. 2. An isotope Q, has 18 neutrons a mass number of 34. (a) (i) Draw the atomic structure of Q. (ii) Write its electron arrangement (b) To which period and group does Q belong? Explain your answer. (c) How does Q form its ion? Explain. 3. (a) Determine the relative atomic mass of the following elements = compositions occur in the proportions given. (i) Neon 20 21 22. Ne (90.92%), 10Ne (0.26%), and 10Ne (8.82%) (ii) Argon 36 38 40 18 Ar (0.34%), 18 Ar (0.06%) and 18 Ar (99.6%)arrow_forwardIn the normal hydrogen electrode, the balance potential difference in the interface is this, the maximum potential is 5 mV. Explain briefly.arrow_forwardThe electrode balance potential is -0.118 V and the interface potential difference is +5 mV. The overvoltage n will be 0.005 - (-0.118) = 0.123 V. Is it correct?arrow_forward
- In the electrode Pt, H2(1 atm) | H+(a=1), if the electrode balance potential is -0.118 V and the interface potential difference is +5 mV. The current voltage will be 0.005 - (-0.118) = 0.123 V ¿Correcto?arrow_forwardIn the electrode Pt, H2(1 atm) | H+(a=1) at 298K is 0.79 mA cm-2. If the balance potential of the electrode is -0.118 V and the potential difference of the interface is +5 mV. Determine its potential.arrow_forwardIn one electrode: Pt, H2(1 atm) | H+(a=1), the interchange current density at 298K is 0.79 mA·cm-2. If the voltage difference of the interface is +5 mV. What will be the correct intensity at pH = 2?. Maximum transfer voltage and beta = 0.5.arrow_forward
- In a Pt electrode, H2(1 atm) | H+(a=1), the interchange current density of an electrode is 0.79 mA cm-2. ¿Qué corriente flow across the electrode of área 5 cm2 when the difference in potential of the interface is +5 mV?.arrow_forwardIf the current voltage is n = 0.14 V, indicate which of the 2 voltage formulas of the ley of Tafel must be applied i a a) == exp (1-B). xp[(1 - ß³): Fn Fn a b) == exp B RT RTarrow_forwardIf the current voltage is n = 0.14 V. Indicate which of the 2 formulas must be applied a) = a T = i exp[(1 - p) F Fn Fn b) i==exp B RTarrow_forward
- Topic: Photochemistry and Photophysics of Supramoleculesarrow_forwardTwo cations that exchange an electron in an interface, the exchange density is worth 1.39 mA/cm2 and the current density is worth 15 mA/cm2 at 25°C. If the overvoltage is 0.14 V, calculate the reaction rate and symmetry factor. Data: R = 8,314 J mol-1 k-1: F = 96500 Carrow_forwardWith the help of the Tafel line, it is estimated that the interchange density of the VO2+/VO2+ system on the carbon paper has a value of 3 mA cm-2. Calculate a) the current density if the voltage has a value of 1.6 mV and the temperature is 25°C. b) the beta value of the anódico process if the Tafel pendulum is 0.6 V at 25°C. Data: R = 8.314 JK-1mol-1, y F = 96485 C mol-1.arrow_forward
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